Tiêu đề 02 Compaction Solutions.pdf ✅

02 Compaction Solution SITUATION (1-3): A sample of soil compacted according to the Standard Proctor Test has a unit weight of 20.63 kN/m3 at 100 percent compaction and at the optimum water content of 14%. Assume that the solid matter has a specific gravity of 2.67. 1. Determine the dry unit weight of soil (kN/m3 ). Solving for weight of solid: Assume total volume = 1 m3 w = Ww Ws 0.14 = Ww Ws Ww = 0.14 Ws γ = Ws + Ww 20.63 = Ws + 0.14 Ws Ws = 18.0965 kN Solving for dry unit weight of soil: γD = Ws V = 18.0965 1 γD = 18.0965 kN m3 = 18.10 kN m3 ALTERNATIVE SOLUTION: γd = γ 1 + w γd = 20.63 kN/m3 1 + 0.14 = 18.10 kN/m3 2. Determine the volume of air (m3 ). Solving for volume of solid: Ws = Vs (γw)(Gs ) 18.0965 = Vs(9.81)(2.67) Vs = 0.6909 m3