Tiêu đề Grade 11 - Answer sheet.pdf ✅

Page 2 69. 70. 71. 5a3 73. 26 . 3 = 1.42 74. . >k jia;=j, j3⁄4.M,h iy mßudj 75. .re' 100,000 76. we, Wi = 14, wrh= 3.5 77. a 2 + 2ax 78. i. 10 ii. 500 ml 79. 6 cm2 80. 570.43 cm3 81. i. 905.14 cm 3 ii. 9084 cm 3 ,54.14 kg 82. i. 2425.5 cm3 ii. 15.75 cm 83. w) 1188 cm2 wd) 84 84. w) 565 5 7 cm3 wd) r = 3 10 85. w) 1584 cm2 wd) = 7√2 86. w) 3696 cm2 wd) r = 7 87. w) i. 450cm2 ii. 38.5cm2 iii. 411.5cm2 wd) i. 1350cm3 ii. 42 88. i. 154cm2 ii. 12cm iii. 21067.2 g iv. 16cm2 89. w) i. 81.5 m2 ii. 489.0 m3 wd) i. 511.5cm2 ii. 120 90. i. 2940 cm2 ii. 1722 cm2 iii. 1.395 g iv. n = 8 91. i. 429 cm2 ii. 89.83 cm3 iii. 256.67 cm3 iv. h = 6.6 cm 92. w) i. 76 m ii. 203 m2 iii. 192.5 m3 93. w) i. 20.8 cm ii. 14 cm2 wd) i. 4200cm ii. 29700 cm3 iii. 29.7 l iv.ñk s;a;= 15 94. i. 1617 cm2 ii. 9702 cm3 95. w) i. 6600 cm2 ii. 2200 cm2 iii. 1232 cm2 wd) i. 61600 cm3 ii. 55.44 kg 96. w) i. 58 cm2 ii. 96 cm2 iii. 42.72g wd) 756 97. a) i. 24 ii.144 cm2 7.2 m2 b) i. 264 cm3 ii. 63 98. a) i. 20 m ii. 30 m iii. 300 m2 b) i. r = 7 cm (wrh) ii. 704 cm2 iii. 1232 cm3 99. w) i. 784 wd) i. 31 cm ii. 5852 cm3 iii.29.26 100. i. 718.67 cm3 ii. 1540 cm3 iii. 821 2 3 cm3 101. i. 1 4 ii. BC = 9.9 cm iii. 14 cm2 iv. 7l 102. w) i. 297 cm3 ii. 2079 cm3 wd) 12 cm 103. w) i. 3.75 cm ii. 3.14 × (3.75) 2 × 20.6 cm2 iii. 909 cm2 wd) fl a;=fõ Wi = 3 × is,sk avrfha Wi tkï fla;= fõ Wi is,sk avrfha Wi fuk a ;=ka .=Khl s' 104. w) i. 2r ii. 3r wd) I) 2 3 πr3 ii. fl a;=fõ mßudj iy w3⁄4O f.da,fha mßudj iudk fõ' iii. 4 3 πr3 iv. 4 3 πr3 v 2572 cm3 we) fuu mrsudj iudk mßudjla we;s f.da,fha wrh = 8.5 cm lg (√ 0.0463 1.082 × 34.83) = 1 2 lg 0.0463 + lg 34.83 − 2 lg 1.08 1 2 2̅ . +1.5420 − 2 × 0.0334 1̅ . 3328 + 1.5420 − 0.0668 0. 8748 − 0.0668 = 0.8080 √ 0.0463 1.082 × 34.83 = 6.428 fyda 6.427 x = 1.52 × √415 lg x = lg 1.52 + 1 2 lg 415 = 0.1818 + 1 2 × 2.6180 = 0.1818 + 1.3090 = 1.4908 ; x = antilog 1.4908 = 30.95 fyda 30. 96 72. A = √5 3 0.871 lg A = 1 3 lg 5 − lg(0.871) = 1 3 (0.6990) − (1̅. 9400) = 0.2330 − (1̅. 9400) = 0.2930 A = antilog (0.2930) = 1.963 A = √65.2 ×0.722 3.06 lg A = 1 2 lg 65.2 × lg 0.722 − lg 3.06 lg A = 1 2 × 1.8142 + 1̅. 8585 − 0.4857 lg A = 0.9071 + 1̅. 8585 − 0.4857 lg A = 0.7656 − 0.4857 lg A = 0.2799 lg A = Antilog 0.2799 A = 1.905 A = 1.91
