Tiêu đề 9. P2C9 (Atomic Model & Nuclear Physics_With Solve_Ridoy 09.12.24.pdf ✅

cigvYyi g‡Wj I wbDwK¬qvi c`v_©weÁvb  Varsity Practice Sheet 1 MCQ weMZ mv‡j DU-G Avmv cÖkœvejx 1. nvB‡Wav‡Rb cigvYyi Avw` kw3 ̄Íi ni †_‡K P‚ovšÍ kw3 ̄Íi nf-G ̄ vbvšÍ‡ii d‡j wb¤œwjwLZ †KvbwUi †ÿ‡Î me©vwaK kw3 wbM©Z nq? [DU 23-24] ni = 80, nf = 2 ni = 1, nf = 2 ni = 3, nf = 90 ni = 2, nf = 1 DËi: ni = 2, nf = 1 e ̈vL ̈v: En = RH     1 n 2 1 – 1 n 2 2 En      1 n 2 1 – 1 n 2 2 D”P kw3 ̄Íi †_‡K wb¤œ kw3 ͇̄i †M‡j kw3 wbM©Z n‡e| 2. 27 13Al + 4 2He  30 14Si + (?) wbDK¬xq wewμqvwU‡Z Abycw ̄ Z KYvwU n‡jvÑ [DU 20-21] Avjdv KYv †cÖvUb B‡jKUab wbDUab DËi: †cÖvUb e ̈vL ̈v: 27 13Al + 4 2He  30 14Si + (27 + 4 – 30) (13 + 2 – 14)X X = 1 1H + 3. A ̈vjywgwbqvg, wnwjqvg Ges wmwjK‡bi cvigvYweK msL ̈v h_vμ‡g 13, 2 Ges 14 n‡j, 27Al + 4He  27Si + (?) wbDwK¬qvi wewμqv‡Z Abycw ̄ Z KYv †KvbwU? [DU 19-20] an  particle an electron a positron a proton DËi: Blank e ̈vL ̈v: awi, KYvwU A ZX  A = 27 + 4 – 27 = 4 Z = 13 + 2 – 14 = 1  KYvwU 4 1X 4. wb‡Pi †KvbwU f‡ii GKK bq? [DU 19-20] amu Nm–1 s 2 MeV MeV c 2 DËi: MeV 5. nvB‡Wav‡Rb cigvYyi cÖ_g †evi K‡ÿ B‡jKUa‡bi †gvU kw3 –13.6 eV| Z...Zxq †evi K‡ÿ †gvU kw3 KZ? [DU 18-19; JnU 10-11] –1.5 eV –3.4 eV –4.5 eV –40.8 eV DËi: –1.5 eV 6. GKwU wbDwK¬qvm GKwU wbDUab MÖnY K‡i, GKwU weUv KYv ( – ) wbtmiY K‡i I `yBwU Avjdv KYvq cwiYZ nq| Avw` wbDwK¬qv‡mi A Ges Z h_vμ‡g wQjÑ [DU 18-19] 6, 3 7, 2 7, 3 8, 4 DËi: 7, 3 e ̈vL ̈v: A ZX + 1 0 n  2 4 2He2+ +  – A = 4 + 4 – 1 = 7 Z = 2 + 2 – 1 = 3 7. wb‡Pi mgxKi‡Y U-235 Gi wdkvb wewμqv †`Lv‡bv n‡q‡Q| Lvwj e·wU‡Z wb‡Pi †Kvb msL ̈vwU n‡e? [DU 16-17] 235 92U + 1 0n   56Ba + 92 36Kr + 3 1 0n 141 142 143 144 DËi: 141 e ̈vL ̈v: 235 92U + 1 0 n  141 56Ba + 92 36Kr + 3 1 0 n 8. †Kv‡bv †ZRw ̄...q †g.‡ji ÿq aaæe‡Ki gvb 0.01 s–1 | Gi Aa©vqyÑ [DU 16-17] 0.693 s 6.93 s 69.3 s 693 s DËi: 69.3 s e ̈vL ̈v: T1/2 = 0.693 0.01 = 69.3 s 9. a†cv‡jvwbqvg 214Po (Z = 84) Gi -wewKi‡Yi gva ̈‡g cÖvß †g.j n‡”QÑ [DU 15-16] 214Po (Z = 84) 210Pb (Z = 82) 214At (Z = 85) 210Bi (Z = 83) DËi: 210Pb (Z = 82) e ̈vL ̈v: 214 84 Po  4 2He2+ + 210 82 Pb
