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Solutions Chapter 19 Coordination Compounds SECTION - A Objective Type Questions (One option is correct) 1. The correct structure of ethylenediaminetetraacetic acid (EDTA) is [IIT-JEE-2010] (1) N CH CH N HOOC CH2 HOOC CH2 CH2 COOH CH2 COOH (2) N CH2 CH2 N HOOC HOOC COOH COOH (3) N CH2 CH2 N CH2 COOH CH2 COOH HOOC CH2 HOOC CH2 (4) N CH CH N H CH2 COOH HOOC CH2 H CH2 HOOC CH2 COOH Sol. Answer (3) N CH2 CH2 N CH2 COOH CH2 COOH HOOC CH2 HOOC CH2 2. Of the following, which ligand does not posses the name suggested by IUPAC when it acts as a ligand in complex? (1) H2O, aqua (2) NH3, ammonia (3) CO, carbonyl (4) F–, fluoro Sol. Answer (2) Fact.
46 Coordination Compounds Solutions of Assignment 3. Write the structural formula for aqua-bromo-bis (ethylenediamine) chromium (III) chloride (1) [CrBr(H2O) (en)]Cl (2) [CrBr2(H2O) (en)]Cl2 (3) [CrBr(H2O) (en)2]Cl2 (4) [CrBr(H2O) (en)2]Cl3 Sol. Answer (3) 2 2 2 2 22 2 [CrBr(H O)(NH CH CH NH ) ]Cl  4. The complex cis [CoCl(NH3)(NH2CH2CH2NH2) 2] 2+ has an octahedral geometry. Name of this complex ion according to IUPAC would be (1) cis - chloroamminethylenediamine cobalt (II) ion (2) cis - amminechloroethylenediamine cobalt (III) ion (3) cis - amminechlorobis (ethylenediamine) cobalt (II) ion (4) cis - amminechlorobis (ethylenediamine) cobalt (III) ion Sol. Answer (4) cis-amminechlorobis (ethylenediamine) cobalt (III) ion. 5. Which complex ion has cis and trans isomer? (1) [PdCl3NH3] – (2) [Pd(CN)5NH3] – (3) [PtCl2(CN)2] 2– (4) [Pt(C2O4) 2] 2– Sol. Answer (3) For cis and trans isomer, complex should have [MA2 B2 ] or [MA2 BC] or [MA4 B2 ] or [MA2 B4 ] formula. 6. What is the name of the complex [Ni(H2O)4(NH2CH2CH2NH2)]SO4.5H2O as per IUPAC rules? (1) Aquaethylenediamine nickel (II) sulphate-1-water (2) Tetraaquaethylenediamine nickel (II) sulphate-5-water (3) Tetraaqua bis (ethylene diamine) nickel (II) sulphate-5-water (4) Tetraaqua bis (ethylene diamine) nickel (III) sulphate-5-water Sol. Answer (2) Tetraaquaethylenediamine nickel (II) sulphate-5-water. 7. The IUPAC name of [Ni(NH3) 4][NiCl4] is [IIT-JEE-2008] (1) Tetrachloronickel (II)-tetraamminenickel (II) (2) Tetraamminenickel (II) - tetrachloronickel (II) (3) Tetraamminenickel (II) - tetrachloronickelate (II) (4) Tetrachloronickel(II) - tetraamminenickelate (0) Sol. Answer (3) IUPAC name is tetraamminenickel(II)-tetrachloronickelate(II). 8. As per IUPAC nomenclature, the name of the complex [Co(H2O)4(NH3) 2]Cl3 is [IIT-JEE-2012] (1) Tetraaquadiaminecobalt (III) chloride (2) Tetraaquadiamminecobalt (III) chloride (3) Diaminetetraaquacobalt(III) chloride (4) Diamminetetraaquacobalt (III) chloride Sol. Answer (4) 9. Which pair of isomers illustrates the concepts of ionisation isomers? (1) [Cr(SCN) (NH3) 5] 2+ and [Cr(NCS) (NH3) 5] 2+ (2) [CoCl(NH3) 5] SO4 and [Co(SO4) (NH3) 5]Cl (3) cis [PtCl2(NH3) 2] and trans [PtCl2(NH3) 2] (4) (+) - [Co(en)3] 3+ and (–) - [Co(en)3] 3+
Solutions of Assignment Coordination Compounds 47 Sol. Answer (2) 35 4 4 35 [CoCl(NH ) ]SO [Co(SO )(NH ) ]Cl  give different ions in solution. 10. Which of the following coordination compounds is incapable of showing geometrical isomerism? (1) [PtCl2(NH3) 2] (2) [CoCl2(NH3) 4] + (3) [Co(NO2) 3(NH3) 3] (4) [Co(en)3] 3+ Sol. Answer (4) 3 3 [Co(en) ] does not show geometrical isomerism. 