Tiêu đề Ideal Gas & Environment Chemistry- Daily-13 (Set-A)-With Solve.pdf ✅

4 e ̈vL ̈v: crms = 3RT M crms  T  crms c rms = T T  2 = T T  T = 4T  T = 4  273 K  T = 1092 K 27. 10 wjUvi AvqZ‡bi e× cv‡Î 300 K ZvcgvÎvq 16 g Aw•‡Rb †h Pvc cÖ`k©b K‡i, GKB cv‡Î GKB ZvcgvÎvq KZ MÖvg bvB‡Uav‡Rb ivL‡j GKB Pvc cÖ`k©b Ki‡e? 14 16 18 32 DËi: 14 e ̈vL ̈v: kZ©g‡Z, VO2 = VN2 = 10 L TO2 = TN2 = 300 K; nO2 = 16 32 = 1 2 PO2 = PN2 GLv‡b, PV = nRT  nO2  TO2 = nN2  TN2  nN2 = nO2  nN2 = 1 2  mN2 = 28 2 = 14 28. ZvwË¡Kfv‡e M ̈v‡mi AvqZb k~b ̈ nq †Kvb ZvcgvÎvq? 298 K 0C – 273 K – 273 C DËi: – 273 C e ̈vL ̈v: Pvj©‡mi m~Îvbymv‡i, V  T [†hLv‡b Pvc I fi w ̄’i] V = kT hv g~jwe›`yMvgx mij‡iLv d‡j 0 K ev, – 273C ZvcgvÎvq M ̈v‡mi AvqZb ZvwË¡Kfv‡e k~b ̈| Y O X ZvcgvÎv, T(K) AvqZb V(m 3)  29. †KD hw` cvnv‡oi P‚ovq cvwb dzUv‡Z Pvq, Z‡e Zv‡K KZ ZvcgvÎvq †duvUv‡Z n‡e? 100C Gi †ewk 100C Gi Kg 100C †Kv‡bvwUB bq DËi: 100C Gi Kg e ̈vL ̈v: †h‡nZz cvnv‡oi P‚ovq Pvc Kg ZvB Kg ZvcgvÎvq cvwb dzU‡Z _vK‡e| cvwbi ùzUbv1⁄4 100C wKš‘ cvnv‡oi P‚ovq cvwb 100C A‡cÿv Kg ZvcgvÎvq dzU‡Z _vK‡e| 30. GKwU f ̈vKzg †P¤^v‡i evqyi Pvc 10–13 atm| hw` †P¤^v‡ii ZvcgvÎv 300 K nq, Z‡e 1 cm3 AvqZ‡b Dcw ̄’Z AYyi msL ̈vÑ 2.4  106 24 24  109 †Kv‡bvwUB bq DËi: 2.4  106 e ̈vL ̈v: PV = nRT  N = PVNA RT  10–13  10–3  6  1023 0.08  300  N  107  6 3  8  1 4  107  2.5  106 wU imvqb (Chemistry) 31. GKwU M ̈vmc~Y© wmwjÛv‡ii AvqZb 352 cm3 wmwjÛviwU‡K 1520 mm(Hg) †_‡K 1 atm Pv‡c †bIqv n‡j, bZzb KZwU wmwjÛvi D3 M ̈vm Øviv c~Y© Kiv hv‡e? [bZzb wmwjÛv‡ii AvqZb 176 cm3 ] 20 10 30 4 DËi: 4 e ̈vL ̈v: P1V1 = P2V2  V2  P1V1 P2  V2 = 704 cm3 GLv‡b, P1 = 1520 mm(Hg) = 2 atm P2 = 1 atm V1 = 352 cm3 kZ©g‡Z, V = n  v  704 = n  176  n = 4 wU (Ans.) 32. GKwU 2 L AvqZ‡bi cv‡Î 1atm Pv‡c N2 M ̈vm i‡q‡Q (25C ZvcgvÎvq)| cv‡Îi Pvc 1900 mm(Hg) n‡e KZ C ZvcgvÎvq? 745C 100C 323C 472C DËi: 472C e ̈vL ̈v: P1 T1 = P2 T2  T2 = P2 P1  T1  T2 = 2.5 atm 1 atm  298  T2 = 745 K = 472C GLv‡b, P1 = 1atm P2 = 1900 mm(Hg) =2.5atm T2 = 298 K 33. SO3 wK‡mi b ̈vq AvPiY K‡i? jyBm A¤ø jyBm ÿviK †cÖvUbxq GwmW †Kv‡bvwUB bq DËi: jyBm A¤ø e ̈vL ̈v: SO3  O = S O O ; †K›`axq cigvYy S GK‡Rvov B‡jKUab MÖn‡Y mÿg| H2O: + SO3  H2SO4 .. 34. PH3 GKwUÑ cvwj‡cÖvwUK ÿviK g‡bv‡cÖvwUK ÿviK WvB‡cÖvwUK ÿviK UavB‡cÖvwUK ÿviK DËi: g‡bv‡cÖvwUK ÿviK e ̈vL ̈v: PH3- G GK‡Rvov gy3‡Rvo B‡jKUab i‡q‡Q hv Av‡iv 1wU †cÖvUb MÖn‡Y mÿg|