Nội dung text 10. P2C10. সেমিকন্ডাক্টর ও ইলেক্ট্রনিক্স Merge OK_Sha 28.4.24_Mahee -Ok.pdf
†mwgKÛv±i I B‡jKUawb· Practice Content 1 `kg Aa ̈vq †mwgKÛv±i I B‡jKUawb· Semiconductor and Electronics weMZ eQ‡i BwÄwbqvwis fvwm©wU‡Z Avmv wjwLZ cÖkœmg~n 1| A B A B jwRK †MUwU n‡Z mZ ̈K mviwY •Zwi Ki| [BUET 21-22] mgvavb: – A – B . AB – = – AB + A – B = A B A B – AB A – B A B = – AB + A – B 0 0 0 0 0 0 1 1 0 1 1 0 0 1 1 1 1 0 0 0 2| IB, IE, VBC, VBE, VCE wbY©q Ki| [ = 49, IC = 5 mA] [BUET 21-22] Ic IB 2.2 k 2 k Vcc = 13 V mgvavb: = IC IB 49 = 5 IB IB = 0.102 mA (Ans) IE = IB + IC = 5.102 mA (Ans) VBE = – 2 103 0.102 10–3 = – 0.204 V (Ans) VCE = Vcc – 2.2 103 5 10–3 = 2V (Ans) VBC = VBE – VCE = – 2.204 V (Ans.) 3| bx‡Pi eZ©bxi Kv‡jKUi wefe VC wbY©q Ki hLb UavbwR÷iwU active mode G wμqvkxj Av‡Q (A_©vr, †eBR-GwgUvi Rvskb m¤§yLx †SuvK Ges Kv‡jKUi-†eBR Rvskb wegyLx †SuvK) †`Iqv Av‡Q, VBE = 0.7 V Ges = 100. [BUET 19-20] 10V RC=4.7 k 4V B E C RE=3.3 k mgvavb: 10V 4.7 k 4V B E C 3.3 k IB IC 10V 0V IE cÖ_g jy‡c, 4 = VBE + 3.3 × 103 × IE IE = 1 mA = IC IB = IC IE – IC 100 = IC 1 – IC IC = 0.99 mA GLb, 10 – VC = 4.7 × 103 IC VC = 5.347 V (Ans.) 4| GKwU mvaviY wbtmviK weea©‡Ki cÖevn jvf 70 nq| hw` wbtmviK cÖevn 8.8 mA nq, Zvn‡j msMÖvnK Ges cxV cÖev‡ni gvb wbY©q Ki| UavbwR÷iwU hLb mvaviY cxV weea©K wnmv‡e KvR K‡i, ZLb cÖevn jvf KZ? [BUET 16-17] mgvavb: cÖ_g †ÿ‡Î, cÖevn jvf, = IC IB = IE – IB IB 70 = 8.8 – IB IB IB = 0.124 mA (Ans.) IC = IE – IB = 8.8 – 0.124 = 8.676 mA (Ans.) wØZxq †ÿ‡Î, cÖevn jvf, = IC IE = 8.676 8.8 = 0.986 (Ans.)