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[SOLUTION] From the formula for moisture content, ω = mm − md md ω = 1526 g − 1053 g 1053 g ω = 44.92% ▣ 8. Calculate the void ratio in percent. [SOLUTION] Se = ωGs Since it is fully saturated, S = 1. (1)e = (0.4492)(2.7) e = 121.3% ▣ 9. Calculate the porosity in percent. [SOLUTION] n = e 1 + e n = 1.213 1 + 1.213 n = 54.81% SITUATION 3. Given that the field unit weight of a soil sample is 1600 kg/m3 , the unit weight of the soil grains is 2500 kg/m3 , and the moisture content of the soil is 12%. ▣ 10. What is the void ratio of the soil sample? [SOLUTION] From the formula for moist density, ρ = ρs (1 + ω) 1 + e 1600 = (2500)(1 + 0.12) 1 + e e = 0.75 ▣ 11. What is the degree of saturation?
[SOLUTION] Solve for the specific gravity of solids Gs = ρs ρw Gs = 2500 kg/m3 1000 kg/m3 = 2.5 Se = ωGs S(0.75) = (0.12)(2.5) S = 0.40 ▣ 12. What is the dry unit weight in kg/m3 ? [SOLUTION] From the formula for the dry density, ρd = ρs 1 + e ρd = 2500 kg m3 1 + 0.75 ρd = 1428.57 kg/m3

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