Tiêu đề Varsity Weekly-3 (Set-A) Solution.pdf ✅

3 e ̈vL ̈v: K...ZKvR = MwZkw3i cwieZ©b Here, x = 2t 2 + 5  v = dx dt = 4t at t = 5s, v = 20 m/s  K...ZKvR = 1 2 mv2 = 1 2  2  (20)2 = 400 J 16. 75% `ÿZvi 4000 W Gi †Kv‡bv cv¤ú M‡o 15 m D”PZvq Aew ̄’Z (3  2  1) m3 †Kv‡bv U ̈vs‡K cvwb Zzj‡Q| Tank c~Y© Ki‡Z KZ mgq jvM‡e? 5.88 min 9.8 min 19.6 min 4.9 min DËi: 4.9 min e ̈vL ̈v: Pin = 4000 W Pout = Pin   = 0.75  4000 = 3000 W m = V = 1000  3  2  1 = 6000 kg  3000 = 6000  9.8  15 t  t = 294 s = 4.9 min 17. Kv‡Ri AwfKl©xq GKK Kx? Ryj AvM© †KwR-wgUvi WvBb-†mw›UwgUvi DËi: Ryj 18. cwieZ©bkxj ej Øviv K...ZKvR n‡jvÑ W =  f i F  . ds  W =  xf xi F(x) dx W = GMm     1 rb – 1 ra W =  x 0 Fdx DËi: W =  xf xi F(x) dx 19. GK e ̈w3 GKwU e ̄`‡K 40 s-G 1 m D”PZvq IVvq| Aci GK e ̈w3 GKB e ̄`‡K 120 s-G GKB D”PZvq Zzj‡Z cv‡i| Zv‡`i Kv‡Ri AbycvZ n‡eÑ 1 : 3 1 : 1 2 : 1 3 : 1 DËi: 1 : 1 e ̈vL ̈v: W  h  W1 W2 = h1 h2 = 1 [h1 = h2]  W1 : W2 = 1 : 1 20. wb‡Pi †Kvb e ̄`i MwZkw3 †ewk? fi M, †eM 2v fi 2M, †eM 3v fi M, †eM 4v fi 3M, †eM 2v DËi: fi 2M, †eM 3v e ̈vL ̈v: (K) Ek  2Mv2 (L) Ek  9Mv2 (M) Ek  8Mv2 (N) Ek  6Mv2 21. wb‡Pi †KvbwU msiÿYkxj e‡ji D`vniY? Nl©Y ej mv›`aej AwfKl©xq ej NvZ ej DËi: AwfKl©xq ej e ̈vL ̈v: †h ej †Kv‡bv e ̄`i Dci wμqv Ki‡j Zv‡K †h‡Kv‡bv c‡_ Nywi‡q cybivq cÖv_wgK Ae ̄’v‡b Avb‡j ej KZ...©K K...ZKvR k~Y ̈ nq Zv‡K msiÿYkxj ej e‡j| D`vniY: AwfKl©xq ej, ˆe`y ̈wZK ej, Av`k© w ̄úas Gi weK...wZ cÖwZ‡ivax ej cÖf...wZ| 22. 2 HP Gi GKwU cv¤ú 12 wgwb‡U 1000 wjUv‡ii GKwU U ̈vs‡K cvwb fwZ© Ki‡Z cv‡i| AwZwi3 1 HP Gi GKwU cv¤ú hy3 Ki‡j D3 Kv‡R KZ wgwbU mgq mvkÕq n‡e? 8 4 6 2 DËi: 4 e ̈vL ̈v: P = mgh t  P  1 t P2 P1 = t1 t2  3 2 = 12 t2  t2 = 8 min  mvkÖq = 12 – 8 = 4 min 23. 