PDF Google Drive Downloader v1.1


Báo lỗi sự cố

Nội dung text Work Sheet - 1 (Chemical Bonding).pdf

Single correct : Q.1 2 × sulphuric acid – H2O + O  X 2 × sulphurous acid – H2O = Y Which option is correctfor above information? (A) X has S–O–S bond (B) Y has S–O–S bond (C) Y has S–S bond (D) X has S–S bond Q.2 Select the correct order with respect to bond angle. (A) NH3 < NF3 < NCl3 (B) OH2 < OF2 < OCl2 (C) SH2 < SF2 < SCl2 (D) BH3 < BF3 < BCl3 Q.3 Which is correct Lewis structure with formal charge on particular atom? (A) S O : O : :  : (B) S O O : :  : O : : : (C) P Cl : : : Cl : : : Cl : : : :O: (D) Cl : :: :F: : : : : F F Q.4 Which of the following statement is correctregarding C2H2 F2molecule. (A) One isomer is polar, one is non polar (B) Two isomers are polar, one is non polar (C) Two isomers are planar, one is non planar (D) Two isomers are only possible and planar Q.5 Which of the following statement is correct. (A) O2 is paramagnetic, O3 is also paramagnetic (B) O2 is paramagnetic, O3 is diamagnetic (C) B2 is paramagnetic, C2 is also paramagnetic (D) Different observation is found in their bond length when NO NO+ and CO CO+ Q.6 Which of the following is the correct combination of atomic orbitals according to MOT. (A) + + + + – – ABMO(g) (B) + + + + + + – – – – – – BMO(ug) (C) + + + – + + – – – – – + ABMO(g) (D) – + – + – – ABMO(g) WORK SHEET - 01 CHEMICAL BONDING
Q.7 The bond length of the S–O bond is maximum in which of the following compound. SOBr2 , SOCl2 , SOF2 (A) SOCl2 (B) SOBr2 (C) SOF2 (D)All have same length Q.8 Which one of the following molecules has zero dipole moment (A) ICl (B)AsCl3 (C) Ni(CO)4 (D) PCl3 Q.9 Select the molecule which has See-Saw shape. (A) XeOF4 (B) [O2 IF2 ] ̄ (C) SOF4 (D) POCl3 Q.10 Among KO2 , KAlO2 , CaO2 and  NO2 , unpaired electron is present in: (A)  NO2 and CaO2 (B) KO2 and KAlO2 (C) KO2 only (D) CaO2 only Q.11 NH3 & N3H has hybridisation (A) sp3 , sp (B) sp, sp3 (C) sp2 , sp (D) sp, sp Q.12 Give the correct order of initialsTor Ffor following statements. UseTif statement is true and Fif it is false. (I) Br–P–Br bond angle in PCl3Br2 is 180°. (II)  NO2 , NO2 &  NO2 species have O–N–O bond angle order,  NO2 < NO2 <  NO2 . (III) Oxy acid is not produced, when NCl3 undergoes hydrolysis. (IV) Silicones are veryinert and water repellant. (A) TTTF (B) TFTT (C) FTFF (D) FTFT Q.13 The xenon compound(s) that are iso-structural with IBr2 – and BrO3 – respectively (A) linear XeF2 and pyramidal XeO3 (B) bent XeF2 and pyramidal XeO3 (C) bent XeF2 and planar XeO3 (D) linear XeF2 and tetrahedral XeO3 Q.14 How manymoleculesare linear in followingcompounds but does nothave anylone pairon central atom. CO2 , XeF2 , [I(CN)2 ] ̄, [ I2 (CN)]+ , I3 ̄, C2H2 , SnCl2 , OF2 , HgCl2 (A) 4 (B) 2 (C) 5 (D) 3 Q.15 Whichofthefollowinghasminimumboilingpoint? (A) OH NO2 (B) OH NO2 (C) CO2 (D) SiO2 Q.16 Which of the following species is tetrahedral and coloured due to charge transfer spectrum? (A) VO4 3– (B) CrO2Cl2 (C) [Sc(H2O)6 ] 3+ (D) both (A) and (B) Q.17 Choose the correct order of boiling point. (A) GeH4 > SiH4 < CH4 (B) Xe > Ne > He (C) He > H2 (D) CH4 > CD4
Q.18 The correct order of dipole moment of HF, HCl, HBr, HI and H2 is : (A) H2 < HF < HCl < HBr < HI (B) H2 < HF < HBr < HCl < HI (C) H2 < HI < HBr < HCl < HF (D) H2 < HI < HBr < HF < HCl Assertion Reason Q.19 Statement-1 : POF3 exist but NOF3 does not exist. Statement-2 : 'P' can form five bond by expanding its octet while 'N' can not expand its octet to form five bonds. (A) Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1. (B) Statement-1istrue,statement-2 istrueandstatement-2isNOTthecorrectexplanation forstatement-1. (C) Statement-1 is true, statement-2 is false. (D) Statement-1 is false, statement-2 is true. Q.20 Statement-1 : Red phosphorus is less volatile than white phosphorus. Statement-2 : Red phosphorus has a discrete tetrahedral structure. A) Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1. (B) Statement-1istrue,statement-2 istrueandstatement-2isNOTthecorrectexplanation forstatement-1. (C) Statement-1 is true, statement-2 is false. (D) Statement-1 is false, statement-2 is true. Q.21 Statement-1 : Bond angle of HOF is lesser than HOCl. Statement-2 : Oxygen atom is more electronegative than chlorine. (A) Statement-1 is true, statement-2 is true and statement-2 