Tiêu đề 3. P2C3 (Current Electricity)_With Solve_Ridoy 25.11.24.pdf ✅

Pj Zwor  Varsity Practice Sheet .................................................................................................................................... 1 MCQ weMZ mv‡j DU-G Avmv cÖkœvejx 1. GKwU ûBU‡÷vb wea‡Ri PviwU evû P, Q, R Ges S-G h_vμ‡g 8 , 12 , 16  Ges 48  †iva hy3 Av‡Q| weaRwU‡K mvg ̈ve ̄’vq Avb‡Z PZz_© evû‡Z KZ †iva Kxfv‡e hy3 Ki‡Z n‡e? [DU 23-24] 24 , series 24 , parallel 48 , series 48 , parallel DËi: 48 , parallel e ̈vL ̈v: P Q = R S  8 l2 = 16 S  S = 24   Av‡iKwU 48  parallel G mshy3 Ki‡j S = 48 2 = 24  n‡e| 2. bqwU †ejbvK...wZi Zvi, hv‡`i cÖwZwUi e ̈vm d I •`N© ̈ L, GK‡Î †kÖwY m3⁄4vq mshy3 Av‡Q| m3⁄4vwUi †iva hw` GKwU L •`‡N© ̈i †ejbvK...wZi Zv‡ii †iv‡ai mgvb nq, Z‡e ZviwUi e ̈vm KZ? [DU 22-23] 3d 9d d 3 d 9 DËi: d 3 e ̈vL ̈v: Zzj ̈ †iva, R = 9L d 2 4 L •`N© ̈ I D e ̈v‡mi †ej‡bi †iva, R = L D 2 4 R = R  9L d 2 = L D 2  D 2 = d 2 9  D = d 3 3. GKwU e ̈vUvwii g‡a ̈ Zwor cÖevn i Øviv cÖKvk Kiv nq| H e ̈vUvwii Zwo”PvjK ej, Gi `yB cÖv‡šÍi wefe cv_©‡K ̈i mgvb KLb n‡e? [DU 21-22] memgq KL‡bvB bv ïaygvÎ hLb i = 0 ïaygvÎ hLb i = aaæeK DËi: ïaygvÎ hLb i = 0 e ̈vL ̈v: E = V + ir E = V n‡j, ir = 0 myZivs i = 0 4. 6  Ges 12  gv‡bi `yBwU †iva mgvšÍiv‡j mshy3 Av‡Q| GB mgvšÍivj ms‡hvM‡K GKwU 4  gv‡bi †iva Ges 24 V e ̈vUvwii mv‡_ wmwi‡R mshy3 Kiv n‡jv| D3 ms‡hv‡M 6  †iv‡ai wfZ‡i cÖevwnZ Zwor Gi cwigvY KZ? [DU 21-22] 2 A 3 A 6 A 12 A DËi: 2 A e ̈vL ̈v: R1 = 6  R2 = 12  R3 = 4  24 V I1 I Rp = R2R1 R2 + R1 = 12  6 12 + 6 = 4   Rs = Rp + R3 = (4 + 4)  = 8   I = V Rs = 24 8 = 3 A  I1 = R2  I R1 + R2  I1 = 12  3 6 + 12  I1 = 2 A 5. 6 V kw3i Drm Øviv GKwU evwZi ga ̈ w`‡q 0.3 A we`y ̈r 2 wgwbU a‡i cÖevwnZ Kiv n‡jv, GB 2 wgwb‡U evwZwU Øviv kw3 e ̈‡qi cwigvY KZ? [Agri. Guccho 20-21; DU 14-15] 12 J 1.8 J 216 J 220 J DËi: 216 J e ̈vL ̈v: e ̈wqZ kw3, W = Pt = VIt = 6  0.3  2  60 = 216 J
2 ........................................................................................................................................  