Tiêu đề CĐ14. NHIỆT PHÂN MUỐI (2023-2024) - ĐỀ.pdf ✅

CHUYÊN ĐỀ 14: NHIỆT PHÂN MUỐI (2024) Biên soạn: Thầy Tony Long – Trung tâm luyện thi SunClass Trang 1 KHOÁ LIVE S – 2K6 Mục tiêu: 9+ LUYỆN THI THPT QUỐC GIA – NĂM HỌC: 2023 - 2024 CHUYÊN ĐỀ 14: NHIỆT PHÂN MUỐI (9+) Mức độ câu hỏi: Vận dụng – Vận dụng cao Thời gian yêu cầu: 4 phút / 1 câu Họ, tên thí sinh: ......................................................... Số báo danh: .............................................................. Dạng 1: Nhiệt phân tinh thể muối nitrat Câu 1. Nhiệt phân hoàn toàn 41,58 gam X (là muối ở dạng ngậm nước), thu được hỗn hợp Y (gồm khí và hơi) và 11,34 gam chất rắn Z. Hấp thụ toàn bộ Y vào nước thu được dung dịch T. Cho T tác dụng với 280 ml dung dịch NaOH 1M, thu được dung dịch chỉ chứa một muối duy nhất, khối lượng muối là 23,8 gam. Phần trăm khối lượng nguyên tố oxi trong X là A. 48,48%. B. 53,87%. C. 59,26%. D. 64,65%. (Đề chính thức BGD năm 2020 – Lần 1) Giải: ................................................................................................................................................................................................................................................................................................................................................................................................... ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ ............................................................................................................................................................................................................................................................................................................................................................................................................................ Câu 2. Nhiệt phân 25,6 gam tinh thể muối X đến khối lượng không đổi, thu được 4 gam chất rắn Y và hỗn hợp khí Z gồm khí và hơi. Hấp thụ toàn bộ Z vào nước, thu được dung dịch T. Cho T tác dụng với 200 ml dung dịch KOH 1M, thu được dung dịch chỉ chứa 20,2 gam muối duy nhất. Phần trăm khối lượng kim loại trong X là A. 9,375%. B. 34,043%. C. 31,111%. D. 23,140%. 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