Tiêu đề 3.-P2C3.-Current-Electricity-2024_With-Solve_Ridoy-6.5.24-PDF.pdf ✅

Pj Zwor  Final Revision Batch 1 Z...Zxq Aa ̈vq Pj Zwor Current Electricity Topicwise CQ Trend Analysis UwcK 2016 2017 2018 2019 2021 2022 2023 †gvU †iv‡ai Ici ZvcgvÎvi cÖfve Ñ Ñ Ñ 1 1 2 – 4 †iva I Av‡cwÿK †iva Ñ 1 Ñ Ñ Ñ 6 – 7 Ry‡ji Zvcxq wμqvi m~Î, Zwor ÿgZv, Zwor kw3 Ñ 1 Ñ 3 6 8 5 23 †Kv‡li Af ̈šÍixY †iva Ges Zwo”PvjK ej Ñ Ñ Ñ Ñ 2 Ñ – 2 †iv‡ai †kÖwY I mgvšÍivj mgš^q ms‡hvM, Zzj ̈ †iva 2 6 1 3 1 5 – 18 eZ©bxi cÖevngvÎv 2 6 1 2 9 4 4 28 †Kv‡li †kÖwY I mgvšÍivj ms‡hvM 1 Ñ 1 2 1 Ñ – 5 In‡gi m~Îvbymv‡i †fv‡ëR Kv‡i›U †jLwPÎ Ñ 1 Ñ Ñ Ñ 1 1 3 wKk©‡di m~Î: m~‡Îi aviYv, eZ©bx‡Z e ̈envi 1 1 1 1 2 Ñ 4 10 ûBU‡÷vb eaxR bxwZ Ñ 1 Ñ 1 2 4 2 10 A ̈vwgUvi I †fvëwgUv‡ii cvV Ñ Ñ Ñ Ñ 3 1 – 4 A ̈wgUvi Gi cvjøv e„w× I kv‡›Ui e ̈envi 1 1 Ñ Ñ 3 6 1 12 * we.`a.: 2020 mv‡j GBPGmwm cixÿv AbywôZ nqwb| weMZ mv‡j †ev‡W© Avmv m„Rbkxj cÖkœ 1| DÏxcKwU jÿ ̈ Ki: [Xv. †ev. 23] 8 B 16 32 D A C P Q R S 24 G r = 0.5 E = 12V (K) X = 16 (K) 1 Kzj¤^ Pv‡R©i msÁv `vI| (L) eZ©bx‡Z †Kv‡li ZworPvjK ej m¤ú~Y© Kvh©Ki nq bv †Kb?Ñ e ̈vL ̈v Ki| (M) M ̈vjfv‡bvwgUvi wew”Qbœ Ae ̄’vq Zwor cÖevn wbY©q Ki| mgvavb: 8  16  24  32  12 V 0.5  Req = (24–1 + 56–1 ) –1  Req = 16.8   Zwor cÖevn, I = V Req + r  I = 12 16.8 + 0.5  I = 0.6936 A  M ̈vjfv‡bvwgUvi wewQbœ Ae ̄’vq Zwor cÖevn 0.6936 A| (Ans.) (N) DÏxc‡Ki ‘X’ †ivawU, wea‡R cÖ`Ë †Kv‡bv GKwU †iv‡ai mv‡_ e ̈envi K‡i mvg ̈e ̄’v m„wó m¤¢e wKbv? MvwYwZK e ̈vL ̈v `vI| mgvavb: eZ©bx‡Z S †iva‡K cwieZ©b K‡i mvg ̈ve ̄’v m„wó Kiv m¤¢e| Avgiv Rvwb, mvg ̈ve ̄’vq, P Q = R S  S = 16  24 8 = 48   S †iv‡ai 32  Gi mv‡_ DÏxc‡Ki 16  †iva †kÖwY‡Z mshy3 Ki‡j, S = 32 + 16 = 48  n‡e| (Ans.) 2| R=20 S M T (K) N E = 12V evwZ [iv. †ev. 23]

Pj Zwor  Final Revision Batch 3 mgvavb: I 1  G 90  3A Current divider low Abyhvqx, I = 90 90 + 1  3 = 2.96 A (Ans.) (N) DÏxcK Abymv‡i Kx e ̈e ̄’v MÖnY Ki‡j 30 A ZworcÖevn gvcv m¤¢e? mgvavb: Avgiv Rvwb, mv‡›Ui †iva, S = G n – 1 = 30 30 3 – 1 = 10   S = R + 1  10 = R + 1  R = 9  A_©vr, 1  †iv‡ai mv‡_ 9  †iva †kÖwY‡Z hy3 Ki‡j M ̈vjfv‡bvwgUvi 30 A Zwor cÖevn gvc‡Z mÿg n‡e| (Ans.) 5| R1 = 40 R2 = 4 R3 = 16 E = 9 V r = 1  R4 = 15 R5 = 10 S [P. †ev. 23] (K) wgUvi eaxR Kx? (L) †Kv‡bv evwZi Mv‡q ‘100 W – 220 V’ †jLv Av‡Q| ej‡Z Kx eyS? (M) eZ©bxi Pvwe S †Lvjv Ae ̄’vq g~j cÖevngvÎv KZ? mgvavb: 9 V 1  40  4  Pvwe S †Lvjv Ae ̄’vq, Zzj ̈ †iva, Req = 40 + 4 = 44   g~j Zwor cÖevn, I = V Req + r  I = 9 44 + 1  I = 0.2 A (Ans.) (N) DÏxc‡Ki eZ©bxi Pvwe S eÜ Ae ̄’vq 10 min Zwor cÖevn Pvjbvi d‡j R4 †iv‡ai wdDRwU M‡j hv‡e wK? †Zvgvi DËi MvwYwZK we‡køl‡Y `vI| [wdDRwU 300 J Zv‡c M‡j hv‡e] mgvavb: I 40  4  15  16  10  I2 I1 I 40  4  I1 16  RP1 44  22  I1 I RP1 = 15  10 15 + 10 = 6   Req = 44  22 44 + 22 = 14.67   g~j Zwor cÖevn, I = V Req + r  I = 9 14.67 + 1  I = 0.5743 A Current divider law Abyhvqx, I1 = 44 44 + 22  I = 0.3828 A Avevi, I2 = 10 10 +15  I1 = 0.1531 A  Drcbœ Zvc, H = I2 2 Rt = 0.15312  15  (10  60)  H = 210.95 J < 300 J myZivs †iv‡ai wdDRwU M‡j hv‡e bv| (Ans.) 6| 12.5  †iv‡ai GKwU Zvi‡K †U‡b wØ ̧Y K‡i GKwU wnUv‡ii KzÐjx •Zwi K‡i G‡Z 220 V mieivn jvB‡b hy3 Kiv n‡jv| KzÐjx‡K 30C Gi cvwb‡Z wbgw3⁄4Z K‡i 305 sec. we`y ̈r Pvjbv Kiv n‡jv| a‡i wb‡Z n‡e m¤ú~Y© Zwor kw3 Zvc kw3‡Z iƒcvšÍwiZ n‡q‡Q| [P. †ev. 23] (K) Kvk©‡di 2q m~Î wee„Z Ki| (L) kv‡›Ui †iva k~b ̈ ev Amxg †KvbwUI bqÑ e ̈vL ̈v Ki|
4  HSC Physics 2nd Paper Chapter-3 (M) DÏxc‡Ki ZviwUi •`N© ̈ 12.5 cm I cÖ ̄’‡”Q‡`i †ÿÎdj 0.1 cm2 n‡j Dcv`v‡bi Av‡cwÿK †iva KZ? mgvavb:†iva, R =  L A   = AR L = 0.1  10–4  12.5 12.5  10–2   = 10–3 m myZivs Dcv`v‡bi Av‡cwÿK †iva 10–3 m| (Ans.) (N) DÏxc‡Ki cvwb wK dzU‡e? †Zvgvi DËi MvwYwZK we‡køl‡Y `vI| mgvavb:Zv‡ii AvqZb AcwiewZ©Z _vK‡j, L1A1 = L2A2  A1 A2 = L2 L1 = 2L1 L1 = 2 R =  L A  R  L A  R2 R1 = L2 L1  A1 A2 = 2  2  R2 = 4  12.5 = 50  GLb, H = Q  V 2 R2 t = ms  2202 50  305 = m  4200  (100 – 30)  m = 1.0042 kg myZivs, m‡e©v”P 1.0042 kg cvwb _vK‡j, cvwb dzU‡e| (Ans.) 7| R1 = 10 R2 = 20 R3 = 10 R4 = 20 3V 3V 3V 3V R5 = 10 B C A [e. †ev. 23] (K) aviKZ¡ Kx? (L) †Kv‡bv e ̄‘‡Z Pv‡R©i gvb wbiew”Qbœ n‡Z cv‡i bvÑ e ̈vL ̈v Ki| (M) eZ©bxi AB As‡ki wefe cv_©K ̈ KZ? mgvavb: A 10  10  10  20  20  B 6 V eZ©bxi mijxK...Z wPÎÑ  RP = 30  30 30 + 30 = 15  A 10  B 6 V 15   VAB = 15 15 + 10  6 = 3.6  myZivs, AB As‡ki wefe cv_©K ̈ 3.6 | (Ans.) (N) R5 †iva AcmviY K‡i eZ©bx m¤ú~Y© Ki‡j g~j cÖev‡ni Kxiƒc cwieZ©b n‡e? MvwYwZKfv‡e we‡kølY Ki| mgvavb: 10  6 V 15  R5 AcmviY Kivi c~‡e©, I1 = V Req = 6 15 + 10 = 0.24 A 6 V 15  R5 AcmviY Kivi ci, I2 = V Req = 6 15 = 0.4 A  I2 I1 = 0.4 0.24 = 1.67  I2 = 1.67 I1 myZivs, R5 AcmviY Ki‡j eZ©bxi g~j Zwor g~j Zwor cÖevn c~‡e©i 1.67 ̧Y n‡e| (Ans.) 8| r1 = 0.2  r1 = 0.3  R = 10  R = 10  eZ©bx-1 eZ©bx-2 E1 = 3 V E2 = 6 V E1 = 3 V E2 = 6 V r2 = 0.3  r1 = 0.2  [wm. †ev. 23] (K) kv›U Kv‡K e‡j? (L) wb‡K‡ji †iv‡ai DòZv mnM 6  10–3 C –1 ej‡Z Kx eyS? (M) eZ©bx-1 Gi ewnt‡iva R Gi ga ̈ w`‡q cÖevwnZ Zwor cÖevn wbY©q K‡iv| mgvavb: Zwor cÖevn, I = Eeq Req + r = 3 + 6 10 + (0.2 + 0.3)  I = 0.857 A myZivs, ewnt‡iva R Gi g‡a ̈ w`‡q Zwor cÖevn 0.857 A| (Ans.)