Tiêu đề DPP-4 SOLUTION.pdf ✅

CLASS : XIth SUBJECT : CHEMISTRY DATE : DPP No. : 4 1 (b) Under similar conditions of P and T, moles or volume of gases react according to stoichiometry of reaction. This is Gay-Lussac’s law of combining volume, e.g., 1 volume H2 combines with 1 volume Cl2 to give 2 volume HCl as: H2 + Cl2→2HCl 2 (b) Real gases show less pressure than ideal gases because molecular interactions lowers the speed of molecules with which they collide 4 (c) Or, a = 2d 3 = 2 × 4.52 3 = 5.219Å = 522 pm ∴ a = 2x 6 (d) Given T1 = 273 + 10 = 283 K T2 = 273 + 20 = 293 K Average KE = 3 2 kT KE1 KE2 = 283 293 = 0.96 Root mean square (rms) velocity, Cl - Na + Cl - x a Topic :- STATES OF MATTER Solutions

Evaporation takes place at constant temperature and thus, kinetic energy does not change. 15 (b) KE = 3 2 RT KE ∝ T KEO2 KESO2 = TO2 TSO2 = 273 546 = 1 2 KESO2 = 2 KEO2 KESO2 > KEO2 17 (b) PV = 1 3 mu 2 ;at constt.V: P1 P2 = u 2 1 u 2 2 18 (d) Van der Waals’ equation (at low pressure), [p + a V 2](V ― b) = RT or pV = RT + pb ― a V + ab V 2 or pVm RT = 1 ― a RT = Z 20 (b) KE = 3 2 kT Where, k is constant. KE ∝ T Here the temperature is same. Hence, for 1 g of H2 and 1 g of CH4 which are taken in two vessels, of 1 L each at same temperature, the kinetic energy per mole will be the same.
ANSWER-KEY Q. 1 2 3 4 5 6 7 8 9 10 A. B B D C B D D B B A Q. 11 12 13 14 15 16 17 18 19 20 A. C C C D B D B D C B