Tiêu đề 1. Che. Varsity Practice Sheet (2nd Paper) With Solve.pdf ✅

cwi‡ek imvqb  Varsity Practice Sheet ............................................................................................................................ 1 MCQ weMZ mv‡j DU-G Avmv cÖkœvejx 1. wb‡Pi †Kvb †ÿ‡Î e ̈vcb me©vwaK n‡e? [DU 22-23] 5C-G Kve©b g‡bvA·vBW 35C-G Kve©b g‡bvA·vBW 5C-G wbqb 35C-G wbqb DËi: 35C-G wbqb e ̈vL ̈v: e ̈vcb nvi, r  1 M A_©vr, M ̈v‡mi e ̈vcb nvi H M ̈v‡mi AvYweK f‡ii eM©g~‡ji e ̈ ̄ÍvbycvwZK| AvYweK fi hZ †ewk n‡e M ̈v‡mi e ̈vcb nvi ZZ Kg n‡e| Avevi, ZvcgvÎv †ewk _vK‡j e ̈vc‡b AskMÖnYKvix AYy ̧‡jvi MwZkw3 †e‡o hvq ZvB M ̈v‡mi e ̈vcb nvi †e‡o hvq| G Kvi‡Y 35C ZvcgvÎvq Ne Gi e ̈vcb me©vwaK n‡e| 2. ev ̄Íe M ̈v‡mi †ÿ‡Î f ̈vbWvi Iqvjm mgxKi‡Y ÔaÕ aaæeKwU wb‡`©k K‡iÑ [DU 22-23; CU 11-12, 08-09; MBSTU 16-17] MwZkw3 AvšÍtAvYweK AvKl©Y AvqZb msbg ̈Zv DËi: AvšÍtAvYweK AvKl©Y e ̈vL ̈v: ev ̄Íe M ̈v‡mi f ̈vbWvi Iqvjm mgxKiY:     P + n 2 a V 2 (V – nb) = nRT GLv‡b, ÔaÕ aaæeKwU AvšÍtAvYweK AvKl©Y wb‡`©k K‡i| ÔaÕ Gi gvb †ewk n‡j M ̈vm AYy ̧‡jvi AvšÍtAvYweK AvKl©Y †ewk nq| 3. GKwU Av`k© M ̈v‡mi Rb ̈ PV ebvg 1 P †jLwPÎ n‡e GKwUÑ [DU 21-22] †Q`Kmn mij‡iLv Awae„Ë X-A‡ÿi mgvšÍivj mij‡iLv g~jwe›`yMvgx mij‡iLv DËi: X-A‡ÿi mgvšÍivj mij‡iLv e ̈vL ̈v: e‡q‡ji m~Îvbymv‡i, w ̄ i ZvcgvÎvq PV = aaæeK ZvB PV ebvg 1 P Gi †jLwPÎ n‡e X-A‡ÿi mgvšÍivj mij‡iLv| PV 1 P 4. nvB‡Wav‡Rb M ̈v‡mi e ̈vc‡bi nvi †Kv‡bv GKwU M ̈v‡mi e ̈vc‡bi nv‡ii 6 ̧Y| M ̈vmwUi AvYweK fi KZ? [DU 21-22] 128 g/mol 72 g/mol 32 g/mol 180 g/mol DËi: 72 g/mol e ̈vL ̈v: e ̈vcb nvi, r  1 M  rH2 rx = Mx MH2      6x x 2 = Mx MH2  36 = Mx 2  Mx = 36  2 = 72 g/mol 5. wb‡Pi †KvbwU jyBm GwmW? [DU 17-18; JU 17-18; BSMRSTU 19-20; JnU 09-10] HNO3 H2SO4 AlCl3 NH3 DËi: AlCl3 e ̈vL ̈v: jyBm GwmW: †hmKj †h.M ev Avqb B‡jKUab `vZv MÖæc n‡Z GK †Rvov B‡jKUab MÖn‡Y mÿg Zv‡`i jyBm GwmW e‡j| †hgb: SO3, BF3, AlCl3, FeCl3, ZnCl2, SnCl2, SiF4, PCl3, K ̈vUvqbmg~n (Ag+ , Ca2+ , Cu2+) BZ ̈vw`| jyBm ÿvi: †hmKj ivmvqwbK c`v_© Ab ̈ c`v_©‡K GK †Rvov B‡jKUab cÖ`v‡b mÿg Zv‡`i jyBm ÿvi e‡j| †hgb: OH– , CN– , R – NH2, R – OH, Cl – , .. NH3, H2 .. O.. BZ ̈vw`| 6. M ̈v‡mi NbZ¡ gvc‡Z e ̈eüZ nqÑ [DU 16-17] Arrhenius equation Perfect gas equation Einstein equation Faraday equation DËi: Perfect gas equation e ̈vL ̈v: Av`k© M ̈vm mgxKiY, PV = nRT  PV = W M RT  PM = W V RT  W V = PM RT  d = PM RT     d = fi (W) AvqZb (V) Gfv‡e Av`k© M ̈vm mgxKiY‡K M ̈v‡mi NbZ¡ cwigv‡c e ̈envi Kiv hvq|

