Tiêu đề DPP-3 SOLUTION.pdf ✅

CLASS : XIth SUBJECT : CHEMISTRY DATE : DPP No. : 3 1 (c) En = E1 n 2 × Z 2 = ―13.6 4 × 9 = ―30.6 eV (for the excited state, n = 2 and for Li 2+ ion, Z = 3) 2 (b) Given, azimuthal quantum number (l)=2 Number of orbital’s =(2l+1) = (2 × 2 + 1) = 4 + 1 = 5 3 (b) Heaviest atom has mass no. 238,(i.e., 92U 238) and lighter one is 1H 1 . 4 (d) λ = h mu . 5 (c) px orbital has two lobes on x-axis. 6 (d) f-orbital has 7 orientations. 8 (b) III shell is more closer to nucleus. 9 (b) Ar and Ca 2+ are isoelectronic species as they have same number of electrons, i.e., 18. 10 (b) p = mu = h λ and E = hc λ ∴ E = c λ ∙ p ∙ λ = c ∙ p 11 (a) ∆x.∆v ≥ h 4πm Topic :- STRUCTURE OF ATOM Solutions
∆x ≥ 6.62 × 10―34 4 × 3.14 × 25 × 10―3 × 10―5 = 2.10 × 10―28m 12 (d) Mass of neutron = 1.675 × 10―27 kg . 13 (c) λ = h mu = 6.62 × 10―34 66 × 103 × 1 15 (c) n = 4(4th shell) l = 2(d-subshell) m1 = ―2(dxy orbital) s = + 1 2 (↑) Hence, electron belongs to 4d-orbital. 16 (d) The four lobes of dx 2―y 2 orbital are lying along x and y axes, while the two lobes of dz 2 orbital are lying along z-axis, and contain a ring of negative charge surrounding the nucleus in xy plane 2s orbitals has one spherical node, where electron density is zero p-orbital have direction character Orbital ⟶pz px py m⟶0 ± 1 ± 1 Nodal plane ⟶xy yz zx 17 (c) dxy orbital lies at 45° angle in between x-and y-axes. 18 (d) According to Pauli exclusion principle. 19 (b) E = hc λ . 20 (d) Cu has configuration [Ar]3d 10,4s 1 ; the two electrons are lost, one from 4s 1 and one from 3 d 10 .
ANSWER-KEY Q. 1 2 3 4 5 6 7 8 9 10 A. C B B D C D D B B B Q. 11 12 13 14 15 16 17 18 19 20 A. A D C B C D C D B D