Tiêu đề AITS 04 SOLUTION.pdf ✅

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[1] ANSWER KEY PHYSICS 1. (4) 2. (2) 3. (2) 4. (4) 5. (3) 6. (3) 7. (3) 8. (1) 9. (4) 10. (4) 11. (2) 12. (2) 13. (4) 14. (3) 15. (4) 16. (2) 17. (2) 18. (2) 19. (3) 20. (2) 21. (4) 22. (3) 23. (4) 24. (3) 25. (2) 26. (2) 27. (2) 28. (2) 29. (2) 30. (3) 31. (4) 32. (2) 33. (2) 34. (1) 35. (2) 36. (2) 37. (1) 38. (3) 39. (4) 40. (2) 41. (1) 42. (4) 43. (2) 44. (1) 45. (1) 46. (3) 47. (1) 48. (4) 49. (3) 50. (1) CHEMISTRY 51. (1) 52. (2) 53. (1) 54. (3) 55. (1) 56. (3) 57. (2) 58. (4) 59. (4) 60. (4) 61. (2) 62. (3) 63. (1) 64. (3) 65. (1) 66. (2) 67. (4) 68. (1) 69. (3) 70. (1) 71. (4) 72. (4) 73. (3) 74. (2) 75. (3) 76. (4) 77. (1) 78. (3) 79. (4) 80. (2) 81. (2) 82. (3) 83. (1) 84. (2) 85. (1) 86. (2) 87. (2) 88. (2) 89. (1) 90. (1) 91. (3) 92. (3) 93. (3) 94. (3) 95. (3) 96. (1) 97. (1) 98. (1) 99. (4) 100. (2) BOTANY 101. (1) 102. (2) 103. (4) 104. (2) 105. (3) 106. (1) 107. (1) 108. (1) 109. (3) 110. (3) 111. (4) 112. (1) 113. (2) 114. (3) 115. (2) 116. (1) 117. (1) 118. (4) 119. (1) 120. (3) 121. (2) 122. (4) 123. (1) 124. (1) 125. (3) 126. (4) 127. (1) 128. (1) 129. (2) 130. (3) 131. (3) 132. (3) 133. (4) 134. (3) 135. (2) 136. (4) 137. (2) 138. (4) 139. (3) 140. (3) 141. (3) 142. (2) 143. (3) 144. (2) 145. (3) 146. (2) 147. (1) 148. (3) 149. (4) 150. (3) ZOOLOGY 151. (4) 152. (3) 153. (2) 154. (2) 155. (2) 156. (2) 157. (1) 158. (2) 159. (3) 160. (3) 161. (2) 162. (1) 163. (3) 164. (2) 165. (4) 166. (2) 167. (2) 168. (1) 169. (4) 170. (4) 171. (2) 172. (3) 173. (3) 174. (2) 175. (3) 176. (3) 177. (4) 178. (3) 179. (3) 180. (3) 181. (2) 182. (3) 183. (1) 184. (3) 185. (3) 186. (2) 187. (2) 188. (4) 189. (3) 190. (3) 191. (1) 192. (3) 193. (1) 194. (4) 195. (2) 196. (4) 197. (3) 198. (3) 199. (4) 200. (2) DURATION : 90 Minutes DURATION : 200 Minutes DATE : 12/03/2023 M. MARKS : 720 All India Test Series (NEET-2023) Part Test – 04 Dropper M

[3] 13. (4) The rms velocity of the molecule of a gas of molecular weight M at kelvin temperature T is given by rms   3 =     RT C M Let MO and MH be the molecular weights of oxygen and hydrogen and TO and TH the corresponding kelvin temperature at which Crms is same for both gases. rms O rms H ( ) ( ) C C= O H O H   3   3   =       RT RT M M Hence, = O H O H T T M M TO = + = 273 47 320 K H = = 32, 2 M M O  H 2 320 20 K 32 T =  = 14. (3) 1 mole gas 1 mole gas 1 7 5  = 2 4 3  = mix 1 2 1 2 mix mix mix 1 2 ( ) ( ) 1 1 1 +  =  = +  −  −  − P V C n n n n C mix mix 1 1 1 1 15 1 11 7 4 1 1 5 3 + = +   =  − − − 15. (4) Total translational kinetic energy 3 3 2 2 = = nRT PV 16. (2) 17. (2) In process AB, T = Constant P = Increases  1 P  V or V = Decreases Q = W; W = –ve or Q = –ve  Heat is rejected out of the system. 18. (2) In a refrigerator, the heat dissipated in the atmosphere is more than that taken from the cooling chamber. Therefore, the room is heated if the door of a refrigerator is kept open. 19. (3) W W W W = + + AB BC CD 0 0 0 0 W PV PV = − + +0 4 0 0 W PV = 3 20. (2) The efficiency of heat engine is 2 1  = −1 T T . or 2 1 1 = −1 W T Q T Here, Q1 = Heat absorbed from the source of heat = 6 kcal T1 = Temperature of source = 227 + 273 = 500 K and T2 = Temperature of sin k = 127 + 273 = 400 K Hence, 400 1 6 500 = − W or 100 1 6 500 = − W or W = 1.2 kcal 21. (4) Sound requires material medium to propagate. 22. (3) 54 60 f = f = 0.9 Hz s = 10 m v = f  = 9 m/s 23. (4) 1 1 0 =10log I I I 2 2 0 =10log I I I 2 1 30 10log = I I 2 3 2 2 1 1 10   = =     I A I A 2 1 = 32 A A