Tiêu đề Vector Varsity Practice Sheet_With Solve-25.pdf ✅

4 .........................................................................................................................................  Physics 1st Paper Chapter-2 weMZ mv‡j JU-G Avmv cÖkœvejx 1. `ywU e‡ji jw×i m‡e©v”P I me©wb¤œ gvb h_vμ‡g 7 N I 1 N| †Kvb GKwU we›`y‡Z ej `yBwU 90 †Kv‡Y wμqv Ki‡j jwäi gvb KZ? [JU 24-25] 8 N 6 N 5 N 4 N DËi: 5 N e ̈vL ̈v: P + Q = 7 (+)P – Q = 1 2P = 8  P = 4 N  Q = 3 N  R = 4 2 + 32 = 5 N 2. wb‡Pi †KvbwU †f±i ivwk? [JU 19-20] AvqZb Pvc †ÿÎdj KvR DËi: †ÿÎdj e ̈vL ̈v: †h mKj ivwk cÖKvk Ki‡Z gvb I w`K Df‡qi cÖ‡qvRb nq Zv‡K †f±i ivwk e‡j| 3. †KvbwU †f±i ivwk? [JU 22-23] AvqZb ˆe`y ̈wZK wefe ̄^Y©cvZ aviKhš¿ ˆe`y ̈wZK cÖvej ̈ DËi: ˆe`y ̈wZK cÖvej ̈ 4. wb‡Pi †KvbwU eÈb m~Î? [JU 21-22] (P )  + Q  + R  = P  + (Q )  + R  m (P )  + Q  = mP  + mQ  P  + Q  = Q  + P  A  .B  = B  .A  DËi: m (P )  + Q  = mP  + mQ  e ̈vL ̈v: wewbgq m~Î: P  + Q  = Q  + P  ms‡hvRb m~Î: (P )  + Q  + R  = P  + (Q )  + R  5. GKwU e ̄‘‡K 50 N ej Øviv cwðg w`‡K Ges 20 N ej Øviv DËi w`‡K Uvbv n‡”Q| jwä e‡ji gvb KZ n‡e? [JU 18-19] 53.85 N 63.85 N 43.85 N 50.85 N DËi: 53.85 N e ̈vL ̈v: 20 N 50 N R  c. c~. `. D. R = 502 + 202 = 53.85 N 6. DËi I c~e© w`‡Ki g‡a ̈ evqy cÖevwnZ n‡”Q| evqyi †e‡Mi DËi I c~e© w`‡Ki Ask h_vμ‡g 5 kmh–1 Ges 12 kmh–1 n‡j jwä †eM KZ n‡e? [JU 19-20] 60 kmh–1 7 kmh–1 17 kmh–1 13 kmh–1 DËi: 13 kmh–1 e ̈vL ̈v: R = 5 2 + 122 = 13 kmh–1 R 5 kmh–1 12 kmh–1 D. c~. 7. 10 N gv‡bi GKwU ej X Aÿ eivei wμqv Ki‡j Y Aÿ eivei Gi Dcvsk n‡eÑ [JU 19-20] 10 N 5 N 8.66 N 0 N DËi: 0 N e ̈vL ̈v: Y-Aÿ eivei Dcvsk = 10 cos90 = 10  0 = 0 N Y 10 N 8. † ̄avZ bv _vK‡j GKRb muvZviæ NÈvq 8 wK.wg. †e‡M muvZvi Kv‡U| NÈvq 4 wK.wg. †e‡M cÖevwnZ b`xi wVK Ic‡ii we›`y‡Z †cuŠQv‡Z muvZviæ‡K †Kvb w`‡K iIbv w`‡Z n‡e? [JU 12-13] 90 120 150 60 DËi: 120 9. 3i  – 4j  – 12k  †f±iwUi gvb KZ? [JU 18-19] 8 11 13 18 DËi: 13 e ̈vL ̈v: gvb = 3 2 + (–4) 2 + (–12) 2 = 13 10. ej cÖ‡qv‡M m‡e©v”P KvR n‡e hLb ej mi‡Yi mv‡_ wμqv K‡iÑ [JU 18-19] 45 †Kv‡Y 30 †Kv‡Y j¤^ eivei GKB w`‡K DËi: GKB w`‡K e ̈vL ̈v: W = Fs cos Wmax n‡j cos = 1,  = 0, A_©vr GKB w`‡K 11. A   B  = B   A  n‡j G‡`i ga ̈eZ©x †KvY KZ? [JU 21-22]   3  4  2 DËi: 