Tiêu đề 1. Basic Concepts of Chemistry (C.M.).pdf ✅

CHEMISTRY Q.1 Column-I Column-II (A) Concentration which are (P) ppm unitless (B) Concentration which (Q) Molarity remain same on varying temperature (C) Concentration which (R) Molality are dependent on the volume of solution (D) In dilute aqueous (S) % W w solution mg/ concentration is approximately equal to [A → P,S , B → P,R,S, C → Q, D → P] Q.2 Column-I Column-II (A) 2 mole electrons transfer (P) 2− C2O4 → CO2 (B) 3 mole of electrons transfer (Q) Fe3O4→ Fe2+ (C) 4 mole of electrons transfer (R) 2− CrO4 → Cr3+ (D) Reduction reactions (S) − MnO4 → − MnF4 [A → P,Q , B → R, C → S, D → Q,R,S] Q.3 Column I Column II (A) 2H O 2H2O 1g 2 1g 2+ → (P) 0.56 g of CaO (B) 3 1g 2 1g N2+ 3H → 2NH (Q) 1.333 g (C) 2 1g CaCO3 → CaO +CO (R) 1.125 g (D) 4 1g 1g 2H2+ C → CH (S) 1.214 g [A → R, B → S, C → P, D → Q] Sol. (A) → R ; Here oxygen is limiting reagent. 32 g of oxygen gives 36 g of H2O 1 g of oxygen gives 32 36 = 1.125 g (B) → (S) ; Here N2 is limiting reagent. 28 g of N2 gives 34 of NH3 1 g of N2 gives 28 34 = 14 17 = 1.214 g of NH3 (C) → (P) ;Here CaCO3 is limiting reagent. 100 g of CaCO3 gives 56 g of CaO 1 g of CaCO3 gives 100 56 = 0.56 g of CaO (D) → (Q) ; Here carbon is limiting reagent. 12 g of C gives 16 g of methane 1 g of C gives 12 16 = 1.33 g 16 Jun 2009 __________(Ex. Sheet)________________ Q.4 (A) Concentration units independent on temperature variation (i) Molality (B) Concentration units dependent on temperature variation (ii) Molarity (C) mg of solute present in 1 kg of solution represent (iii) ppm concentration (D) moles of solute present in 1 kg of solvent represent (iv) moles of solute in hundred moles of solution Column-A Column-B [(A)→ (i, iii, iv), (B) → (ii) , (C) → (iii) , (D) → (i)] Q.5 (A) On decomposition 50% increase in volume at the same temperature and pressure (i) NH3 (B) On decomposition 100% increase in volume at the same temperature and pressure (ii) HCl (C) On decomposition no change in volume at the same temperature and pressure (iii) O3 (D) Gases highly soluble in water (iv) COCl2 Column-A Column-B [(A) → (iii), (B) → (i, iv) , (C) → (ii) , (D) → (i, ii, iv)] 10 July 09 ___________________________________ Q.6
Column - I Column - II (A) Concentration which is dimensionless (P) ppm (B) Concentration which remain same on varying temperature (Q) Molality (C) In a dilute aqueous solution let mole fraction of solute is x, therefore (1 x) 18 x 103 −   represent (R) mol mol % (D) In dilute aqueous solutions mg/L concentration is approximately (S) wt. wt. % Sol. (A) → (P, R, S) (B) → (P, Q, R, S) Since all the given concentration is independent on the volume of solution. (C) → (Q) Mole fraction of H2O = (1 – x) Therefore molality = (1 x) 18 x 103 −   (D) → (P) ------------ 09 __________________________________ Q.` Column-I Column-II (A) 1.2 g of Mg (P) Hence 10x of solute is dissolved in 1 ml solution (B) Molarity of (Q) One ml of solution chlorine when chlorine weighs 10x g gets converted to chloride and chlorate is (C) Density of solution is (R) Reacts with 0.8 g of 10x g/ml oxygen to form 2.0 g of MgO (D) Strength of a (S) One sixth of normality solution is 1000x g in one litre [(A) → R; (B) → S; (C) → Q; (D) → P] Q. 8 Column-I Column-II (A) On decomposition 50% (P) NH3 increase in volume at the same temperature and pressure (B) On decomposition 100% (Q) HI increase in volume at same temperature and pressure (C) On decomposition no change (R) O3 in volume at the same temperature and pressure (D) Gases highly soluble in water (S) COCl2 (T) HCl [A → R ; B → P,S ; C → Q,T ; D → P, Q, S,T] Sol. 2NH3 ⎯→ N2 + 3H2 2HI ⎯→ H2 + I2 O3 ⎯→ O2 + 2 1 O2 COCl2 ⎯→ CO + Cl2 2HCl ⎯→ H2 + Cl2 Q. 9 Starting with 2 moles of A and 1 mole of B, the following reaction 2 A + 3B ⎯→ X + 2Y is made to take place. Assume the reaction to go to completion. Match the no. of moles listed in column II with various species listed in Column I. Column-I Column-II (A) A (P) 1/3 (B) B (Q) 2/3 (C) X (R) 0.0 (D) Y (S) 4/3 (T) 1/6 [A → S ; B → R ; C → P ; D → Q] Q.10 Column matching : Column I Column II A. CaC2 P. 106 gm B. 2 g-equivalent of Q. 22.4 L at S.T.P. Na2CO3 C. 6.02 × 1023 Ne R. Molarity of solution atoms D. Number of S. 0.01 moles of solute gm-molecules in one lit. of solution per litre of solution E. Centimolar solution T. N0 formula units Fe4 [Fe(CN)6 ] 3 F. Mohr’s salt U. Calcium carbide G. Contain 18 gm-atom V. (NH4 ) 2 SO4 .Fe(SO4 ).
of N 6H2O [A→U; B → P; C → Q; D → R; E→ S; F→V; G → T] Q.11 Match the Column. Column -I Column-II (A) 16 gm of CH4 (P) 0.5 mole (B) 1 gm of H2 (Q) 5 NA atoms (C) 22 gm of CO2 (R) 11.2 litre (D) 9 gm of H2O (S) 0.5 × NA atoms (T) 1.5 NA atoms Sol. A → Q; B → P,R ; C → P,R,T; D →P,R,T