Tiêu đề DPP - 6 Solutions.pdf ✅

Class : XIIth Subject : CHEMISTRY Date : DPP No. : 6 2 (a) R—CNReduction RCH2CH2 3 (d) C3H9N may have the structures as: (CH3 )3N, (a) CH3CH2CH2NH2, (b) (CH3 )2CHNH2 (c) 4 (b) Tertiary amines, due to lack of H-atom, attached directly with N, does not react with benzene sulphonyl chloride (C6H5SO2CI), i.e., Hinsberg’s reagent. (C2H5 )3N is a tertiary amine, so does not react with C6H5SO2CI. 5 (d) CH3CN H.OH aq.H2SO4 +2H2O ―NH3 CH3COOHDecarboxylation Sodalime ∆ ―CO2 CH4 Ethane ethanoic acid methane Nitrile (A) 8 (a) Nitrobenzene on nitration gives m-dinitro benzene as –NO2 group is meta-directing. In this reaction the attacking reagent is NO + 2 . Conc.HNO3 NO2 nitrobenzene m-dinitrobenzene Conc.H2SO4 NO2 NO2 Topic :- Amines Solutions
9 (a) Presence of—OCH3 gp. on aniline makes it more basic than the presence of —NO2, —Cl or —CH3 gp. 10 (b) Benzene diazonium chloride reacts with phenol in weakly basic medium gives p-hydroxy azobenzene. 11 (c) R—NC+2HgO⟶RNCO+Hg2O 19 (d) The abnormal trend of 3 amines is explained in terms of steric effect. Note basic order of amines on the basis of pKb reported in Finar (CH3 )2NH > CH3NH2 > (CH3 )3N > NH3 3.23 3.32 4.2 4.73 pKb (C2H5 )2NH > (C2H5 )3N > C2H5NH2 > NH3 3.07 3.13 3.37 4.73 pKb 20 (c) SnCI2 + 2HCI(g)→SnCI4 + 2[H] CH3CN + 2[H] + HCI→CH3CH = NH.HCIH2O boil CH3CHO + NH4CI (X ) (Y ) (X ) is acetaldimine hydrochloride and (Y ) is acetaldehyde. N2Cl + benzene diazonium chloride phenol OH Weakly basic medium p-hydroxy azobenzene N N OH + HCl
ANSWER-KEY Q. 1 2 3 4 5 6 7 8 9 10 A. A A D B D C C A A B Q. 11 12 13 14 15 16 17 18 19 20 A. C B B A D B C D D C