Nội dung text Y5 Maths 5011f - 2025 Week 12 Notes.pdf
Page 2 A) REVISION 1. Problem Solving a) Problem Solving involving money Q1. Lucy has $1 125 in savings. Her brother has four times as much savings. How much money do they have together? Answer E.g. One part is 1125 . Lucy and her brother have 5 parts altogether, so 5 x 1125 = $6125 Q2. Brian’s monthly salary is $ 2 200. He spends $500 for rent, $625 to repay a car loan, $425 for food and $300 for miscellaneous expenses each month. The remainder is his savings. What is the total amount saved for one year? Answer Savings = 2200 – (500 + 625 + 425 + 300) = 2200 – 1850 = $350 b) Problem solving involving percentages Q1. A store owner paid $120 wholesale price for a suit. He needs to make a 35% profit on the sale of the suit. By how much should he markup the price of the suit to make his desired profit? Hint: Rephrase: What is 35% of $120? Answer: 27 Q2. Mr. Yang receives 10% commission on each sale that he makes. He earned $450 last week in commissions. How much were his sales? Hint: Rephrase: $450 is 10% of what number? Answer: $4500
Page 3 c) Miscellaneous problem solving The strategy for the method “Guess and Check” is to: • guess a solution • plug the guess back into the problem to see if you get the correct answer. • If the answer is too big or too small, make another guess that will get you closer to the goal, and continue guessing until you arrive at the correct solution. You can also use a strategy of using a series of equations to solve for a variable by eliminating the other/s. Question 1 Nadia takes a ribbon that is 48 metres long and cuts it in two pieces. One piece is three times as long as the other. How long is each piece? Answer: 12 and 36 Question2. Peter is outside looking at the pigs and chickens in the yard. Nadia is indoors and cannot see the animals. Peter gives her a puzzle. He tells her that he can see 13 heads and 36 feet and asks her how many pigs and how many chickens are in the yard. Help Nadia find the answer. Answer: use a system of equations. Let number of pigs = x Let number of chickens = y x + y=13 heads..............Equation 1) 4x + 2y = 36...................Equation 2 Multiply 1) by -2 -2x -2y = -26 Add this to 2) 4x - 2x +2y -2y = 36 - 26 So 2x = 10 x = 5 Substitute x = 5 into 1) gives y = 8 So Number of pigs = 5 and Number of chickens = 8