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28 Surveying: Measurements Solutions ▣ 1. A line was measured with a 50 m tape. There were 5 tallies and 8 pins, and the distance from the last pin to the end line was 2.25 m. Find the length of the line in meters. [SOLUTION] (50 + 8)(50 m) + 2.25 m = 2902.25 m ▣ 2. A line AB 100 m long was paced by a surveyor four times with the following data: 142, 145, 145.5, and 146. Another line CD was paced four times again with the following results: 893, 893.5, 891, and 895.5. Determine the pace factor. [SOLUTION] PF = 100 m 142 + 145 + 145.5 + 146 4 = 0.6914 m/pace ▣ 3. In the previous question, determine the distance of line CD. [SOLUTION] d = ( 893 + 893.5 + 891 + 895.5 4 ) (0.6914 m pace) d = 617.632 m ▣ 4. In question 4, if line CD was at elevation of 478 m above the sea level and the radius of the earth is 6400 km, determine the reduced distance of line CD along the sea level. [SOLUTION] d ′ = (617.632 m) ( 6400 6400 + 0.478) d ′ = 617.586 m SITUATION 1. Consider the following data which shows the difference in elevation between A and B. Trial Diff. in Elevation (m) No. of measurements 1 520.14 1 2 520.20 3 3 520.18 6 4 520.24 8

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