100 gm f‡ii GKwU cv_i Dj¤^Z‡j 20 m e ̈vmv‡a©i e„Ë c‡_ Nyi‡Z Nyi‡Z A Ae ̄’vb n‡Z B-Ae ̄’v‡b Avmj (wPÎ-1)| kw3i cwieZ©b KZ n‡e? B A r=20m wPÎ-1 10 J 39.2 J 30 J 50.2 J DËi: 39.2 J e ̈vL ̈v: Ep  mg × 2r  0.1  9.8  2  20  39.2 J 24. w ̄’i Ae ̄’v †_‡K 20 kg fiwewkó †Kvb e ̄` wbw`©ó e‡ji wμqvi d‡j 2s ci 15 ms–1 †eM cÕvß nj| 4s ci e ̄`wUi MwZkw3 KZ n‡e? 6000 J 12000 J 18000 J 9000 J DËi: 9000 J e ̈vL ̈v: v = u + at  a  15 2  7.5 ms–2  E  1 2 mv 2  1 2 m (at)2  1 2  20  (7.5  4)2  9000 J 25. GKwU w ̄úas‡K GK Ae ̄’vb †_‡K Ab ̈ Ae ̄’v‡b cÕmvwiZ Ki‡Z cÕhy3 ej KZ...©K m¤úvw`Z KvR mi‡YiÑ mgvbycvwZK e ̈ ̄ÍvbycvwZK e‡M©i mgvbycvwZK e‡M©i e ̈ ̄ÍvbycvwZK DËi: e‡M©i mgvbycvwZK e ̈vL ̈v: W  1 2 k (xf 2 – xi 2 )  W  x 2
4 imvqb (Chemistry) 1. †Kvb †gØj †Rvov ch©vq mviwYi GKB ch©vqfy3? Li, Na Mn, Fe Ar, Rn Al, Ga DËi: Mn, Fe e ̈vL ̈v: Mn(25)  1s2 2s2 2p6 3s2 3p6 3d5 4s2 ; ch©vq-4 Fe(26)  1s2 2s2 2p6 3s2 3p6 3d6 4s2 ; ch©vq-4 2. †KvbwUi g‡a ̈ KY© m¤úK© i‡q‡Q? Mg, Ca Na, K B, Si P, S DËi: B, Si e ̈vL ̈v: ch©vq mviwYi wØZxq ch©vqfz3 wewfbœ MÖæ‡ci †gŠjmg~‡ni wKQz ch©vqe...Ë ag© GKB MÖæcfz3 †gŠ‡ji †P‡q cieZ©x Z...Zxq ch©vqfz3 Zv‡`i Wvbw`‡Ki †gŠ‡ji mv‡_ A_©vr, †KvYvKzwYfv‡e Aew ̄’Z †gŠ‡ji a‡g©i mv‡_ AwaKZi wgj †`Lv hvq| G `ywU ch©v‡qi g‡a ̈ †KvYvKzwY Ae ̄’v‡bi `ywU †gŠ‡ji a‡g©i mv`...k ̈‡K †gŠ‡ji KY© m¤úK© e‡j| MÖæc ch©vq 1(IA) 2(IIA) 13(IIIA) 14(IVA) 2 Li(3) Be(4) B(5) C(6) 3 Na(11) Mg(12) Al(13) Si(14) +9 +9 +9 3. wb‡Pi †KvbwU iwOb †hØM? ScCl3 MgCl2 Cu2Cl2 CoCl2 DËi: CoCl2 e ̈vL ̈v: Ae ̄’všÍi avZzmg~n iwOb †hŠM MVb K‡i| Ae ̄’všÍi avZzi Avq‡bi mvaviY B‡jKUab web ̈vm (n – 1) d1–9 4s1–2 GLv‡b, Sc3  [Ar] 3d0  k~b ̈ d AiweUvj| Mg2  1s2 2s2 2p6 3s0  d AiweUvj †bB| Cu  [Ar] 3d10  d AiweUvj c~Y©| Co2  [Ar] 3d7  d AiweUvj AvswkK c~Y© ZvB iwOb †hŠM cÖ`k©b K‡i| 4. M2+ = [(n –1 )d6 , (n = 4)], M †gØjwUi ˆewkó ̈ n‡jv- i. cÕfveK wnmv‡e KvR K‡i ii. `ywU n ̈vjvBW †hØM MVb K‡i iii. Wvqvg ̈vM‡bwUK ag© cÕ`k©b