Tiêu đề Conversion 07.pdf ✅

1 Conversion 07 Assume 100% yield if not mentioned and also find x & y gm H O2 22 2 4 Red NaOH CrO Cl then H O KMnO 2 3 Hot Fe 2. Zn-Hg/HCl NaOH, CaO, Tube Mg C (P) (Q) (S) (T) (U) → → → → → ∆ ∆ | HCHO, ↓ HCl 3 (1) H2/Pd (2) NaNO2 Sn NaOH AgCN CHCl 2. KCN HCl,0 C HCl KOH (b) (a) (Z) (Y) (X) (W) (V) ° ← ←  → → → ← 2 4 | 98%, H SO ↓ 2 2 2 22 4 Br NaNO (i) CO SOCl H /Pd (i) HCHO NaOH HCl BaSO (ii) H (ii) H (c) (d) (e) (f ) (g) (H) (i) → → ← → → → ⊕ ⊕ 2 | Ac O / NaOAc, ∆ ↓ NH H PO 3 34 KMnO N H H 4 24 2 KOH Ni (P) (O) (n) (m) (l) (k) (j) ∆ ∆∆ ← ← ← ← ← ← | KOH/EtOH ↓ 3 2 2 3 H O NaNO (i) Red P/Br EtOH (i) EtO HCl (ii) KOH H (ii) H O , (Q) — (R) (S) (t) (u) (v) (w) ⊕ Θ ⊕ + ∆ → → → ← → → 4 | NaBH , ↓ MeOH 4 24 32 3 2 22 4 (i) LiAlH H SO CH NH O HBr (ii) H O H O CCl (D) (C) (B) (A) (z) (y) (x) ∆ ∆∆ ← ← ← ← ← ← 2 4 | Conc., ↓ H SO 2 44 4 2 2 24 4 3 NaNH 1% HgSO HIO 1% KMnO H (i) NaNH Red hot (2eq.) H SO 0 C Pd/BaSO (ii) CH I Fe tube (5) (4) (3) (2) (1) (O) (N) (M) ° ← → ← ← ← ← → 3 | CH I(2 eq.) − ↓ 2 2 3 3 2 Na m CPBA H NaOI HO H O liq.NH H O Pd (6) (7) (8) (9) (10) (11) (12) (13) ⊕ → → → → → ← → − 2 3 2 3 | Al O , ↓ Cr O 24 4 3 3 56 2 2 3 N H (i)OsO O O (i) NaOEt Na pH 6.0 (ii) H IO Zn/H O (ii) Et I Zn/H O Liq.NH (20) (19) (18) (17) (16) (15) (14) = − ← ← → ← ← ←  1. tBuONa [8.4 gm] [50%] [60%] 1.Red P/Cl2 [y gm] [x gm] 22 2 2 4 2 4  ? (i) O  ? HBr Conc. P CC R O (ii) H2O THF H SO H SO BH  dil. (E)← (F)← (G)   →3 (H)  →3 (I)  →(J)  →  (K)  →(L) ? AgCN Total products obtained ?