Title 2. P2C2 স্থির তড়িৎ-(With Solve).pdf ✅

32 ......................................................................................................................................  Physics 2nd Paper Chapter-2 weMZ mv‡j KUET-G Avmv cÖkœvejx 1. 20 †m.wg. e ̈vmv‡a©i GKwU cwievnx †Mvj‡Ki Zj mylgfv‡e 3 gvB‡μv-Kzj¤^ Avav‡b AvwnZ| †Mvj‡Ki c„‡ô Ges †K›`a †_‡K 30 †m.wg. `~‡i †Kv‡bv we›`y‡Z Zwor cÖvej ̈ wbY©q Ki| [KUET 19-20] mgvavb: †Mvj‡Ki c„‡ô cÖvej ̈, E1 = 1 40  Q R 2  E = 9  109  3  10–6 0.22  E1 = 6.75  105 NC–1 (Ans.) †Mvj‡Ki †K›`a †_‡K 30 cm `~‡i cÖvej ̈, E2 = 1 40  Q r 2  E = 9  109  3  10–6 0.32  E2 = 3  105 NC–1 (Ans.) 2. 12 F Ges 24 F aviK‡Z¡i `yBwU aviK †kÖwYe×fv‡e mshy3 Ki‡j aviKZ¡ KZ n‡e? G‡`i `yB cÖvšÍ 40 V Gi GKwU e ̈vUvixi mv‡_ mshy3 Ki‡j GwU KZ PvR© MÖnY Ki‡e? GKwU 100  †ivaK D3 aviK `yBwUi mv‡_ †kÖwY ms‡hvM Ki‡j M„nxZ Pv‡R©i wK cwieZ©b n‡e? [KUET 03-04] mgvavb: Zzj ̈ aviKZ¡, Ceq = 12  24 12 + 24 = 8 F (Ans.) M„nxZ †gvU PvR©, Q = CV = 8  10–6  40  Q = 3.2  10–4 C (Ans.) 100  †ivaK hy3 Ki‡j M„nxZ Pv‡R©i †Kv‡bv cwieZ©b n‡e bv| †Kbbv e ̈vUvwii wefe cv_©K ̈ I Zzj ̈ aviKZ¡ DfqB aaæeK _vK‡e| (Ans.) weMZ mv‡j RUET-G Avmv cÖkœvejx 1. 1.0 m evûwewkó GKwU eM©‡ÿ‡Îi cÖwZwU †KvYvq 5  10–9 C PvR© ̄’vcb Kiv n‡jv, eM©‡ÿ‡Îi †K‡›`a wefe wbY©q Ki| [RUET 07-08] mgvavb: 1m 1 2 m 5nC 5nC 5nC 5nC e‡M©i †K‡›`a wefe, V = V1 + V2 + V3 + V4  V = 1 40  1 r (q1 + q2 + q3 + q4)  V = 9  109  1 1 2  (4  5  10–9 )  V = 254.558 V (Ans.) 2. PviwU 4 F Gi aviK‡K 100 V e ̈vUvwii mwnZÑ (i) mgvšÍivj ms‡hvM w`‡j wK cwigvY •e`y ̈wZK kw3 mwÂZ n‡e? (ii) wmwiR ms‡hvM w`‡j wK cwigvY •e`y ̈wZK kw3 mwÂZ n‡e? [RUET 03-04] mgvavb: (i) mgvšÍivj ms‡hv‡M, Ceq = 4  4 = 16 F  mwÂZ wefekw3, U = 1 2 CeqV 2  U = 1 2  16  10–6  1002  U = 0.08 J (Ans.) (ii) wmwiR ms‡hv‡M, Ceq = 4 4 = 1 F  mwÂZ wefekw3, U = 1 2 CeqV 2  U = 1 2  1  10–6  1002  U = 5  10–3 J (Ans.) weMZ mv‡j CUET-G Avmv cÖkœvejx 1. 1 bs wP‡Î V1, V2, V3 †fv‡ë‡Ri gvb wbY©q Ki Ges mswkøó K ̈vcvwmU‡ii PvR© wbY©q Ki| [CUET 07-08] V2 V3 C2 C3 6F 12F V1 10 V + – wPÎ-1 C1 6F mgvavb: C1 avi‡Ki †ÿ‡Î, V1 = 10 V (Ans.)  Q1 = C1V1  Q1 = 6  10–6  10  Q1 = 60 C (Ans.) Avevi, Cs = C2C3 C2 + C3 = 6  12 6 + 12 = 4 F  Q2 = Q3 = Cs  10 = 40 C (Ans.)  V2 = Q2 C2 = 40 C 6 F = 6.667 V (Ans.)  V3 = Q3 C3 = 40 C 12 F = 3.33 V (Ans.) 2. 12 C Ges 8 C `ywU we›`y PvR© ci ̄úi †_‡K 10 †m.wg. `~‡i Aew ̄’Z| PvR© `ywU‡K 6 †m.wg. e ̈eav‡b wb‡q Avm‡Z KZUzKz KvR Ki‡Z n‡e| PvR© `ywU k~‡b ̈ Aew ̄’Z| [CUET 05-06] mgvavb: Avgiv Rvwb, K...ZKvR, W = Qq 40     1 rf – 1 ri  W = 12  10–6  8  10–6  9  109      1 0.06 – 1 0.1  W = 5.76 J (Ans.)