cwi‡ek imvqb  Varsity Practice Sheet ........................................................................................................................... 3 14. wb‡¤œi †KvbwU AmZ ̈? [DU 12-13] NH+ 4 is the conjugate acid of base NH3 NH3 and H2O are conjugate pair OH– is the conjugate base of acid H2O OH– and H2O are conjugate pair DËi: NH3 and H2O are conjugate pair e ̈vL ̈v:  NH3 + H +  NH+ 4 base conjugate acid  H2O – H +  OH– acid conjugate base  NH3 + H2O ⇌ NH + 4 + OH– ; not conjugate pair  NH3 + H2O ⇌ NH + 4 + OH– ; conjugate pair 15. wb‡¤œi †jLwPÎmg~‡n wbw`©ó ZvcgvÎvq GKwU wbw`©ó f‡ii Av`k© M ̈v‡mi AvqZ‡bi mv‡_ Gi Pv‡ci m¤úK© †`Lv‡bv n‡q‡Q| †Kvb †jLwPÎwU Aï×? [DU 11-12] V P 1 V P P PV PV V DËi: PV V e ̈vL ̈v: e‡q‡ji m~Îvbymv‡i, PV = aaæeK| ZvB PV †K Y Aÿ eivei Ges V †K X Aÿ eivei ̄ vcb Ki‡j X A‡ÿi mgvšÍivj †iLv cvIqv hv‡e| PV V 16. 101.3 kPa evwn ̈K Pv‡c cvwbi ùzUbv1⁄4 KZ? [DU 11-12] 120.8C 90.5C 100.0C 18.0C DËi: 100.0C e ̈vL ̈v: 1 atm (101.325 kPa) Pvc n‡jv mvaviY evqygÐjxq Pvc| GB Pv‡c cvwbi ùzUbvsK 100C (373 K) 17. wb‡¤œi †Kvb M ̈vmwU Av`k© M ̈v‡mi ag© †_‡K me‡P‡q †ewk wePz ̈Z? [DU 10-11] HCl He CH4 N2 DËi: HCl e ̈vL ̈v: Av`k© M ̈v‡mi ag© n‡Z wePz ̈wZi KwZcq Kvi‡Yi GKwU n‡”Q AvYweK fi| wbw®...q M ̈vm e ̈ZxZ Ab ̈vb ̈ †ÿ‡Î AvYweK fi hZ †ewk n‡e Av`k© M ̈vm †_‡K wePz ̈wZ ZZ †ewk n‡e| HCl = 36.5 g mol–1 He = 4 g mol–1 CH4 = 16 g mol–1 N2 = 28 g mol–1 HCl Gi AvYweK fi me©vwaK nIqvq Gi wePz ̈wZ †ewk n‡e| 18. ZvcgvÎvi (T) mv‡_ Zi‡ji ev®úPvc (P) cwieZ©b wb‡¤œi †Kvb †jLwPÎ Øviv mwVKfv‡e †`Lv‡bv n‡q‡Q? [DU 09-10] T P T P T P T P DËi: T P e ̈vL ̈v: †M-jymv‡Ki m~Îvbymv‡i, w ̄ i AvqZ‡b wbw`©ó M ̈v‡mi Pvc cig ZvcgvÎvi mgvbycvwZK  P  T (V I n w ̄ i)  P = KT GB mgxKiYwU‡K y = mx Gi mv‡_ Zzjbv Ki‡j g~jwe›`yMvgx mij‡iLv cvIqv hvq| T P 19. evqygЇji †Kvb A‡j I‡Rvb ̄Íi Aew ̄’Z? [DU 09-10] Troposphere Thermosphere Mesosphere Stratosphere DËi: Stratosphere e ̈vL ̈v: Ua‡cvwùqv‡ii ci Dci w`‡K 15 km †_‡K 50 km D”PZv ch©šÍ evqygЇji 2q ̄Íi ÷a ̈v‡Uvwùqvi 35 km we ̄Í...Z| ÷a ̈v‡Uvwùqvi‡K kvšÍ gÐj ejv nq| ÷a ̈v‡Uvwùqv‡i m~‡h©i Av‡jvi ga ̈ ̄ ÿwZKviK UV-iwk¥ †kvlYKvix I‡Rvb (O3) ̄Íi we` ̈gvb hv Aw·‡Rb (O2) †_‡K m„wó nq|