2  Physics 2nd Paper Chapter-9 10. aiv hvK, Co-60 †ZRw ̄...q c`v‡_©i Aa©vqy 5 ermi| KZ ermi c‡i H †ZRw ̄...q c`v‡_©i †ZRw ̄...qZv K‡g cÖv_wgK Ae ̄ vi 1 32 †Z n«vm cv‡e? [DU 14-15] 10 years 16 years 25 years 32 years DËi: 25 years e ̈vL ̈v: nT1/2 mgq ci 1 2 n Ask Aewkó _v‡K| GLv‡b, 1 32 = 1 2 5  n = 5 cÖ‡qvRbxq mgq = nT1/2 = 5  5 = 25 years 11. wb‡¤œi †KvbwU GKwU wbDK¬xq wdDkb wewμqv cÖ`k©b K‡i †hwU †_‡K cÖPzi cwigv‡Y kw3 Drcvw`Z nq? [DU 14-15] 238 92U  234 90Th + 4 2He 3 1H + 2 1H  4 2He + 1 0 n 236 92U  141 56Ba + 92 36Kr + 31 0 n 24 11Na  24 12Mg + 1 0 e DËi: 3 1H + 2 1H  4 2He + 1 0 n 12. GKwU nvB‡Wav‡Rb cigvYy D‡ËwRZ Ae ̄ v †_‡K wb¤œZi kw3 ͇̄i Avm‡j †h †dvUb wbtmiY Ki‡e Zvi Zi1⁄2‣`N© ̈ KZ n‡e? D‡ËwRZ kw3 ̄Íi Ges wb¤œZi kw3 ͇̄ii kw3 h_vμ‡g –3.4 eV Ges –13.6 eV| (†`Iqv Av‡Q, cø ̈v1⁄4 aaæeK, h = 6.63  10–34 Js, Av‡jvi †eM c = 3.0  108 ms–1 )| [DU 13-14] 1.95  10–26 m 1.21  10–7 m 1.0  10–7 m 0.15 m DËi: 1.21  10–7 m e ̈vL ̈v:  = hc E2 – E1 = 6.63  10–34  3  108 (– 3.4 + 13.6)  1.6  10–19  6.4  10–34  3  108 10  1.6  10–19  4  3  10–34 + 8 + 19 –1  12  10–8  1.2  10–7 m 13. 214 83Bi AvB‡mv‡Uvc n‡Z GKwU Avjdv KYv wbtmiY Gi d‡j †cÖvWv± AvB‡mv‡Uvc n‡eÑ [DU 13-14] 210 79Au 210 81Tl 210 89Bi 210 85At DËi: 210 81Tl e ̈vL ̈v: 214 83Bi  4 2He2+ + 210 81Tl weMZ mv‡j GST-G Avmv cÖkœvejx 1. †iwWqv‡gi Aa©Rxeb 1590 eQi| Gi Mo Rxeb KZ eQi? [GST 23-24] 2294 2290 2300 2304 DËi: 2294 e ̈vL ̈v:  = T1/2 0.693 = 1590 0.693 = 2294 2. †Kv‡bv GKwU †h.‡Mi g‡a ̈ GKB Dcv`v‡bi wKQz †ZRw ̄...q c`v_© we` ̈gvb| †ZRw ̄...q c`v‡_©i Aa©vqy 25 eQi| 100 eQi ci H †ZRw ̄...q c`v‡_©i KZ Ask Aewkó _vK‡e? [GST 22-23] 1 4 1 8 1 12 1 16 DËi: 1 16 e ̈vL ̈v: 1 2 n Ask Aewkó _v‡K nT1/2 mgq ci  100 = n  25  n = 4  Aewkó _vK‡e = 1 2 4 = 1 16 3. wbDwK¬qvi eÜb kw3 n‡jv ____ wbDwK¬qv‡m GK‡Î †eu‡a ivLvi kw3Ñ [GST 22-23] †cÖvUb I wbDUabmg~n‡K B‡jKUab I wbDwK¬qbmg~n‡K ïaygvÎ wbDUabmg~n‡K ïaygvÎ †cÖvUbmg~n‡K DËi: †cÖvUb I wbDUabmg~n‡K 4. wbDwK¬qvi wdkb wewμqvq wbM©Z kw3 n‡jvÑ [GST 22-23] †ZRw ̄Œq wbDwK¬qv‡mi eÜbkw3 wdkb fMœvsk I wbDUa‡bi MwZkw3 wbDUa‡bi wefekw3 ïaygvÎ wdkb fMœvs‡ki MwZkw3 DËi: †ZRw ̄Œq wbDwK¬qv‡mi eÜbkw3 5. GKwU nvB‡Wav‡Rb cigvYy D‡ËwRZ Ae ̄ v †_‡K f‚wg Ae ̄ vq wd‡i Avm‡jÑ [GST 20-21] †dvUb †kvlY K‡i †dvUb wbtmiY K‡i kw3 †kvlY K‡i AvqwbZ nq DËi: †dvUb wbtmiY K‡i 6. †Kvb iwk¥/KYvi †f`bÿgZv me‡P‡q †ewk? [GST 20-21] Avjdv G·-†i Mvgv weUv DËi: Mvgv
