Tiêu đề 2. Chemistry Cycle Varsity Practice Sheet With Solve.pdf ✅

̧YMZ imvqb  Chemistry Cycle Varsity Practice Sheet................................................................................................... 1 ̧YMZ imvqb Qualitative Chemistry MCQ weMZ mv‡j DU-G Avmv cÖkœvejx 1. Sc †g.‡ji 3d1 B‡jKUabwUi †Kvqv›Uvg msL ̈vi m¤¢ve ̈ †mU †KvbwU? [DU 23-24; SUST 19-20]     3 2 0 + 1 2     3 1 0 + 1 2     3 1 0 – 1 2     3 0 0 + 1 2 DËi:     3 2 0 + 1 2 e ̈vL ̈v: †Kvqv›Uvg msL ̈v †ÿ‡Î,  l Gi gvb 0 †_‡K (n – 1) ch©šÍ nq|  m Gi gvb – l †_‡K 0 mn + l ch©šÍ nq| Sc Gi 3d1 B‡jKUa‡bi †ÿ‡Î, n = 3; l = 2; m = 0; s = + 1 2 2. Al(OH)3 Gi `ave ̈Zv hw` Ôs’ nq Z‡e Gi `ave ̈Zv ̧Yv‡1⁄4i gvb KZ? [DU 23-24; RU-C 21-22; JUST 19-20] 27s2 s 4 3s4 27s4 DËi: 27s4 e ̈vL ̈v: Al(OH)3 ⇌ Al 3+ + 3OH– s s 3s  `ave ̈Zv ̧Yv1⁄4, Ksp = [Al 3+] × [OH– ] 3 = s × (3s) 3 = 27s 4 3. wb‡Pi †Kvb †Rvov †h.‡M mgAvqb cÖfve we` ̈gvb? [DU 23-24; BSMRSTU 18-19] CH4, HCl NaCl, CH3Cl H2S, HCl CaCl2, C6H5Cl DËi: H2S, HCl e ̈vL ̈v: Rjxq `ae‡Y H2S wb‡¤œv3fv‡e mvg ̈ve ̄ vq _v‡K: H2S ⇌ 2H+ + S2– Rjxq `ae‡Y HCl wb‡¤œv3fv‡e mvg ̈ve ̄ vq _v‡K: HCl  H + + Cl – Dfq Rjxq `ae‡Y H + Avqb we` ̈gvb| ZvB †h.M؇qi g‡a ̈ mg-Avqb cÖfve we` ̈gvb| 4. wb‡Pi †Kvb Zwor †P.¤^Kxq wewKi‡Yi Zi1⁄2‣`N© ̈ me‡P‡q †ewk? [DU 22-23] AwZ‡e ̧wb iwk¥ Ae‡jvwnZ iwk¥ G·-iwk¥ †iwWI Zi1⁄2 DËi: †iwWI Zi1⁄2 e ̈vL ̈v: wewfbœ ai‡bi Zwor Pz¤^Kxq wewKi‡Yi Zi1⁄2‣`N© ̈: Zwor Pz¤^Kxq wewKiY Zi1⁄2•`N© ̈ gnvRvMwZK iwk¥ < 0.0005 nm Mvgv iwk¥ 0.0005 nm – 0.01 nm iÄb iwk¥ 0.01 nm – 10 nm AwZ‡e ̧wb iwk¥ 10 nm – 380 nm `„k ̈gvb Av‡jv 380 nm – 780 nm Ae‡jvwnZ iwk¥ 780 nm – 1mm gvB‡μvI‡qf AÂj 1 mm – 1 m †iwWI I †Uwjwfkb 1 mm – 10 km myZivs, Zi1⁄2‣`‡N© ̈i μg: -ray < X-ray < UV-ray < Visible-ray < IR-ray < Microwave < Radiowave 5. NH+ 4 Avq‡bi Dcw ̄ wZ wbY©‡q e ̈eüZ weKviKwU n‡jvÑ [DU 22-23; JU-A 22-23] NaOH K4[Fe(CN)6] NaOH, K2HgI4 (NH4)2C2O4 DËi: NaOH, K2HgI4 e ̈vL ̈v: NH+ 4 Avqb kbv3Ki‡Y †bmjvi `aeYmn cixÿv Kiv nq| †bmjvi `aeY ev †bmjvi weKviK n‡jv NaOH ev KOH `aeY wgwkÖZ ÿvixq cUvwkqvg †UUavAv‡qv‡Wv gviwKD‡iU (II) Gi `aeY (NaOH/KOH + K2[HgI4] wgkÖY) 6. RH wiWevM© aaæeK n‡j, nvB‡Wav‡Rb eY©vwji evgvi wmwi‡Ri 2q jvB‡bi Zi1⁄2‣`N ̈© KZ n‡e? [DU 22-23] 36RH 5 16 3RH 3RH 16 5 3RH DËi: 16 3RH e ̈vL ̈v: evgvi wmwi‡Ri Rb ̈, n1 = 2 n2 = n1 + jvBb bv¤^vi = 2 + 2 = 4 1  = RH ×     1 n1 2 – 1 n2 2 = RH ×     1 2 2 – 1 4 2 = 3RH 16   = 16 3RH
2 ....................................................................................................................................  Chemistry 1st Paper Chapter-2 7. †Kvb Dc ̄ÍiwU m¤¢e bq? [DU 21-22] 2d 3p 4f 1s DËi: 2d e ̈vL ̈v: 2d AiweUv‡ji †ÿ‡Î n = 2 nq| n = 2 n‡j l = 0, 1| A_©vr, 2s Ges 2p AiweUvj m¤¢e; wKš‧ 2d AiweUvj m¤¢e bq| 8. As G KqwU †hvRb B‡jKUab Av‡Q? [DU 20-21] 3 4 5 6 DËi: 5 e ̈vL ̈v: 33As  1s2 2s2 2p6 3s2 3p6 3d10 4s2 4p3 †hvRb B‡jKUab n‡”Q me©‡kl Kÿc‡_i B‡jKUab| As Gi me©‡kl Kÿc‡_ 5wU B‡jKUab Av‡Q| ZvB As Gi †hvRb B‡jKUab 5wU| 9. RH wiWevM© aaæeK n‡j, nvB‡Wav‡Rb cigvYyi eY©vwj‡Z evgvi wmwi‡Ri Rb ̈ me©wb¤œ KZ Zi1⁄2 msL ̈vi iwk¥ wewKwiZ nq? [DU 20-21, 15-16] 3 4 RH 5 36 RH 3 16 RH 9 144 RH DËi: 5 36 RH e ̈vL ̈v: evgvi wmwi‡Ri Rb ̈, n1 = 2 me©wb¤œ Zi1⁄2 msL ̈vi Rb ̈, n2 = n1 + 1 = 2 + 1 = 3   – = RH ×     1 n1 2 – 1 n2 2 = RH ×     1 2 2 – 1 3 2 = RH ×     1 4 – 1 9 = 5 36 RH 10. D‡ËwRZ Ae ̄ vq nvB‡Wav‡Rb cigvYyi †Kvqv›Uvg msL ̈v n = 4, l = 1 wewkó AiweUvjwU wK? [DU 19-20] s orbital p orbital dz 2 orbital dx 2 – y 2 orbital DËi: p orbital e ̈vL ̈v: n = 4 Gi Rb ̈ l = 0, 1, 2, 3 nq| †hLv‡b l = 1 Øviv p AiweUvj wb‡`©k K‡i| 11. bvB‡UaU A ̈vbvq‡b KqwU B‡jKUab i‡q‡Q? [DU 19-20; JU 17-18] 19 23 31 32 DËi: 32 e ̈vL ̈v: bvB‡UaU Avq‡b (NO– 3 ) B‡jKUab msL ̈v = (7 + 8  3 + 1) = 32wU 12. MRI h‡š¿i mvnv‡h ̈ gvbe‡`‡ni †ivM wbY©‡q †Kvb †g.jwUi f~wgKv i‡q‡Q? [DU 19-20] Neon Oxygen Hydrogen Silicon DËi: Hydrogen e ̈vL ̈v: MRI †gwk‡b NMR mwμq cigvYy e ̈eüZ nq| NMR mwμq cigvYy‡Z we‡Rvo msL ̈K †cÖvUb ev wbDUab hy3 wbDwK¬qvm _v‡K| 1H GKwU NMR mwμq cigvYy nIqvq GB †g.jwU‡K MRI †gwk‡b e ̈envi Kiv nq| 13. wb‡¤œi †Kvb cixÿvwU mvjwdDwiK GwmW I bvBwUaK Gwm‡Wi g‡a ̈ cv_©K ̈ Ki‡Z e ̈envi Kiv hvq? [DU 19-20] mve©Rbxb wb‡`©k cixÿv †mvwWqvg Kve©‡bU ̧ov †hv‡M g ̈vM‡bwkqvg wdZv †hv‡M †ewiqvg bvB‡UaU `aeY †hv‡M DËi: †ewiqvg bvB‡UaU `aeY †hv‡M e ̈vL ̈v: mvjwdDwiK GwmW I bvBwUaK Gwm‡W h_vμ‡g SO2– 4 I NO– 3 Avqb we` ̈gvb| mvjwdDwiK Gwm‡W †ewiqvg bvB‡UaU `aeY †hvM Kiv n‡j SO2– 4 Avqb Dcw ̄ Z _vKvq mv`v Aat‡ÿc co‡e| wKš‧ NO– 3 Avq‡bi †ÿ‡Î †Kv‡bv Aat‡ÿc Drcbœ n‡e bv| SO2– 4 (aq) + Ba(NO3)2(aq)  BaSO4(s) + 2NO– 3 (aq) mv`v Aat‡ÿc 14. cÖ_g UavbwRkb avZz wmwi‡Ri GKwU avZz n‡Z cÖvß GKwU M3 Avq‡b cvuPwU B‡jKUab 3d mve‡k‡j Aew ̄ Z| M3+ AvqbwU Kx n‡Z cv‡i? [DU 18-19, 05-06] Cr3+ Mn3+ Fe3+ Sc3+ DËi: Fe3+ e ̈vL ̈v: cÖ_g UavbwRkb avZz wmwiR n‡jv Sc(21) – Zn(30) ch©šÍ| Fe3+(26)  1s2 2s2 2p6 3s2 3p6 3d5 4s0  Fe3+ Avq‡bi B‡jKUab web ̈v‡m 3d mve‡k‡j 5wU B‡jKUab we` ̈gvb | 15. wb‡Pi †Kvb cigvYy ev Avq‡b B‡jKUab I wbDUa‡bi msL ̈v mgvb? [DU 18-19] 9 4 Be 19 9 F 23 11Na+ 18 8O 2– DËi: 18 8O 2– e ̈vL ̈v: 9 4 Be B‡jKUab msL ̈v = 4 wbDUab msL ̈v = 9 – 4 = 5 19 9 F B‡jKUab msL ̈v = 9 wbDUab msL ̈v = 19 – 9 = 10 23 11Na+ B‡jKUab msL ̈v = 11 – 1 = 10 wbDUab msL ̈v = 23 – 11 = 12 18 8O 2– B‡jKUab msL ̈v = 8 + 2 = 10 wbDUab msL ̈v = 18 – 8 = 10 16. `„k ̈gvb Av‡jvi m‡ev©”P Zi1⁄2‣`‡N© ̈i iwk¥ †KvbwU? [DU 18-19] †e ̧wb bxj jvj meyR DËi: jvj e ̈vL ̈v: `„k ̈gvb Av‡jvi Zi1⁄2‣`‡N© ̈i cwimi = 380 nm – 780 nm| jvj Av‡jvi Zi1⁄2‣`‡N© ̈i cwimi = 647 nm – 780 nm, hv `„k ̈gvb Av‡jvi g‡a ̈ me©vwaK|
