Tiêu đề 24.12.23_SR.STAR CO-SC(MODEL-A,B_C)_Jee_Main_GTM-2_KEY_SOL.pdf ✅

Sec: SR.IIT_*CO-SC(MODEL-A,B&C) GTM-2 Date: 24-02-23 Time: 3 HRS JEE-MAIN Max. Marks: 300 KEY SHEET PHYSICS 1 B 2 B 3 D 4 A 5 A 6 D 7 D 8 B 9 C 10 A 11 A 12 C 13 B 14 A 15 C 16 B 17 B 18 B 19 A 20 C 21 15 22 3 23 2 24 3 25 3 26 2 27 4 28 3 29 8 30 0 CHEMISTRY 31 B 32 D 33 A 34 A 35 D 36 D 37 D 38 D 39 A 40 C 41 D 42 A 43 D 44 C 45 C 46 D 47 A 48 B 49 D 50 A 51 3 52 4 53 5 54 1 55 5 56 9 57 8 58 9 59 6 60 6 MATHEMATICS 61 B 62 A 63 A 64 C 65 B 66 B 67 B 68 D 69 C 70 C 71 B 72 A 73 C 74 A 75 B 76 C 77 C 78 B 79 B 80 B 81 5 82 11 83 2 84 0 85 90 86 2 87 540 88 3 89 18 90 1
Narayana IIT Academy 24-12-23_SR.IIT_*CO-SC(MODEL-A,B&C)_JEE-MAIN_GTM-2_KEY&SOL SR.IIT_*CO-SC Page NO: 2 SOLUTIONS PHYSICS 1. Given velocity in x-direction 2 / x v m s  Acceleration   8 2 . 8 / E e m e a j jm s m e m               1 , 2 x d time t s v    Now 1 2 . 2 y y a t  y y y v u a t   1 0 8 4 / 2 y v m s     Now 4 / tan 2 2 / y x v m s v m s       1  tan 2   2. In the diagram balance all the forces 3. 0 2 i B d       7 4 10 100 2 3.14 4        6 B T 5 10   (Southwards) 4.   2 1       MB cos cos   0 0 cos60 cos 0 2 MB     MB 0 0 Torque MB   sin 60 2 .sin 60   3
Narayana IIT Academy 24-12-23_SR.IIT_*CO-SC(MODEL-A,B&C)_JEE-MAIN_GTM-2_KEY&SOL SR.IIT_*CO-SC Page NO: 3 5. 3 2 L L    B xdx  5 2 . 2    B l 6. 1 0   283 , 320 v s    2 2 7 L C z R X X      1 0 tan 45 X X L C R            7. Conceptual 8.     2 max 1 2 2 min 1 2 I I I I I I     Simplifying the required answer will be 2 9. Using 2 2 13.6 n z E ev n       2 1 2 3 13.6 122.4 1 E ev ev         2 3 2 3 13.6 13.6 3 E ev ev       E ev 108.8 10. Conceptual 11. Vernier constant = Least count = 1 , 10 MSD    1 1 20 cm MSD  12.   2 max 10 ....... 1 2 u H m g     2 0 max 20 , 45 u R m angle of projection g     13. 2 com I I md   2 2 2 6 2 2 3 mL L m I ml         
Narayana IIT Academy 24-12-23_SR.IIT_*CO-SC(MODEL-A,B&C)_JEE-MAIN_GTM-2_KEY&SOL SR.IIT_*CO-SC Page NO: 4 14. Energy     3 2 R R   TE TE 3 2 6 GmM GmM R R GmM Energy R           15. . DV P B V   8 2  6 10 / N m 16. Alongbc   w 0 60 180 60 120 250 250 120 130 Q V J Along ab u J also Q J So w J               Hence 130 0 130       w w J ab bc 17. 2 V fR C  1 2 2 P V P P V C C R fR f C R CV R R C C                 18.   2 T , 3      19.  2 1 1 2 . 0 2 2 2 mm v kx m    20. Energy lost = Energy utilised for rise in temperature. 21. c F a z  FBD of Kg 1 1 3 F f  