Tiêu đề Motion of Particles Varsity Practice Sheet Solution.pdf ✅

4  Higher Math 2nd Paper Chapter-9 9. GKwU ͇̄¤¢i P~ov n‡Z 5 ms–1 †e‡M Avbyf~wgK w`‡K wbwÿß GKwU ej ͇̄¤¢i cv`‡`k n‡Z 20 wgUvi `~‡i gvwU‡Z c‡o| ͇̄¤¢i D”PZv KZ? [JU 14-15] 78.4 m 78.0 m 68.4 m 80.4 m DËi: 78.4 m e ̈vL ̈v: x = ut  20 = 5t  t = 4 s  h = 1 2 gt2 = 1 2  9.8  4 2 = 78.4 m 10. †Kv‡bv KYvi Dci GKB mg‡q GKB w`‡K wμqvkxj `yBwU †eM 12 ms–1 Ges 5 ms–1 n‡j, Zv‡`i jwä †eM KZ? [JU 14-15] 12 ms–1 16 ms–1 17 ms–1 10 ms–1 DËi: 17 ms–1 e ̈vL ̈v: GKB w`‡K wμqvkxj n‡j jwä, w = u + v = 12 + 5 = 17 ms–1 Note: wecixZ w`‡K wμqvkxj n‡j jwä, w = u – v; u > v 11. GKwU aaæeK ej 40 †KwR f‡ii GKwU e ̄‘i Dci w ̄’ive ̄’v n‡Z 6 †m‡KÛ wμqv K‡i 18 ms–1 †e‡Mi m„wó K‡i| e‡ji cwigvY KZ? [JU 14-15] 120 N 110 N 210 N 100 N DËi: 120 N e ̈vL ̈v: F = ma = m v t = 40  18 6 N = 120 N weMZ mv‡j RU-G Avmv cÖkœvejx 1. 20 ms–1 †e‡M EaŸ©Mvgx †Kv‡bv †ejyb †_‡K cwZZ GK UzKiv cv_i 20 †m‡KÛ c‡i gvwU‡Z coj| cv_‡ii UyKiv cwZZ nIqvi mgq †ejy‡bi D”PZv KZ wQj? [RU 23-24, 14-15; DU 10-11] 390 m 560 m 12580 m 1560 m DËi: 1560 m e ̈vL ̈v: h = – ut + 1 2 gt2 = ( – 20  20) + 1 2  9.8  202 = 1560 m 2. 98 ms–1 Avw`‡e‡M Ges f~wgi mv‡_ 30 †Kv‡Y GKwU e ̄‘ wb‡ÿc Kiv n‡jv| e ̄‘wUi ågYKvj †KvbwU? [RU 23-24] 1 s 10 s 5 s 12 s DËi: 10 s e ̈vL ̈v: T = 2usin g = 2  98  1 2 9. = 10 s 3. 12 ms–1 †e‡Mi `yB cv‡k¦© 30 I 60 †Kv‡Y wμqviZ AskKØq KZ ms–1 ? [RU 23-24] 6 3, 6 6, 6 2 24, 24 3 24 2, 24 DËi: 6 3, 6 e ̈vL ̈v: 30 60 V2 V1 12 ms –1 V1 = 12cos30 = 6 ms–1 V2 = 12cos60 = 6 3 ms–1 4. w ̄’i Ae ̄’v n‡Z GKwU e ̄‘ 4 ms–2 mgZ¡i‡Y Pj‡Z _vK‡jv| mßg †m‡K‡Û GwU KZ wgUvi `~iZ¡ AwZμg Ki‡e? [RU 22-23] 13 39 52 26 DËi: 26 e ̈vL ̈v: s = u + 1 2 a(2t – 1)  s = 0 + 1 2  4(2  7 – 1)  s = 2(14 – 1) = 26 m 5. k~‡b ̈ wbwÿß GKwU cv_i L‡Ði me©vwaK cvjøvi gvb 40 wgUvi| cv_‡ii me©vwaK D”PZv KZ wgUvi? [RU 22-23] 20.1 20 21 21.5 DËi: mwVK DËi †bB e ̈vL ̈v: tan = 4H R  tan45 = 4H 40 [⸪ me©vwaK cvjøvi Rb ̈  = 45 nq]  H = 10 m  mwVK DËi †bB| Shortcut: tan = 4H R = gT2 2R