Tiêu đề COA MIMP QNA.pdf ✅

Most IMP Questions of COA UNIT : 1 1) Define Flip Flop. Explain any two application of it. 2) Draw and explain a common bus system for four registers. 3) Explain memory transfer. 4) Explain bus transfer. 5) Explain logic micro operation and list application of it. 6) Explain three state bus buffer. UNIT : 2 1) List Memory Reference Instruction and explain any one of it. 2) Give list of basic computer register with their size and draw register organization with memory bank. 3) Draw and explain control unit of basic computer system. 4) Explain Instruction cycle. 5) Explain Instruction format. 6) Explain AND and BSA instructions. 7) Explain scheme used to differentiate 3 types of instructions in basic computer. UNIT : 3 1) Explain stack organization of CPU. 2) Explain general register organization. 3) Explain any four addressing mode. 4) Explain characteristics of RISC and CISC. 5) (3*4) + (5*6) convert into RPN and show stack operations. UNIT : 4 1) Explain RAM, ROM, EPROM and EEPROM. 2) Explain Main Memory. 3) Explain Virtual Memory. 4) Explain cache memory with any one mapping technique. 5) Explain Associative Memory. 6) Explain Auxiliary Memory. UNIT : 5 1) Explain Method of Asynchronous Data Transfer. 2) Explain modes of Data Transfer. 3) Explain DMA. 4) Explain CPU-IOP communications.
Q-1 Draw and explain Block Diagram of Digital Computers. Ans  It is an interconnection of digital modules.  It is a system that manipulates discrete elements of information that is represented internally in a binary form.  Advantages: o Easy to Design  Low Cost o Very Fast Speed o More Popular with upgrading Technology o Easy to Function o Easy to Program Q-2 Explain the Register Transfer Language. Ans  Definition: The symbolic notation used to describe the micro operation transfers among registers is called a register transfer language.  It is a convenient tool for describing the internal organization of digital computers in concise and precise manner.  The statement below denotes a transfer of the content of register R1 into register R2. R2 ← R1 Q- 3 Define Flip Flop. Explain any two application of it.  It can store 1-bit information.  It can be designed using NAND or NOR gates.  It has to stable states: Logic 1 and Logic 0  Types of Flip Flop 1. RS Flip Flop 2. D Flip Flop 3. T Flip Flop 4. JK Flip Flop 5. Master Slave JK Flip Flop  Application Of Flip Flop 1.Used as a memory element
2.Used as a delay element 3.Used as a basic block in counters and registers Q-4 Draw and explain a common bus system for four registers. Ans o Bus is a path(of a group of wires) over which information is transferred, from any of several sources to any of several destinations. o A bus structure consists of a set of common lines, one for each bit of a register, through which binary information is transferred one at a time. o Control signal determine which register is selected by the bus. o The two selection lines S1and S0are connected to the selection inputs of all four multiplexers. o The selection lines choose the four bits of one register and transfer them into the four-line common bus. S1 S0 Register Selected 0 0 Register A 0 1 Register B 1 0 Register C 1 1 Register D FunctionTable for Bus Q- 5 Explain Memory Transfer. Ans • Read Operation: The transfer of information from a memory word to the outside environment is called a read operation.
• Write Operation: The transfer of new information to be stored into the memory is called a write operation. • A memory word will be symbolized by the letter M. Read: DR ←M[AR] This causes a transfer of information into DR from the memory word M selected by the address in AR. Write: M[AR] ←R1 This causes a transfer of information from R1 into memory word M selected by address AR. Q-6 Draw and explain Logic Micro-operations in detail. (Hardware implementation of Logic micro operation.) Ans Logic micro operations specify binary operations for strings of bits stored in registers. Fig. Hardware implementation of Logic micro operation S1 S0 Output Operation 0 0 E=A /\B AND 0 1 E = AV B OR 1 0 E = A ⊕B XOR 1 1 E= Â Compliment Function table