K‡i wb‡Pi †KvbwU mwVK? i I ii ii I iii i I iii i, ii I iii DËi: i I ii e ̈vL ̈v: n = 4 n‡j M 2+ = 3d6 A_©vr †gŠjwU Fe2+| M †gŠjwU Ae ̄’všÍi †gŠj nIqvq GwUi cÖfveb ÿgZv Av‡Q| Fe n ̈vjvBW A_©vr †K¬vwi‡bi mv‡_ wewμqv K‡i FeCl2 Ges FeCl3 MVb Ki‡Z cv‡i| myZivs Fe cwieZ©bkxj †hvR ̈Zv cÖ`k©b K‡i| d AiweUv‡ji B‡jKUab web ̈vm: ↿⇂ ↿ ↿ ↿ ↿ d AiweUv‡j 4 wU AhyM¥ B‡jKUab _vKvq GwU †PŠ¤^K‡ÿÎ Øviv Lye AvKwl©Z nIqvq GwU c ̈vivg ̈vM‡bwUK ag© cÖ`k©b Ki‡e| 5. N2 AYyi †ÿ‡Î †KvbwU cÕ‡hvR ̈? gy3 †Rvo B‡jKUab GKwU A‡cvjvi mg‡hvRx †cvjvi mg‡hvRx sp msKiY wewkó DËi: A‡cvjvi mg‡hvRx e ̈vL ̈v: n = 3 n‡j, N †gŠjwU n‡jv †K¬vwib (Cl)| Zvn‡j, N2 n‡‧Q †K¬vwib AYy (Cl2); hv cÖK...Zc‡ÿ GKwU A‡cvjvi mg‡hvRx AYy| 6. wb‡Pi †Kvb AvqwbKi‡Y me‡P‡q Kg kw3 jv‡M? K  K + + e– Ca  Ca+ + e– Mg  Mg+ + e– Na  Na+ + e– DËi: K  K + + e– e ̈vL ̈v: cigvYyi AvKvi e...wׇZ AvqwbKiY kw3 n«vm cvq| AvKvi Gi μg: K > Ca > Na > Mg K Gi AvKvi me‡P‡q eo nIqvi K Gi AvqwbKi‡Y me‡P‡q Kg kw3 jv‡M| 7. ch©vq mviwY‡Z †Kvb eø‡K AavZzi msL ̈v †ewk? s p d f DËi: p e ̈vL ̈v: s I d eø‡K avZzi msL ̈v †ewk| p-eø‡K AavZz m‡e©v‧P| 8. wb‡Pi †KvbwUi Mjbv1⁄4 me‡P‡q Kg? MgCl2 AlCl3 SiCl4 NaCl DËi: SiCl4 e ̈vL ̈v: SiCl4 †hŠ‡M †cvjvivqb me‡P‡q †ewk nq| dvRv‡bi bxwZ Abyhvqx †hŠ‡Mi K ̈vUvq‡bi PvR© h‡Zv †ewk H †hŠ‡Mi mg‡hvRx Z‡Zv †ewk n‡e †cvjvivqb †ewk nIqvi `iæY| mg‡hvRx ˆewkó ̈ me‡P‡q †ewk nIqvi Kvi‡Y SiCl4-G Mjbv1⁄4 me‡P‡q Kg nqÑ SiCl4-Gi K ̈vUvqb Si4+ AlCl3-Gi K ̈vUvqb Al 3+ MgCl2-Gi K ̈vUvqb Mg2+ NaCl-Gi K ̈vUvqb Na+ 9. †K›`axq cigvYyi AóK c~Y© n‡”Q- i. H2O ii. BCl3 iii. NCl3 wb‡Pi †KvbwU mwVK? i, ii ii, iii i, iii i, ii, iii DËi: i, iii e ̈vL ̈v: H H Cl B Cl Cl Cl N Cl Cl O (H2O) (BCl3) (NCl3) wPÎ n‡Z H2O AYy‡Z O Gi ewnt ͇̄i 8wU B‡jKUab BCl3 Gi B Gi ewnt ͇̄i 6wU B‡jKUab Ges NCl3 Gi N Gi ewnt ͇̄i 8wU B‡jKUab i‡q‡Q| ZvB BCl3 G AóK ms‡KvPb N‡U|