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[SOLUTION] z + e + 0.362 = 1.622 1.256 + e + 0.362 = 1.622 e = 0.004 m ▣ 5. Determine the correct reading at A that will give the level line of sight with the instrument still at point B. [SOLUTION] A ′ = 0.362 + 0.004 A ′ = 0.366 m SITUATION 2. The line of sight of a wye level was tested by setting up exactly midway between two points A and B. The rod reading on A was 1.520 and ta B was 1.395. The instrument was next set up at B and rod readings A and B are 1.683 and 1.490, respectively. ▣ 6. What is the true difference in elevation between A and B? [SOLUTION] From the first condition, z + 1.395 + e = 1.52 + e z = 0.125 m
▣ 7. What is the error in the line of sight? [SOLUTION] From the second condition, z + 1.49 = 1.683 + e1 e1 = −0.068 m ▣ 8. Determine the true rod reading at A that will make the line of sight horizontal. [SOLUTION] A ′ = 1.683 + (−0.068 m) A ′ = 1.615 m ▣ 9. Differential leveling is run from BM1 to BM2 at a distance of 6 km. It was observed that the leveling rod was inclined 4° from the vertical every time the backsight is taken. The average BS reading is 2.4 m and the average length per setup is 300 m. Determine the correct elevation of BM2 if the recorded elevation was 68.3 m. [SOLUTION] Find the correction to be applied in each backsight. e = 2.4 − 2.4 cos 4° e = 0.0058463 m Number of set-ups n = 6000 m 300 m = 20 Corrected values BM2 ′ = 68.3 m − 20(0.0058463 m) BM2 ′ = 68.183 m

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