Tiêu đề 31.12.23_SR.STAR CO-SC(MODEL-A,B_C)_Jee_Main_GTM-4_KEY _ SOL.pdf ✅

Sec: SR.IIT_*CO-SC(MODEL-A,B&C) GTM-4 Date: 31-12-23 Time: 3 HRS JEE-MAIN Max. Marks: 300 KEY SHEET PHYSICS 1 D 2 B 3 B 4 C 5 B 6 B 7 B 8 A 9 B 10 B 11 D 12 A 13 C 14 B 15 D 16 D 17 A 18 A 19 A 20 A 21 4 22 6 23 25 24 141 25 32 26 3 27 2 28 352 29 400 30 125 CHEMISTRY 31 C 32 D 33 A 34 A 35 B 36 B 37 B 38 C 39 B 40 A 41 C 42 B 43 A 44 D 45 C 46 D 47 C 48 D 49 B 50 D 51 5 52 5 53 5 54 44 55 3 56 10 57 6 58 5 59 25 60 3 MATHEMATICS 61 D 62 A 63 C 64 A 65 D 66 B 67 D 68 C 69 A 70 A 71 A 72 A 73 B 74 A 75 D 76 C 77 C 78 D 79 B 80 B 81 3 82 3 83 4 84 5 85 6 86 2 87 3 88 3 89 26 90 68
Narayana IIT Academy 31-12-23_SR.IIT_*CO-SC(MODEL-A,B&C)_JEE-MAIN_GTM-4_KEY&SOL SR.IIT_*CO-SC Page NO: 2 SOLUTIONS PHYSICS 1. 4 10 1 100 10 900 G G V V I R R R           2. 2 4 0 . 4 R m r dr KR       4 3 0 2 2 GM G KR KR G V r R       3. 2 / 2 a m s   Velocity after t  2 v m s   / Then 2 2 1 N V a R    2 2 / N a m s   So net according   2 2 2 2 aT           2 4 4 aT    2 1 4 2 T a     So N = 4 4. 1 ' , 2 ' rms rms rms T T M V V M V T M     5.  2 1 1 2 1 1 1 1 f R R                   1 1.25 1.5 1 1 1 100 20 40               1 1.5 1 1  6    1 1.5 7  6   1 1.5 6 9 7 7     . 6. 2 A r n     2 2 A r n n   0 2 4 A r n n   0 So 1 4 An n n n A    7. No.of divisions = 50 Pitch = 0.5 mm Least count 0.5 10 50 mm    m 8. 1 LC   0 1 8 2 4 LC L C     0 4    .
Narayana IIT Academy 31-12-23_SR.IIT_*CO-SC(MODEL-A,B&C)_JEE-MAIN_GTM-4_KEY&SOL SR.IIT_*CO-SC Page NO: 3 9. 6 6 2 4 4 V V V        3 4 8 8 V V V       10. For stable equilibrium, m  is parallel to B  (i.e., 0   0 ) and for unstable equilibrium, m  is antiparallel to B  (i.e, 0  180 ). PE in the unstable equilibrium, 0 2 U m B m B m B      . cos0       (0.40 / ) 0.16 0.064 J T T J   Amount of work done to displace the solenoid from its stable to unstable orientation, i.e., U U J J J 2       f 0.064 0.064 0.128   11. 2 2 2 2 2 2 1 1/ 1 1/ K A x n n U x n       12. V V V rel F B    4 9 3 3    VB 4.5 /   V m s B 13. A) 2 2 3 KQ V 3R r 2R       At 2 2 3 R KQ R 11KQ 11V r , V 3R 2 2R 4 8R 8            B) KQ V V 2R 2   C) 3 2 KQ R KQ V E R 2 2R 2    D) 2 KQ V E 4R 4   14. Here the diode is in forward bias. So we replace it by a connecting wire, 30 0 0 0 10 10 10    V V V A A A    3 3 10 VA  V V A 10 15. In photoelectric experiment, speed of fastest emitted electron is given by 2 max 1 2 hc mv w    Case-I : 1 2 2 hc mv w    ......... (i) Case-II : 1 2 ' 2 3 / 4 hc mv w   
Narayana IIT Academy 31-12-23_SR.IIT_*CO-SC(MODEL-A,B&C)_JEE-MAIN_GTM-4_KEY&SOL SR.IIT_*CO-SC Page NO: 4 1 4 2 ' 2 3 hc mv w    ....... (ii) From eqn. (i) & (ii) 2 2 4 ' 3 3 w v v   Hence 4 ' 3 v v  16. If the insect is not sliding, mg f sin  mg mg sin cos      3 tan 4     The height h from the bottom h R R   cos 4 0.20 5 5 R h R R m           . 17. 3 1 8.314 100 1247.1 2           U nC T J v 18. Conceptual 19. In x direction : Applying conservation of momentum mu mv  2 cos30 0 2cos30 3 u u v   Also 0 2 cos30 3 3 v u e u u    2 3  e 20. 10 d d s u   u s u s m s     10 1 / 21.   4 4 0 0 0 2 1 cos 60 2 2 4 512 I I I I           22. Loss 1 2 2 1 2 1 2 C C V C C         1 12 2 30 10 (20) 2      9 6 10 J   