Tiêu đề Advanced Series 10th Class Chemistry- Solutions.pdf ✅

Class 10 Chemistry Table of Content 1. Chemical Reaction And Equation 1 – 19 2. Periodic Classification of Elements 20 – 45 3. Acids, Bases, and Salts 46 - 61 4. Chemical Bonding 62 – 100 5. Metals and Non-Metals 101 – 109 6. General Organic Chemistry 110 – 121 7. Solutions 122 -168 8. Chemical Kinetics 169 - 182

Class 10 – Chemistry | A -10 Chemical Reaction and Equation 1 1. Chemical Reaction and Equation Solutions LEVEL – I 1. Correct option: () In a chemical equation in which the number of atoms of each element is the same on the side of reactants and number of atoms of in each element is the same on products side is called a balanced chemical equation. Balancing a chemical equation involves adjusting the coefficients to make sure that the same number of atoms of each element is present on both sides of the equation. This is used to satisfy the law of conservation of mass, which states that matter cannot be created or destroyed in a chemical reaction, only rearranged. Example - Preparation of Sodium chloride 2 2 ( ) ( ) 2 ( ) Na s Cl g NaCl s + → 2. Correct option: (A) Created, destroyed. According to the law of conservation of mass, this states that the total mass of the reactants in a chemical reaction is equal to the total mass of the products. In a chemical reaction, atoms are neither created nor destroyed. While atoms can rearrange among themselves and combine to form different molecules and compounds during a chemical reaction, the total number of atoms on both product side and reactant side remains the same. So, atoms are conserved throughout a chemical reaction. 3. Correct option: (B) Here in chemical equation on reactants side number of copper molecules are 3 but on product side number of copper molecules are 2.on reactant side number of number of sulfur molecules are 3 and oxygen molecules are 12 but on product side number of sulfur and oxygen molecules are 2,8 respectively. On reactants side number of Potassium, Iodine is only 1. But on products side its clearly showing 4 molecules of Potassium and Iodine respectively. Hence it violates aw of conservation of mass. 4. Correct option: (C) According to law of conservation of mass matter can neither be created nor is destroyed. So, number of atoms present in each molecules on both sides must be equal. In the given options option C is violating this rule on reactants side 2,2,6 Ferrus, Sulfur, Oxygen molecules are present so as in products. 5. Correct option: (D) In options A and B number of atoms on reactant side and product side are not equal. In option A number of nitrogen molecules on reactant and product side is 1,3 respectively, number of Hydrogen molecules are 4and12 respectively. In option B number of Nitrogen molecules are 2,4 respectively, number of Hydrogen’s are 6,12 respectively. 6. Correct option: (A) Number of molecules of Nitrogen and Hydrogen on both sides are same i.e.2,6 respectively. As number of molecules on reactants and products are equal the given equation is well balanced.
Class 10 – Chemistry | A -10 Chemical Reaction and Equation 2 7. Correct option: (A) When potassium nitrate is heated, it decomposes into potassium nitrite and oxygen gas. Above equation is balanced, we can rewrite it as 3 2 2 2 2 KNO KNO O → + . 8. Correct option: (A) The given information, 'n' grams of substance X react with 'm' grams of substance Y to form 'p' grams of R and 'q' grams of S. The chemical equation representing this reaction can be written as X + Y → R + S. In a balanced chemical equation, the total mass of the reactants is equal to the total mass of the products. Therefore, we can conclude that n grams of X combined with m grams of Y should give us p grams of product R and q grams of S product S. Hence, the correct equation representing the reaction for the given condition is n + m = p + q. 9. Correct option: (B) 3 3 2 Cu AgNO Cu NO Ag + → + + 2 ( ) 2 In this reaction, copper reacts with silver nitrate (AgNO3) to form copper (II) nitrate (Cu(NO3)2) and silver (Ag). The coefficients in the equation indicate the Stoichiometry ratios between the reactants and products, such that the number of atoms of each element is balanced on both sides of the equation. 10. Correct option: (B) 2 2 3 N H NH + → 3 2 In this reaction, one molecule of nitrogen gas reacts with three molecules of hydrogen gas to produce two molecules of ammonia. The coefficients in the balanced equation makes the number of atoms of each element is balanced on both sides of the equation. 11. Correct option: (B) The given chemical equation is: ( ) 3 ( ) ( ) Heatcool A NH g C g s  + According to the given information, we need to determine the products of the reaction. Let's analyze each option: A) 3 2 A PCl → →,C Cl This option clearly explains that A reacts to form PCl3 and C reacts to form Cl 2 . However, there is no direct indication of these products in the given equation. Alone PCl3 cannot give Ammonia as a product. Therefore, option A is not applicable. B) 4 A NH Cl C HCl → → , This option suggests that A reacts to form NH Cl 4 (Ammonium chloride) and C reacts to form HCl (hydrochloric acid). The formation of NH Cl 4 is possible if A is ammonia (NH3). Additionally HCl can be formed from C, which could represent a compound containing chlorine. Therefore, option B is a potential answer. C) A, C⎯⎯→ HCl This option suggests that both A and C react to form HCl . While it is possible for A and C to combine and form HCl , there is no direct indication of this in the given equation. Therefore, option C is not correct option.