Tiêu đề 07. ALTERNATING CURRENT(H).pdf ✅

NEET REVISION 07. ALTERNATING CURRENT(H) NEET REVISION Date: March 18, 2025 Dura on: 1:00:00 Total Marks: 180 INSTRUCTIONS INSTRUCTIONS PHYSICS 1. In the circuit shown in figure neglecting source resistance the voltmeter and ammeter reading will respectively be [Q355958] (1) (2) (3) (4) 2. Consider the circuit shown in figure given below and match the columns. Column I Column II A. For P. Current leads the voltage B. For Q. The current and voltage in circuit are in same phase C. For R. Voltage leads the current [Q355940] (1) A - Q, B - P, C - R (2) A - P, B - Q, C - P (3) A - P, B - R, C - Q (4) A - R, B - P, C - Q 3. In the circuit shown in fig. If both the bulbs and are identical, [Q355861] (1) will be brighter than (2) Their brightness will be the same (3) will be brighter than (4) Only will glow be- cause the capacitor has infinite impedance 4. In an series circuit, if the angular fre‐ quency is gradually increased then match the fol‐ lowing columns [Q356237] (1) (2) (3) (4) 5. The average and effective values for the wave shape shown in the figure are: [Q356092] 0 V , 8 A 150 V , 3 A 0 V , 3 A 150 V , 6 A ω = 5, 000 rad/ sec ω = 2, 500 rad/ sec ω = 10, 000 rad/ sec B1 B2 B1 B2 B2 B1 B2 LCR A − P, B − R, C − S, D − Q A − S, B − P, C − Q, D − R A − P, B − S, C − Q, D − R A − Q, B − R, C − P, D − S
NEET REVISION (1) and (2) and (3) and (4) and 6. A sinusoidal voltage is ap‐ plied across a pure inductance of . The current through the coil:- [Q355888] (1) (2) (3) (4) 7. In a series circuit, resistance and the impedance . The phase difference between the current and the voltage is [Q355938] (1) (2) (3) (4) 8. Given below are two statements: Statement-I: The reactance of an ac circuit is zero. It is possible that the circuit contains a ca‐ pacitor and an inductor. Statement-II : In ac circuit, the average power delivered by the source never becomes zero. In the light of the above statements, choose the correct answer from the above statements, choose the correct answer from the options given below: [Q356186] (1) Both Statement I and Statement II are true. (2) Both Statement I and Statement II are false. (3) Statement I is true but Statement II in false. (4) Staement I is false but Statement II is true. 9. When 100 volt is applied across a coil, a current of flows through it. When 100 volt at is applied to the same coil, only 0.5 ampere current flows. The impedance of the coil is [Q355891] (1) (2) (3) (4) 10. What will be the reading in the voltmeter and ammeter of the circuit shown ? [Q355972] (1) (2) (3) (4) 11. A series circuit with inductance 10 , ca‐ pacitance , resistance is conencted to an source of voltage, . If the resonant frequency of the circuit is and the frequency of the soruce is , then [Q356236] (1) (2) (3) (4) 12. An source of angular frequency is fed across a resistor and a capacitor in series. The current registered is I. If the frequency of source is changed to (maintaining the same voltage), the current in the circuit is found to be halved. Calculate the ratio of reactance to resis‐ tance at the original frequency [Q355984] (1) (2) (3) (4) 13. Primary side of a transformer is connected to supply. Turns ratio of primary to secondary winding is . Load resistance connected to secondary side is The power consumed in it is: [Q356321] (1) (2) (3) (4) 14. For the circuit shown in figure, the current in the inductance is 0.8 while in the capacitance is 0.6 . What is the current drawn from the source ? [Q355863] (1) (2) (3) (4) 15. In a transformer primary voltage is and secondary current is with output power [Q356310] (1) Transformer is step up (2) Transformer is step down (3) Transformer is auxiliary (4) None of these Vm 2 π Vm 2 Vm π Vm √2 Vm 2 π Vm √2 Vm π√2 Vm √2 V (t) = 100 sin(500t) L = 0.02H 10 cos(500t) −10 cos(500t) 10 sin(500t) −10 sin(500t) L − C − R R = 10Ω Z = 10Ω 0 ∘ 30 ∘ 45 ∘ 60 ∘ DC 1 amp AC 50 c/s 300Ω 100Ω 400Ω 200Ω 90V , 2A 0V , 2A 90V , 1A 0V , 1A LCR H 10μF 50Ω ac V = 200 sin(100 t) volt LCR v0 ac v vo = v = Hz 50 π vo = Hz, v = 50 Hz 50 π v = 100 Hz; vo = Hz 100 π vo = v = 50 Hz ac ω r C ω/3 ω √ 4 5 √ 2 5 √ 3 5 √ 1 5 230 V , 50 Hz 10 : 1 46 Ω. 10.0 W 11.5 W 12.5 W 12.0 W A A 0.2 A 0.7 A 0.5 A 0.3 A 220 V 0.11 A 60 W