Physics 2nd Paper Chapter-3 6. q Avavb wewkó GKwU †MvjK‡K GKwU Acwievnx myZvi GKcÖv‡šÍ †eu‡a  †KŠwYK †e‡M †Nviv‡bv n‡”Q| N~Y©vqgvb AvavbwU Kx cwigvY we`y ̈r Drcbœ Ki‡e? [DU 20-21] q 2q q  q 2 DËi: q 2 e ̈vL ̈v: T = 2   I = q 2      cÖevn I = q T  I = q 2 7. wb‡Pi eZ©bx‡Z ZworcÖevn I1 Gi gvb KZ? [DU 19-20] 30  5  0.6 A + I1 I2 9 V – R 0.2 A 0.4 A 0.6 A 1.2 A DËi: 0.4 A e ̈vL ̈v: 30  5  A + I1 I2 9 V – R 0.6 A B D C Req = V I = 9 0.6 = 15  ABCD As‡ki Zzj ̈‡iva = 15 – 5 = 10   1 R + 1 30 = 1 10  R = 30  10 30 – 10  R = 15   I1 = 30  I R + 30  I1 = 30  0.6 15 + 30  I1 = 2 5 A  I1 = 0.4 A 8. wP‡Î cÖ`wk©Z eZ©bx‡Z 4  †iv‡ai g‡a ̈ ZworcÖevn KZ? [DU 18-19] 2  5 V 2  4  5 4 Ampere 5 8 Ampere 1 Ampere 4 5 Ampere DËi: 1 Ampere e ̈vL ̈v: Req =     2  2 2 + 2 + 4  Req = 5   I = V R  I = 5 5  I = 1 A 9. PviwU •e`y ̈wZK †iva h_vμ‡g 1, 2, 3 Ges 4 ohm ci ̄úi †kÖwY mgev‡q hy3 Ki‡j †KvbwUi g‡a ̈ w`‡q me‡P‡q †ewk we`y ̈r cÖevwnZ n‡e? [DU 17-18; SUST 16-17] 1 ohm 2 ohm 4 ohm me ̧‡jvi ga ̈ w`‡q mgvb we`y ̈r cÖevwnZ n‡e DËi: me ̧‡jvi ga ̈ w`‡q mgvb we`y ̈r cÖevwnZ n‡e e ̈vL ̈v: †kÖwY mgev‡q cÖwZwU †iv‡ai ga ̈ w`‡q mgvb we`y ̈r cÖevwnZ n‡e| 10. wP‡Î cÖ`wk©Z eZ©bx‡Z cÖevngvÎv I2 KZ n‡e? [DU 17-18] 20  I 9 V 12  10  I2 I1 I2 I1 0.16 A 0.26 A 0.36 A 0.46 A DËi: 0.16 A e ̈vL ̈v: 20  I 9 V 12  10  I2 I1 I2 I1 + – eZ©bxi Zzj ̈‡iva, Req = 20 + 10  12 10 + 12  Req = 20 + 60 11  Req = 280 11 
Pj Zwor  Varsity Practice Sheet ................................................................................................................................... 3  I = 9 280 11  I = 99 280 A  I2 = R1  I R1 + R2  I2 = 10  99 280 10 + 12  I2 = 99 28  22  100 30  20  1 6  0.16 A 11. 12 V Zwo”PvjK kw3 Ges 0.1  Af ̈šÍixY †iv‡ai GKwU e ̈vUvwi‡K GKwU •e`y ̈wZK †gvU‡ii m‡1⁄2 mshy3 Ki‡j e ̈vUvwii cÖvšÍ؇qi wefe cv_©K ̈ `uvovq 7.0 V| †gvU‡i mieivnK...Z Kv‡i‡›Ui gvb KZ? [DU 17-18] 50 A 70 A 12 A 190 A DËi: 50 A e ̈vL ̈v: E = V + Ir  I = 12 – 7 0.1 = 50 A 12. GKwU Zvgvi Zv‡ii •`N© ̈ 2 m I e ̈vm 5 mm| hw` ZviwUi •`N© ̈ wØ ̧Y I e ̈vm A‡a©K Kiv nq Z‡e ZviwUi Av‡cwÿK †iv‡ai Kx cwieZ©b n‡e? [DU 16-17] Av‡cwÿK †iva A‡a©K n‡e Av‡cwÿK †iva GKB _vK‡e Av‡cwÿK †iva wØ ̧Y n‡e Av‡cwÿK †iva Pvi ̧Y n‡e DËi: Av‡cwÿK †iva GKB _vK‡e 13. cÖ`Ë eZ©bx‡Z †iva R KZ? [DU 16-17] 9.0 V 5.0  0.6 A R 30  I1 I2 15  20  25  30  DËi: 15  e ̈vL ̈v: 30  5  A + I1 I2 9 V – R 0.6 A B D C Req = V I = 9 0.6 = 15  ABCD As‡ki Zzj ̈‡iva = 15 – 5 = 10   1 R + 1 30 = 1 10  R = 30  10 30 – 10  R = 300 20 = 15  14. hw` 5 A Zwor 3 N›Uv a‡i GKwU evwZi ga ̈ w`‡q cÖevwnZ nq Zvn‡j H evwZi ga ̈ w`‡q cÖevwnZ Pv‡R©i gvbÑ [DU 15-16] 3.6 × 104 C 5.4 × 104 C 1.4 × 103 C 3.6 × 106 C DËi: 5.4 × 104 C e ̈vL ̈v: Q = It = 5  3  60  60 C = 5.4  104 C 15. cÖ`Ë eZ©bx‡Z R3 †iv‡a ZworcÖevn KZ? [DU 15-16] R1 = 1  R3 = 2  R2 = 2  2 V + – 3 A 2 A 1 A 0.5 A DËi: 0.5 A e ̈vL ̈v: Req = 1 + 2  2 2 + 2  Req = 2  I = V Req = 2 2 = 1 A †h‡nZz R2 I R3 †iva mgvb Ges mgvšÍivj ZvB 1 A `yB fv‡M wef3 n‡q cwievwnZ n‡e|  IR2 = IR3 = 1 2 A 16. GKwU ûBU‡÷vb wea‡Ri PviwU evû‡Z h_vμ‡g 6, 18, 10 Ges 20 In‡gi †iva hy3 Av‡Q| PZz_© evû‡Z KZ gv‡bi †iva †kÖwY mgev‡q hy3 Ki‡j weaRwU mvg ̈ve ̄’v cÖvß n‡e? [CU 15-16, 05-06; JU 14-15, 11-12, 10-11; RU 09-10; DU 06-07] 20  30  10  40  DËi: 10  e ̈vL ̈v: mvg ̈ve ̄’vq, P Q = R S  S = QR P  S = 18  10 6  S = 30  wKš‘ S = 20   S > S, myZivs mvg ̈ve ̄’vq ivL‡Z n‡j PZz_© evû‡Z (30 – 20) = 10  †kÖwY‡Z hy3 Ki‡Z n‡e|
4 ........................................................................................................................................  Physics 2nd Paper Chapter-3 17. cÖ`Ë eZ©bx‡Z R3 Gi `yB cÖv‡šÍ wefe cv_©K ̈ n‡”QÑ [DU 14-15] 10 V 8  R3 6  3  5 V 2 V 8 V 6 V DËi: 8 V e ̈vL ̈v: Zzj ̈‡iva, Req = 3  6 3 + 6 + 8 = 10   I = V Req  I = 10 10  I = 1 A  VR3 = IR3  VR3 = 1  8  VR3 = 8 V 18. GKwU bjvKvi Zvgvi Zv‡ii †iva R| AvqZb mgvb †i‡L ZviwUi •`N© ̈ wØ ̧Y Kiv n‡j cwiewZ©Z †iva KZ? [DU 14-15] 2R 4R 8R R 2 DËi: 4R e ̈vL ̈v: R2 = n2R1  R2 = 22R1  R2 = 4R1 19. eZ©bx‡Z B Ges C we›`yi g‡a ̈ wefe cv_©K ̈ KZ? [DU 13-14] 6 V 2  3  A D B C 3  6  1 V 2 V 3 V 9 V DËi: 2 V e ̈vL ̈v: Zzj ̈ †iva, Req = 2 + 3  6 3 + 6 + 3  Req = 2 + 2 + 3  Req = 7   I = V Req = 6 7 A  VBC = I  RBC  VBC = 6 7  3  6 3 + 6  VBC = 6  2 7  VBC = 1.7414 V  VBC  2 V 20. †jLwP‡Î GKwU Zv‡ii `yB cÖv‡šÍi wefe cv_©‡K ̈i mv‡_ Zwor cÖev‡ni cwieZ©b †`Lv‡bv n‡q‡Q| ZviwUi †iva KZ? [DU 13-14] 0 1 2 3 4 5 6 7 8 9 8 7 6 5 4 3 2 1 0 Voltage (volt) Current (amps) 6  0.67  5  1.5  DËi: 1.5  e ̈vL ̈v: R = V I  R = 9 6  R = 1.5  21. wb‡Pi wgwkÖZ GKK ̧wji g‡a ̈ †KvbwU IqvU Gi mgZzj ̈ bq? [DU 13-14] Joul/sec (Amp)(Volt) (Amp2 )()  2 /Volt DËi:  2 /Volt e ̈vL ̈v: P = W t GKK watt  P = VI GKK (Amp) (volt)  P = V 2 R GKK (volt)2 /  P = I2R GKK (Amp)2 () 22. 100 W Ges 220 V wjwLZ GKwU •e`y ̈wZK evj¦ cÖwZw`b 10 N›Uv R¡‡j| 1 kWh Gi g~j ̈ 3.00 UvKv n‡j Gi Rb ̈ RyjvB gv‡m •e`y ̈wZK wej KZ Avm‡e? [DU 13-14] 220 Tk 155 Tk 105 Tk 93 Tk DËi: 93 Tk e ̈vL ̈v: †gvU e ̈wqZ kw3, W = Pt 1000  31 = 100  10  31 1000 kWh = 31 kWh †gvU wej = 31  3 = 93 UvKv