Tiêu đề Unit No. 4 Part-A (SHM) (Google Drive Link).pdf ✅

www.youtube.com/physicswithshahid SIMPLE HARMONIC MOTION (UNIT-4 PART-A) MDCAT 1 A particle executing a vibratory motion while passing through the mean position has A) Maximum P.E. and minimum K.E. C) Maximum K.E. and minimum P.E. B) P.E. and K.E. both maximum D) P.E. and K.E. both minimum 2 The frequency of wave is 0.002 Hz. Its time period is A) 100 s B) 5000 s C) 500 s D) 50 s 3 The unit of force constant is A) Nm B) N/kg C) N/m D) Nkg 4 The amplitude, frequency and period of an object vibrating at the end of spring, if the equation for its position, as a function of time, is X = 0. 25 Sin ( π 3 ) t A) 0.25m, 0.2 Hz, 4s C) 0.25m, 0.25 Hz, 4s B) 0.25m, 1/8 Hz, 8s D) 0.25m, 1/6 Hz, 6s 5 Distance and displacement traveled by a vibrating body in a time equal to 3/4 T ; where T is the period of the vibration A) 3x ,3xoo B) 3x ,xo C) 3x ,o 0 D) 2x ,o 0 6 The product of frequency and time period is A) 4 B) 1 C) 2 D) 6 7 The variation of the acceleration a of the particle executing S.H.M. with displacement x is as shown in the figure A) B) C) D) 8 Distance covered during one vibration of an oscillating body in terms of amplitude ‘A’ is A) A/2 B) 2A C) A D) 4A 9 A particle moves in a circular path with a uniform speed. Its motion is: A) Periodic C) Simple harmonic motion B) Oscillatory D) Angular SHM 10 If the frequency of simple pendulum is 0.25 Hz then its time period is A) 1 sec B) 3 sec C) 2 sec D) 4 sec 11 The graph represents A) Motion of a simple pendulum starting from mean position B) Motion of a simple pendulum starting from extreme position C) Simple pendulum describing a horizontal circle D) None of the above 12 The restoring force becomes maximum, when the particle reaches at: A) Mean position B) Extreme position C) All position D) None of them 13 A body moves with S.H.M. and makes a complete oscillation in two second, its angular frequency is A) 2 rad s-1 B) 1 rad s-1 C) 3.14 rad s-1 D) 0.98 rad s-1 14 If the position of oscillating object is given by the equation X = √2Cos ( π 8 t)then its displacement after 2 second is: A) 3 m B) 2 m C) 1 m D) 0 m 15 The motion of the projection of a particle moving in a circle with constant speed along the diameter of the circle is