̧YMZ imvqb  Chemistry Cycle Varsity Practice Sheet.................................................................................................. 3 17. Co Ges Co2+ Gi Rb ̈ wb‡Pi †Kvb †hvR ̈Zv B‡jKUab web ̈vmwU mwVK? [DU 17-18] 4d7 5s2 and 4d7 5s 3d5 4s1 and 3d5 4s 3d7 3s2 and 3d7 3s 3d7 4s2 and 3d7 4s DËi: 3d7 4s2 and 3d7 4s e ̈vL ̈v: Co(27)  [Ar] 3d7 4s2 Co2+(27)  [Ar] 3d7 4s0 18. wb‡Pi †Kvb web ̈vmwU cvDwji eR©b bxwZ I û‡Ûi bxwZ mg_©b K‡i? [DU 17-18] ⃝↿⇂ ⃝↿⇂ ⃝↿ ⃝↿ ⃝↿↿ ⃝↿⇂ ⃝↿⇂ ⃝↿↿ ⃝↿ ⃝⇂ ⃝↿⇂ ⃝↿⇂ ⃝⇂ ⃝↿↿ ⃝↿ ⃝↿⇂ ⃝↿⇂ ⃝↿⇂ ⃝↿ ⃝↿ DËi: ⃝↿⇂ ⃝↿⇂ ⃝↿⇂ ⃝↿ ⃝↿ e ̈vL ̈v: cvDwji eR©b bxwZ: GKB cigvYy‡Z `yBwU B‡jKUa‡bi PviwU †Kvqv›Uvg msL ̈vi gvb KL‡bv mgvb n‡Z cv‡i bv| û‡Ûi bxwZ: mgkw3m¤úbœ wewfbœ AiweUv‡j B‡jKUabmg~n Ggbfv‡e Ae ̄ vb Ki‡e †hb Zviv me©vwaK msL ̈vq AhyM¥ ev we‡Rvo Ae ̄ vq _v‡K| Gme AhyM¥ B‡jKUa‡bi w ̄úb GKBgyLx n‡e| 19. †Kvb cÖwμqvq 234 90Th †_‡K 234 91Pa •Zwi nq? [DU 17-18] -emission -emission -emission neutron-emission DËi: -emission e ̈vL ̈v: †ZRw ̄...q †g.‡ji wbDwK¬qvm n‡Z weUv iwk¥ () wbM©Z n‡j fimsL ̈v AcwiewZ©Z _v‡K wKš‧ cvigvYweK msL ̈v 1 †e‡o hvq| 234 90Th – 0 –1 e  234 91Pa 20. wb‡Pi †Kvb Av‡jvKiwk¥i Zi1⁄2‣`N© ̈ me‡P‡q eo? [DU 17-18] Gamma ray Microwave Visible ray X-ray DËi: Microwave 21. 26 cvigvYweK msL ̈vwewkó GKwU †g.‡ji M †k‡j B‡jKUab msL ̈v KZwU? [DU 16-17] 12 18 14 16 DËi: 14 e ̈vL ̈v: Fe(26)  K 1s2 L 2s 2 2p6 M 3s 2 3p6 3d6 4s2  M †k‡j †gvU B‡jKUab msL ̈v = (2 + 6 + 6) = 14wU 22. je‡Yi `ave ̈Zv ̧Ydj wbY©‡q †Kvb ai‡Yi `aeY Dc‡hvMx?[DU 15-16] Super saturated Unsaturated Saturated All of them DËi: Saturated e ̈vL ̈v: †Kv‡bv wbw`©ó ZvcgvÎvq m¤ú„3 `ae‡Y Dcw ̄ Z K ̈vUvqb I A ̈vbvq‡bi †gvjvi NbgvÎvi Dchy3 NvZmn ̧Ydj‡K H †h.