Tiêu đề Physical optics & Organic Chemistry (Full)- Daily-21 (Set-A)-With Solve.pdf ✅

2 8. 800 nm Zi1⁄2‰`‡N© ̈i GKwU Av‡jvKiwk¥ †Kv‡bv wP‡o AvcwZZ n‡j  = 30 †Z cÖ_g me©wb¤œ we›`y cvIqv †Mj| wPowUi cÖ ̄’Ñ 1.6 nm 1.6 micron 6.5  10–4 2.6  10–4 cm DËi: 1.6 micron e ̈vL ̈v: dsin  = nλ  d = nλ sin 30° = 1  800  10–9 1 2 = 1600  10–9 = 1.6  10–6 = 1.6  9. GKwU I0 ZxeaZvi mgewZ©Z Av‡jv GKwU mgeZ©K Gi ga ̈ w`‡q †Mj| D3 mgeZ©K I Zvi c~‡e©i mgeZ©‡Ki Aÿ؇qi ga ̈eZ©x †KvY 60 n‡j, wØZxq mgeZ©K n‡Z wbM©Z Av‡jvi ZxeaZv KZ? I0 I0 4 I0 5 I0 6 DËi: I0 4 e ̈vL ̈v: I = I0 cos2  = I0 cos2 (60) = I0 4 10. GKRb evjK GKwU wØ-wPo cixÿvq, wPo؇qi ga ̈eZx© `~iZ¡ 6 mm Ges wPo n‡Z c`©vi `~iZ¡ 1 m †i‡L 480 nm I 600 nm Zi1⁄2‰`‡N© ̈i Av‡jv e ̈env‡i c`v©q `ywU e ̈wZPvi Svji ˆZwi Ki‡jv| e ̈wZPvi Svji `ywUi Z„Zxq Pi‡gi ga ̈eZ©x `~iZ¡ KZ? 0.072 mm 0.72 mm 0.0072 mm †Kv‡bvwUB bq DËi: †Kv‡bvwUB bq e ̈vL ̈v: x1 = 31D a ; x2 = 32D a  x = x2 – x1 = 3D a (2 – 1)  x = 3  1 6  10–3  (600 – 480)  10–9  x = 3  120  10–9 6  10–3 = 60  10–6 m = 0.06 mm 11. GKB K¤úv1⁄4 I we ̄Ívi wewkó `ywU Av‡jvK Zi‡1⁄2i DcwicvZb NU‡jv| Gi d‡j `ywU †ÿ‡Î `kv cv_©K ̈ h_vμ‡g 0 Ges  2 | D3 `yB †ÿ‡Î ZxeaZvi AbycvZ n‡eÑ 2 : 1 1 : 2 1 : 1 3 : 1 DËi: 2 : 1 e ̈vL ̈v: awi, Zi1⁄2 `ywUi we ̄Ívi A 1g †ÿ‡Î, A1 = A 2 + A2 + 2  A  A  cos(0)  A1 = 2A 2q †ÿ‡Î, A2 = A 2 + A2  2 + A  Acos      2  A2 = 2A  A1 A2 = 2 2 = 2  I1 I2 =     A1 A2 2 [ I  A 2 ] = ( 2) 2 = 2 12. †Kvb is Gi wePz ̈wZ me‡P‡q †ewk? njy` †e ̧bx jvj Kgjv DËi: †e ̧bx e ̈vL ̈v: †e ̧bx Av‡jvi wePz ̈wZ †ewk| hvi Zi1⁄2‰`N© ̈ †ewk Zvi wePz ̈wZ Kg| Zi1⁄2‰`‡N© ̈i μgvbymv‡i †e ̧bx  njy`  Kgjv  jvj| 13. †Kvb ZË¡ Øviv Av‡jvi †eu‡K hvIqvi NUbv e ̈vL ̈v Kiv hvq? †Kvqv›Uvg ZË¡ Zi1⁄2 ZË¡ ˆØZbxwZ KYv ZË¡ DËi: Zi1⁄2 ZË¡ e ̈vL ̈v: wP‡oi ga ̈ w`‡q Av‡jvi †eu‡K hvIqvi NUbv‡K e ̈wZPvi e‡j| e ̈wZPvi nvB‡Rb Gi Zi1⁄2 ZË¡ w`‡q e ̈vL ̈v Kiv hvq| 14. †Kv‡bv iwk¥i Zi1⁄2‰`N© ̈ 400 nm n‡j, Zi1⁄2 msL ̈v KZ? 1.11  106 m –1 5  104 m –1 2  105 m –1 2.5  106 m –1 DËi: 2.5  106 m –1 e ̈vL ̈v: Zi1⁄2 msL ̈v = 1 λ = 1 400 10-9 = 109 400 = 107 4 = 0.25  107 = 2.5  106 m –1 15. †Kv‡bv GKwU c`v‡_©i Dci Av‡jv 60 †Kv‡Y AvcwZZ n‡j, cÖwZdwjZ Av‡jvK iwk¥ m¤ú~Y© mgewZ©Z nq| H c`v‡_© Av‡jvi †eMÑ 3 × 108 m/s 3 × 108 ms–1 1 3 × 108 ms–1 3 2 × 108 m/s DËi: 3 × 108 ms–1