4 ....................................................................................................................................  Chemistry 2nd Paper Chapter-1 20. 13C ZvcgvÎvq wbw`©ó f‡ii GKwU Av`k© M ̈v‡mi AvqZb w ̄’i Pv‡c wØ ̧Y Kiv n‡jv| GB Ae ̄’vq M ̈vmwUi ZvcgvÎv KZ n‡e? [DU 08-09] 7.5C 299C 13C 26C DËi: 299C e ̈vL ̈v: Pvj©‡mi m~Îvbymv‡i, V1 T1 = V2 T2  V1 T1 = 2V1 T2  T2 = 2T1 = {2 × (273 + 13)} K = 572 K = 299C 21. GKB ZvcgvÎvq H2 I O2 M ̈v‡mi rms †e‡Mi AbycvZ n‡”QÑ [DU 08-09] 1 8 1 4 4 8 DËi: 4 e ̈vL ̈v: crms(H2) crms(O2) = 3RT MH2 3RT MO2 = MO2 MH2 = 32 2 = 4  cH2 : cO2 = 4 : 1 22. 17C ZvcgvÎvq 2 atm Pv‡c 5 litre AvqZ‡bi GKwU M ̈v‡mi IRb 3 g| M ̈vmwUi AvYweK IRb KZ? [DU 07-08] 7.14 26.13 32.14 16.34 DËi: 7.14 e ̈vL ̈v: PV = nRT  PV = W M RT  M = WRT PV = 3 × 0.0821 × 290 2 × 5 = 7.1427 g mol–1 23. Kve©b, bvB‡Uav‡Rb I Aw·‡R‡bi cvigvYweK IRb h_vμ‡g 12, 14 I 16| wb‡Pi M ̈vm †Rvov ̧‡jvi g‡a ̈ †KvbwUi e ̈vcb nvi mgvb? [DU 07-08; CU 16-17; KU 14-15; Agri. Guccho 21-22] CO2 and NO2 CO2 and N2O CO2 and CO N2O and NO2 DËi: CO2 and N2O e ̈vL ̈v: †Kv‡bv M ̈v‡mi e ̈vcb nvi H M ̈v‡mi AvYweK f‡ii eM©g~‡ji e ̈ ̄ÍvbycvwZK| A_©vr, M ̈v‡mi AvYweK fi mgvb n‡j H M ̈vm؇qi e ̈vcb nvi mgvb n‡e| MCO2 = 44 g mol–1 MCO = 28 g mol–1 MNO2 = 46 g mol–1 MN2O = 44 g mol–1 GLv‡b, CO2 I N2O M ̈v‡mi AvYweK fi mgvb| ZvB G‡`i e ̈vcb nvi mgvb n‡e| 24. Pvc w ̄’i †i‡L GKwU M ̈v‡mi (AvqZb 1000 cm3 ) ZvcgvÎv A‡a©K Kiv nj| cwiewZ©Z Ae ̄’vq Dnvi AvqZb KZ n‡e? [DU 06-07] 2000 cm3 500 cm3 1000 cm3 1500 cm3 DËi: 500 cm3 e ̈vL ̈v: Pvj©‡mi m~Îvbymv‡i, V1 T1 = V2 T2  V1 T1 = V2 T1 2  V2 = 1 2 V1 =     1 2  100 = 500 cm3 25. 10.00 kg wnwjqvg Øviv 288 K ZvcgvÎvq GKwU †ejyb‡K dzwj‡q †ejy‡bi g‡a ̈ M ̈v‡mi Pvc 1.50 atm Kiv nq| †ejybwUi AvqZb KZ? [DU 05-06] 78720 L 39360 L 2050 L 39.36 L DËi: 39360 L e ̈vL ̈v: PV = nRT = W M RT  V = WRT MP = 10 × 103 × 0.082 × 288 4 × 1.5 = 39360 L 26. wb‡Pi †Kvb e ̄‘i Rb ̈ GKB AvqZ‡bi cv‡Î GKB ZvcgvÎvq Pvc m‡e©v”P n‡e? [DU 05-06] 28 g N2 4 g H2 17 g NH3 4 g He DËi: 4 g H2 e ̈vL ̈v: PV = nRT  P = nRT V GLv‡b R, T I V aaæeK n‡j, P  n A_©vr, hvi †gvj msL ̈v (n) †ewk Zvi Pvc (P) m‡e©v”P n‡e| nN2 = 28 28 = 1 mol; nH2 = 4 2 = 2 mol nNH3 = 17 17 = 1 mol; nHe = 4 4 = 1 mol  4 g H2 Gi †gvj msL ̈v m‡e©v”P nIqvq Gi Pvc m‡ev©”P n‡e| 27. 1 atm Pv‡c I wbw`©ó ZvcgvÎvq GKwU wbw`©ó AvqZ‡bi cv‡Î 4 g He, 14 g N2 Ges 16 g O2 Av‡Q| †KvbwUi AvswkK Pvc m‡e©v”P? [DU 02-03] He mKj AvswkK Pvc mgvb N2 O2 DËi He