Tiêu đề C1 PSAD Reviewer.pdf ✅

C1 PSAD Reviewer ^_^ Situation 1 - The chandelier is supported by three chains which are concurrent at point O. If the resultant force at O has a magnitude of 130 lb and is directed along the negative z axis, 1. Determine the force in chain A A. 52.1 lb C. 36.41 lb B. 151.26 lb D. 98.74 lb 2. Determine the force in chain B A. 52.1 lb C. 98.74 lb B. 151.26 lb D. 36.41 lb 3. Determine the force in chain C A. 36.41 lb C. 98.74 lb B. 52.1 lb D. 36.41 lb Solution: Difficulty: 1/5 Fc = F (4j-6k) √4 2 +(-6) 2 0.5547 Fj – 0.8321 Fk Fa = Fb = Fc FRz = ΣFz 130 = 3(0.8321F) F = 52.1 Situation 2 - The hook is subjected to three forces A, B, and C as shown. A = 35 kN, B = 45 kN
C1 PSAD Reviewer ^_^ 4. If the resultant of the forces is 80 kN and is acting along the positive x-axis, find angle α. A. 60° C. 22.85° B. 35° D. 14.78° 5. If α = 60°, what is the value of force C such that the resultant of forces A, B, and C acts along the x-axis? A. 45 kN C. 35 kN B. 80 kN D. 40 kN 6. Find the value of C for A, B, and C to be in equilibrium. A. 45 kN C. 72.17 kN B. 40.9 kN D. 36.41 KN Solution: Difficulty: 1/5 C cosα + 45cos60° - 35 = 80 C cosα = 92.5 C sinα = 45sin60° C sinα = 38.97 tanα = 38.97 92.5 ; α = 22.85° If α = 60° C sin60° = 45sin60° ; C = 45kN C cosα + 45cos60° = 35 C cosα = 12.5 C sinα = 45sin60° C sin= 338.97

C1 PSAD Reviewer ^_^ Ay = 376.4 N Situation 4 - Load W is to be lifted using the crane which is hinged at B as shown in the figure. The value of x1 = 10m, x2 = 18m. Neglecting the weight of the crane, 10. Determine the force of Cable AC. A. 26.65 kN C. 42.85 kN B. 30.96 kN D. 19.74 kN 11. Determine the resultant reaction at B. A. 39.4 kN C. 37.48 kN B. 31.52 kN D. 25.96 kN 12. Determine the largest load that can be lifted if the maximum force of Cable AC is 50 kN. A. 67.84 kN C. 44.14 kN B. 47.84 kN D. 34.25 kN Solution: Difficulty: 1/5 tanΘ = 18 18 ; Θ = 45° tanα = 18 8 ; α = 66.04° ΣFh = 0 AC cos45° = BC sin23.96° BC = 1.74 AC ΣFv = 0 AC sin45° + 20 = BC cos23.96° 1.74(AC)cos23.96° = 20 + AC sin45° AC = 22.65 kN