cigvYyi g‡Wj I wbDwK¬qvi c`v_©weÁvb  Varsity Practice Sheet 3 weMZ mv‡j Agri-G Avmv cÖkœvejx 1. †m.ikw3 †Kvb c×wZ‡Z m„wó nq? [Agri. Guccho 20-21, 19-20; RU 17-18; BU 14-15; BRUR 14-15; DU 13-14; KU 13-14, 08-09] Fission (wdkb) Induced Fission (Av‡ewkZ wdkb) Chemical Reaction (ivmvqwbK wewμqv) Fusion (wdDkb) DËi: Fusion (wdDkb) 2. 1 kg f‡ii †ZRw ̄...q †g.‡ji GKwU e ̄‧i g‡a ̈ 48 w`b ci H †g.‡ji gvÎ 0.25 kg cvIqv hvq| †g.jwUi Aa©vqy KZ? [Agri. Guccho 20-21] 24 days 12 days 36 days 72 days DËi: 24 days e ̈vL ̈v: nT1/2 mgq ci 1 2 n Ask Aewkó _v‡K| Aewkó = 0.25 1 = 1 4 = 1 2 2 Ask; n = 2  Aa©vqy = 48 2 = 24 days weMZ mv‡j JU-G Avmv cÖkœvejx 1. GKwU †ZRw ̄...q AvB‡mv‡Uv‡ci 200 MÖvg f‡ii GKwU bgybvi Aa©-Rxeb 20 eQi| 60 eQi †cwi‡q †M‡j Avmj AvB‡mv‡Uv‡ci KZUzKz Aewkó _vK‡e? [JU 22-23] 3.3 MÖvg 10 MÖvg 25 MÖvg 48 MÖvg DËi: 25 MÖvg e ̈vL ̈v: 200 20 100 20 50 20 25 MÖvg 2. 1 amu f‡ii mgZzj ̈ kw3 †KvbwU Øviv cÖKvk Kiv hvqÑ [JU 21-22; BSFMSTU-A 19-20] 934 J 934 MeV 934 eV 934 kg DËi: 934 MeV 3. weUv ÿq nq †Kvb e‡ji Kvi‡Y? [JU 21-22] mej wbDK¬xq `ye©j wbDK¬xq Zwor Pz¤^Kxq gnvKl© DËi: `ye©j wbDK¬xq 4. wUawUqv‡gi Aa©Rxeb 12.5 eQi| 25 eQi ci GKwU wbw`©ó wUawUqvg e ̄‧L‡Ûi KZ Ask Aewkó _vK‡e? [JU 20-21; Agri. Guccho 19-20; IU 15-16] 1 8 1 6 1 4 1 2 DËi: 1 4 e ̈vL ̈v: nT1/2 mgq ci 1 2 n Ask Aewkó _v‡K| nT1/2 = t  n  12.5 = 25  n = 2  Aewkó _vK‡e = 1 2 n = 1 4 Ask| 5. †Kvb ai‡bi †ZRw ̄...q iwk¥ gvby‡li Rb ̈ me‡P‡q wec3⁄4bK? [JU 20-21] Avjdv weUv Mvgv †Kv‡bvwUB bq DËi: Mvgv e ̈vL ̈v: Mvgv iwk¥i †f`b ÿgZv me©vwaK e‡j †Kvl ÿwZMÖ ̄’ nq †ewk| 6. wb‡Pi †KvbwU AvB‡mv‡Uv‡bi D`vniY? [JU 19-20] 32 15P 14 6C 40 20Ca 39 19K DËi: Blank e ̈vL ̈v: †h mKj cigvYy‡Z mgvb msL ̈K wbDUab Av‡Q Zv‡`i‡K AvB‡mv‡Uvb e‡j| 7. GKwU 23 11Na Gi cvigvYweK fi 22.989770 wKš‧ Ab ̈ w`‡K 238 92U Gi cvigvYweK fi 238.050784| KviYÑ [JU 19-20] Df‡qiB AvB‡mv‡Uvc i‡q‡Q 238 92U Gi AvB‡mv‡Uvc 23 11Na GKwU †ZRw ̄Œq c`v_© †Kv‡bvwUB bq DËi: Df‡qiB AvB‡mv‡Uvc i‡q‡Q e ̈vL ̈v: AvB‡mv‡Uvc _vKvq Av‡cwÿK cvigvYweK fi wnmve Kiv n‡”Q| 8. 86A 222  82A 206 + 8 0n 1 + () GB wewμqvq KqwU  KYv †ei n‡e? [JU 18-19] 0 2 4 16 DËi: 0