is correct explanation for statement-1. (B)Statement-1istrue,statement-2istrueandstatement-2isNOT thecorrectexplanationforstatement-1. (C) Statement-1 is true, statement-2 is false. (D) Statement-1 is false, statement-2 is true. Comprehension Paragraph for question nos. 22 & 23 Hydrogen bonding originates from the dipole-dipole interaction between H-atom and anyof the other atom like F, O, N and in somecases with Cl atom. There are two types of H-bonding like intermolecular and intramolecular H– bonding. Q.22 Which of the following plot for  (density) v/s T (temperature) for liquid H2O is correct: (A)  0°C T 4°C (B)  0°C T 4°C (C)  0°C T 4°C (D)  0°C T 4°C Q.23 Which of followingstatement isincorrect. (A) Boiling point of H2O2 is greater than that of H2O (B) Ethylene glycol is less viscous than glycerol. (C) o-nitrophenol can be separated from its meta and para isomer using its steam volatile property. (D) In ice each 'O' atom is tetrahedrally arranged byfour H-atoms which are all equidistant.
Paragraph for question nos. 24 to 26 The hybrid orbitals sp, sp2 , sp3 , sp3d 2 , etc are equivalent, but there are some cases in which the hybrid orbitalsare nonequivalent.Thisnonequivalenceis foundinsp3dhybridisation.Insp3d(trigonalbipyramid) hybridisation, there are three equivalent hybrid orbitals developed from (s + px + py ) lie in the equatorial plane (i.e. xy-plane) at 120°, and other two equivalent hybrid orbitals developed from (pz + 2 z d ) project mutually at 180° in the axial directions. Thus there are two sets of hybrid orbitals, i.e. a set of three equivalent equatorial hybrid orbitals and a set of two equivalent axial hybrid orbitals. This idea has beenestablishedfromtheexperimentalfindingsinPCl5 inwhichthethreeequatorialchlorinesaredifferent from the two axial chlorines. The equatorial P–Cl bond (204 pm) is shorter than the axial P–Cl bond (219 pm). If different atoms of different electronegativity are attached to the central atom, then Bent's rule will determine the positions of the different surrounding atoms in the trigonal bipyramidal geometry. Q.24 Which of the following statement is correct regarding the structure of H2CSF2Me2molecule. (A) Two C–H bonds are in the same plane of equatorial S–Me bonds. (B) Two C–H bonds are in the same plane of axial S–F bonds. (C) Nodal plane of -bond is perpendicular to the axial S–F plane. (D) -bond is formed by p –p overlapping. Q.25 In P4O10 molecule, bridging P–O bond length is (A) larger than that of in P4O6 (B) lesser than that of in P4O6 (C) Equal to that of in P4O6 (D) can not be compared Q.26 In which of the following pair of species, all bond angles are equal (A) CO3 2– , COCl2 (B) PO4 3– , POCl3 (C) BF4 ̄ , BH4 ̄ (D) CH3 F , CH4 Paragraph for question nos. 27 & 28 According to Fajan rules, the percentage of covalent character in an ionic compound increases if the cation is highly charged or the cation is small and the anion is large or the cation has pseudo inert gas configuration.As a result of increased covalent character, the melting point decreases and solubility in less polar solvent increases. Read and above comprehension and answer the following questions. Q.27 The correct order of increasing ionic character is (A) BeCl2 < MgCl2 < CaCl2 < BaCl2 (B) BeCl2 < MgCl2 < BaCl2 < CaCl2 (C) BeCl2 < BaCl2 < MgCl2 < CaCl2 (D) BaCl2 < CaCl2 < MgCl2 < BeCl2 Q.28 Based on lattice energy and other considerations, which one of the following alkali metal chlorides is expected to have the highest melting point ? (A) LiCl (B) NaCl (C) KCl (D) RbCl Paragraph for question nos. 29 to 31 When two compoundsACl3 and DCl3 of two elementsAand D are mixed together a compoundADCl6 is formed. Structural analysis showed thatADCl6 is an ionic compound. Given that DCl3 is trigonal planar andACl3 is trigonal pyramidal predict the shape of the anion. Q.29 If anion has See - Saw shape then shape of cation formed is (A) Linear (B) Bent (C) Pentagonal bipyramidal (D)Trigonal planar Q.30 If shape of anion is tetrahedral then shape of cation formed is (A) Tetrahedral (B) Bent (C) Linear (D)Trigonal planar

Tài liệu liên quan

x
Báo cáo lỗi download
Nội dung báo cáo



Chất lượng file Download bị lỗi:
Họ tên:
Email:
Bình luận
Trong quá trình tải gặp lỗi, sự cố,.. hoặc có thắc mắc gì vui lòng để lại bình luận dưới đây. Xin cảm ơn.