‡Mi `ave ̈Zv ̧Ydj (Ksp) ejv nq| `ave ̈Zv ̧Ydj m¤ú„3 `ae‡Yi †ÿ‡Î wnmve Kiv nq| 23. wkLv cixÿvq †Kvb †g.jwU †mvbvjx njy` wkLv cÖ`k©b K‡i? [DU 15-16; JnU 17-18] Copper Chromium Sodium Calcium DËi: Sodium e ̈vL ̈v: avZz/avZe Avqb eY© eøy-Møvm/†Kvevë Kuv‡P eY© Li/Li+ D3⁄4¡j jvj – Na/Na+ †mvbvjx njy` eY©nxb K/K+ nvjKv †e ̧wb †Mvjvcx jvj Rb/Rb+ jvj‡P †e ̧wb – Cs/Cs+ bxj – Ba/Ba2+ KuvPv Av‡c‡ji gZ meyR bxjvf meyR Ca/Ca2+ B‡Ui b ̈vq jvj nvjKv meyR Sr/Sr2+ UKU‡K jvj – Ra/Ra2+ jvj – Cu/Cu2+ bxjvf meyR eY©nxb wkLv cixÿvq eY© †`q bv  Be2+, Mg2+, Fe2+, Fe3+ , Al 3+ 24. 2p AiweUv‡j n, l Ges m Gi gvb h_vμ‡gÑ [DU 14-15, 06-07; RU-C 22-23, 11-12] 2, 1, 0 2, 1, (– 1, 0, 1) 2, 2, (– 2, – 1, 0, 1, 2) 1, 1, 0 DËi: 2, 1, (– 1, 0, 1) e ̈vL ̈v: 2p AiweUv‡ji †ÿ‡Î, n = 2, l = 1 Ges m = – 1, 0, 1 25. _v‡qvmvj‡dU (S2O 2– 3 ) Avq‡b me©‡gvU †hvRb B‡jKUab msL ̈v KZ? [DU 14-15] 28 30 32 34 DËi: 32 e ̈vL ̈v: S(16) = 1s2 2s2 2p6 6wU 3s 2 3p4 O(8) = 1s2 6wU 2s 2 2p4  S2O 2– 3 Avq‡b me©‡gvU †hvRb B‡jKUab msL ̈v = {(6 × 2) + (6 × 3) + 2} = 32wU 26. 14 6C I 16 8O ci ̄ú‡iiÑ [DU 14-15; JU 17-18] Isomer Isotone Isobar Isotope DËi: Isotone e ̈vL ̈v: 14 6 C G wbDUab msL ̈v = 14 – 6 = 8 16 8O G wbDUab msL ̈v = 16 – 8 = 8 †h‡nZz Zv‡`i wbDUab msL ̈v mgvb ZvB Zviv ci ̄ú‡ii AvB‡mv‡Uvb|
4 ....................................................................................................................................  Chemistry 1st Paper Chapter-2 27. †Kvb is Gi Av‡jvi K¤úv1⁄4 me‡P‡q Kg? [DU 14-15] bxj jvj njy` meyR DËi: jvj e ̈vL ̈v:   1  A_©vr, hvi Zi1⁄2‣`N ̈© me‡P‡q †ewk Zvi K¤úv1⁄4 me‡P‡q Kg| †h‡nZz `„k ̈gvb Av‡jvi cwim‡i jvj e‡Y©i Av‡jvi Zi1⁄2‣`N© ̈ me‡P‡q †ewk ZvB Gi K¤úv1⁄4 me‡P‡q Kg n‡e| 28. wb‡¤œi wewKiY ̧‡jvi g‡a ̈ †KvbwUi Zi1⁄2‣`N© ̈ me‡P‡q Kg? [DU 14-15] X-ray UV-ray -ray Infra-red DËi: -ray e ̈vL ̈v: Zi1⁄2‣`‡N© ̈i μg: -ray < X-ray < UV-ray < Infrared 29. wb‡Pi †Kvb AiweUv‡j B‡jKUab Av‡M cÖ‡ek K‡i? [DU 13-14; IU 17-18] 4f 5d 6p 7s DËi: 4f e ̈vL ̈v: †h AiweUv‡ji kw3 Kg A_©vr (n + l) Gi gvb Kg †mB AiweUv‡j B‡jKUab Av‡M cÖ‡ek K‡i| 4f = 4 + 3 = 7 5d = 5 + 2 = 7 6p = 6 + 1 = 7 7s = 7 + 0 = 7 (n + l ) Gi gvb mgvb n‡j hvi