Page 3 w) i. 24 cm2 ii. 528 cm3 wd) i. πr 2h = 540 ii. h = 540 πr 2 iii. h = 31.73 cm 105. . 106. . 107. 108. . 109. . 110. . 111. . 112. . w) i. 2πrh + 2πr 2 2πr + 2r + 2πr 2 6πr 2 ii. r = 2 wd) a 3 = r 3h 16 22 cm 8 cm a) i. 4a ii. 2 3 πa 3 cm iii. 2πa 3 cm3 b) i. ;yvQfõ mßudj = l =i,dkfha mßudj ksid 2x 2 = 2πa 3 x 2 = πa 3 ii. 7223 iii. 85 cm i. >kldNfha mßudj = 10.86 × 10.86 × 0.85 cm2 f.d a, 3 mßudj = 3 × 4πr 3 3 r = q 3 × 4πa 3 3 = 10. 862 × 0.85 a 3 = 10.862 ×0.85 4π ii. a 3 = 10.862 ×0.85 12.55 a 3 = 2 ,>q 10.86 + ,>q 0.95 − ,>q 12.55 = 2 × 1.0359 + 1̅. 9294 − 1.0986 = 2.0718 + 1̅. 9294 − 1.0986 = 2.0012 − 1.0986 = m%' ,' 0.9026 = 7.991 iii. a 3 = 8 a = 2 3 a = 2 cm i. j3⁄4.M,h = 20 × 14 = 280m2 ii. πr 2 = 22 7 × 7 × 7 = 154 cm2 iii. 20 m 7 m 1 m 4 m 14 m 7 m 8 m X 5 m iv. 4 × 4 = 16 m2 v. 154 m2 + 16 m2 = 170 m2 280 − 170 = 110 m2 ( ;K ìu i`oyd ) vi. x 2 = 5 2 + 8 2 = 25 + 64 x = √89 iii. h = 24 × (1.75) 3 49 log h = log 24 + log 1.75 − log 49 = 1.3802 + 3 × 0.2430 − 1.6902 = 1.3802 + 0.7290 − 1.6902 = 2. 1092 − 1.6902 = antilog 0.4190 = 2.624 cm i. c, mßudj = πr 2h = 22 7 × 7 × 7 × 10 = 1540 cm2 ii. 4 3 πr 3 = 4 3 πa 3 18 × 4 3 πa 3 = π × 7 × 7 × h 24 a 3 = 49 h h = 24a 3 49 cm i. ùÿrefõ c, mßudj = 1 3 πr 2h = 1 3 π × r 2 × 12 = 4 πr 2 ii. a × a × b = 4 πr 2 b × a 2 = 4 πr 2 a 2 = 4 πr 2 b iii. a 2 = 4 πr 2 b = 12.56 ×9.572 18 log a 2 = log 12.56 + log 9. 572 − log 18 log a 2 = 1.0990 + 2 × 0.9809 − 1.2553 log a 2 = 1.0990 + 1.9618 − 1.2553 = 3.0508 − 1.2553 = antilog 1.8055 a 2 = 63.90 = 64 a = 8 cm i. wkq,df.a fldgi ;%sfldaKhl s' lu,df.a fldgi ;%mSishuls' ii. wkq,df.a = 1 2 × 80 × 80 = 3200 m2 iii. lu,df.a fldgfia j'M,h = 1 2 × 80 (100 + 20) = 40 × 120 = 4800 m2 wkq,d ( lu,d 3200 ( 4800 32 ( 48 2 ( 3 80 m 32 m 3200 m2 4800 48 m m2 100 m iv. v. 20m