11. Which of the following compounds exhibit geometrical isomer? (1) Pt(NH3) 2Cl2 (2) Zn(NH3) 2Cl2 (3) Pt(NH3) 3Cl (4) All of these Sol. Answer (1) Pt(NH3 ) 2 Cl2 12. The ionization isomer of [Cr(H2O)4Cl(NO2)]Cl is [IIT-JEE-2010] (1) [Cr(H2O)4(O2N)]Cl2 (2) [Cr(H2O)4Cl2] (NO2) (3) [Cr(H2O)4Cl(ONO)]Cl (4) [Cr(H2O)4Cl2(NO2)] H2O Sol. Answer (2) Cr(H2 O)4 Cl(NO2 )]Cl and [Cr(H2 O)4 Cl2 ](NO2 ) have same molecular formula but they give different ions on ionization. 13. NiCl2{P(C2H5) 2(C6H5)}2 exhibits temperature dependent magnetic behaviour (paramagnetic/diamagnetic). The coordination geometries of Ni2+ in the paramagnetic and diamagnetic states are respectively [IIT-JEE-2012] (1) Tetrahedral and tetrahedral (2) Square planar and square planar (3) Tetrahedral and square planar (4) Square planar and tetrahedral Sol. Answer (3) The hybridisation of Ni2+ in paramagnetic complex is sp3 and hence the complex is tetrahedral. The diamagnetic complex is square planar as the hybridisation of Ni2+ is dsp2 . 14. A six coordinate complex of formula CrCl3.6H2O has green colour. A 0.1 M solution of the complex when treated with excess of AgNO3 gave 28.7 g of white precipitate. The formula of the complex would be (1) [Cr(H2O)6]Cl3 (2) [Cr(H2O)5Cl]Cl2.H2O (3) [Cr(H2O)4Cl2]Cl.2H2O (4) [Cr(H2O)3Cl3].3H2O Sol. Answer (2) 0.1 mole of complex gives 28.7 gm of AgCl. Mole of AgCl formed 28.7 0.2 108 35.5   So the formula is [Cr(H2 O)5 Cl]Cl2 .H2 O. 15. If excess of AgNO3 solution is added to 100 ml of 0.024 M solution of dichlorobis (ethylene diamine) cobalt (III) chloride, how many moles of AgCl will be precipitated? (1) 0.0012 (2) 0.0016 (3) 0.0024 (4) 0.0048 Sol. Answer (3) One Cl– ion is present outside the co-ordination sphere, so, mole of AgCl formed is equal to 1 10 × mole of complex = 0.0024.
48 Coordination Compounds Solutions of Assignment 16. The EAN of Pt in potassium hexachloroplatinate (IV) is (1) 46 (2) 86 (3) 36 (4) 84 Sol. Answer (2) EAN = (78 – 4) + 2 × 6 = 86 17. Which of the following complex has five unpaired electrons? (1) [Mn(H2O)6] 2+ (2) [Mn(CN)6] 3– (3) [CrCl3(H2O)3] (4) [Ag(NH3) 2] + Sol. Answer (1) 2 5 Mn : 3  d H2 O is a weak ligand, so, [Mn(H2 O)6 ] +2 complex contain 5 unpaired e– . 18. Which of the following species is diamagnetic? (1) An isolated, gas-phase V3+ ion (2) A high spin ocatahedral Fe+2 complex (3) An isolated, gas phase Cu2+ ion (4) A low spin octahedral Co3+ complex Sol. Answer (4) Low spin complexes of Co+3 do not contain any unpaired e–. 19. The complex [Ni(CN)4] 2– is diamagnetic and the complex [NiCl4] 2– is paramagnetic. What can you conclude about their molecular geometries? (1) Both complexes have square planar geometries (2) Both complexes have tetrahedral geometries (3) [NiCl4] 2– has a square planar geometry while [Ni(CN)4] 2– has a tetrahedral geometry. (4) [NiCl4] 2– has a tetrahedral geometry while [Ni(CN)4] 2– has a square planar geometry Sol. Answer (4) 2 2 4 [Ni(CN) ] square planar    dsp 2 3 4 (NiCl ) Tetrahedral    sp 20. [PtCl2(NH3) 2] [Electronic configuration of Pt : [Xe]5d86s2] (1) A tetrahedral geometry and is paramagnetic in behaviour (2) A tetrahedral geometry and is diamagnetic in behaviour (3) A square planar geometry and is paramagnetic in behaviour (4) A square planar geometry and is diamagnetic in behaviour Sol. Answer (4) Most of the complexes of Pt+2 are square planar and diamagnetic. 21. Which of the following complex is considered to be tetrahedral? (1) [FeCl4] – (2) [Ni(CN)4] 2– (3) [PtCl4] 2– (4) [PdCl2(NH3) 2] Sol. Answer (1) [FeCl4 ] – is a tetrahedral complex.

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