4  Physics 2nd Paper Chapter-9 9. 12 6C Ges 13 6C Kve©‡bi `ywU AvB‡mv‡Uvc nIqvq G‡`i ivmvqwbK wewμqvÑ [JU 17-18] †ek wfbœ cÖvq mgvb mgvb wØZxq AvB‡mv‡UvcwU wewμqv wbi‡cÿ DËi: cÖvq mgvb 10. GKwU B‡jKUab hw` E2 kw3 ̄Íi †_‡K E1 wb¤œ kw3 ͇̄i Mgb K‡i, Zvn‡j weKxY© kw3i Zi1⁄2‣`N© ̈ n‡eÑ [JU 17-18] E2 – E1 hc hc E2 – hc E1 c h (E2 – E1) hc E2 – E1 DËi: hc E2 – E1 e ̈vL ̈v: hc  = E2 – E1   = hc E2 – E1 11. weUv iwk¥i KwYKvi fiÑ [JU 16-17] B‡jKUa‡bi f‡ii mgvb B‡jKUa‡bi f‡ii wØ ̧Y †cÖvU‡bi f‡ii mgvb †cÖvU‡bi f‡ii wØ ̧Y DËi: B‡jKUa‡bi f‡ii mgvb 12. GK LÐ †iwWqvg 4000 eQi †ZRw ̄...q wewKiY K‡i GK-cÂgvs‡k cwiYZ n‡j †iwWqv‡gi Aeÿq aaæeK wKfv‡e †jLv hvq? [JU 16-17] 1 5 = e–4000 5 = e–4000 1 5 = e –  4000 †Kv‡bvwUB bq DËi: 1 5 = e–4000 e ̈vL ̈v: N = N0e –t  1 5 = e–4000 13. wbDUab Øviv AvNvZ K‡i hw` †Kvb fvix cigvYyi wbDwK¬qvm‡K cÖvq mgfi wewkó `ywU AYy‡Z wef3 Kiv nq, Zvn‡j Zv‡K e‡jÑ [JU 16-17] wdkb wdDkb wWwdDkb †Kv‡bvwUB bq DËi: wdkb 14. †Kvb cigvYy †_‡K wbtm„Z wewKi‡Yi Zi1⁄2‣`N© ̈ 3315  10–10 m| †h `ywU kw3 ͇̄ii g‡a ̈ GB wewKiY nq Zv‡`i kw3i cv_©K ̈ n‡eÑ [JU 15-16] 3.75 eV 2.75 eV 6.75 eV †Kv‡bvwUB bq DËi: 3.75 eV e ̈vL ̈v: E2 – E1 = hc  = 6.63  10–34  3  108 3315  10–10 = 6.63  10–34  3  108 3.315  10–7 = 2  10–27  3  108 = 6  10–19 J = 6  10–19 1.6  10–19 eV = 60 16 eV = 15 4 eV = 3.75 eV 15. weUv iwk¥ m¤ú‡K© †KvbwU mwVK? [JU 14-15] abvZ¥K PvR©hy3 FYvZ¥K PvR©hy3 PvR© wbi‡cÿ we`y ̈r‡ÿÎ Øviv wewÿß nq bv DËi: FYvZ¥K PvR©hy3 e ̈vL ̈v: (– ve) charge, †h‡nZz  iwk¥ GKwU e – | 16. Mvgv iwk¥ m¤ú‡K© †KvbwU mwVK? [JU 14-15] ab PvR©hy3 FY PvR©hy3 PvR© wbi‡cÿ †P.¤^K †ÿÎ Øviv wewÿß nq DËi: PvR© wbi‡cÿ weMZ mv‡j RU-G Avmv cÖkœvejx 1. †Kvb cigvYyi wbDwK¬qv‡m wbDUab †bB? [RU 23-24, 20-21] 2 1H 3 1H 1 1H †Kv‡bvwUB bq DËi: 1 1H 2. nvB‡Wav‡Rb cigvYy‡Z GKwU B‡jKUab 2q kw3 ̄Íi †_‡K 1g kw3 ͇̄i Ae ̄ všÍ‡ii wewKiY K¤úv1⁄4 KZ? [RU 23-24] 1.50RH 2.25RH 0.75RH 3.00RH DËi: Blank e ̈vL ̈v: 1  = RH ×     1 1 2 – 1 2 2  c  = c × RH × 4 – 1 4 = 3 4 RH × c  f = 0.75 RH × c Note: Option G RH Gi mv‡_ c ̧Y n‡e|