n Gi gvb Kg Zvi kw3 wb¤œ n‡e Ges †mLv‡b B‡jKUab Av‡M cÖ‡ek Ki‡e| ZvB 4f AiweUv‡j B‡jKUab Av‡M cÖ‡ek Ki‡e| 30. AvB‡mv‡Uv‡bi D`vnviYÑ [DU 13-14; JU 17-18] 13 7N, 13 6 C 40 18Ar, 40 20Ca 40 20Ca, 40 19K 31 15P, 32 16S DËi: 31 15P, 32 16S e ̈vL ̈v: 31 15P G wbDUab msL ̈v = 31 – 15 = 16 32 16S G wbDUab msL ̈v = 32 – 16 = 16 G‡`i wbDUab msL ̈v mgvb nIqvq Giv ci ̄ú‡ii AvB‡mv‡Uvb| 31. wb‡Pi wbDwK¬qvi wewμqvq ÔXÕ †K Kx ejv hvq? 14 7N +   17 8O + ÔXÕ [DU 13-14] Proton -particle -ray Neutron DËi: Proton e ̈vL ̈v:  iwk¥ †hvM Kiv n‡j fimsL ̈v 4 e„w× cvq Ges cvigvYweK msL ̈v 2 e„w× cvq| 14 7N + 4 2He2+  17 8O + 1 1H proton 32. wb‡¤œi †Kvb †Kvqv›Uvg †mUwU cigvYyi GKwU B‡jKUa‡bi Rb ̈ m¤¢e bq? [DU 12-13] n = 2, l = 1, m = 0, s = + 1 2 n = 3, l = 1, m = 2, s = – 1 2 n = 1, l = 0, m = 0, s = – 1 2 n = 2, l = 0, m = 0, s =  1 2 DËi: n = 3, l = 1, m = 2, s = – 1 2 e ̈vL ̈v: n = 3 n‡j l = 0, 1, 2 nIqv m¤¢e| l = 1 n‡j m = – 1, 0, + 1 nIqv m¤¢e; wKš‧ m = 2 m¤¢e bq| 33. nvB‡Wav‡R‡bi cvigvYweK eY©vwji †Kvb wmwiRwU‡Z `„k ̈gvb A‡ji iwk¥ †`Lv hvq? [DU 12-13; Agri. Guccho 20-21] Paschen Lyman Balmer Brackett DËi: Balmer e ̈vL ̈v: wmwiR cÖavb eY©vwj AÂj jvB‡gb AwZ‡e ̧wb evgvi `„k ̈gvb c ̈v‡ðb Ae‡jvwnZ (Bbd«v‡iW) eav‡KU Ae‡jvwnZ (Bbd«v‡iW) dzÛ Ae‡jvwnZ (Bbd«v‡iW) nvgwd«m Ae‡jvwnZ (Bbd«v‡iW) 34. wb‡¤œi †mU ̧wji †KvbwU Cr Ges Cr3+ Avq‡bi B‡jKUawbK web ̈vm †`Lvq? [DU 11-12; RU 12-13; CU 11-12; JnU 17-18] Cr Cr3+ [Ar] 3d4 4s1 [Ar] 3d3 4s0 [Ar] 3d5 4s1 [Ar] 3d2 4s1 [Ar] 3d5 4s1 [Ar] 3d3 4s0 [Ar] 3d4 4s2 [Ar] 3d1 4s2 DËi: [Ar] 3d5 4s1 [Ar] 3d3 4s0 e ̈vL ̈v: AiweUvjmg~n B‡jKUab Øviv c~Y© ev Aa©c~Y© Ae ̄ vq AwaK w ̄ wZkxj nq| Cr(24) Gi †ÿ‡Î 3d4 4s2 Gi Zzjbvq 3d5 4s1 AwaK w ̄ wZkxj| Cr(24)  [Ar] 3d5 4s1 Cr3+(24)  [Ar] 3d3 4s0 35. wb‡¤œi wewμqvi k~b ̈ ̄ v‡b wK n‡Z cv‡i? 26 12Mg + 2 1H  24 11Na + ––– [DU 11-12] -particle -particle -ray neutron DËi: -particle