Title HPGE 27 Solutions.pdf ✅

[SOLUTION] QT = 1 2 [ 8 15 CD√2g tan φ1 H 5 2] + 2 3 CD√2gLH 3 2 + 1 2 [ 8 15 CD√2g tanφ2 H 5 2] QT = 1 2 [ 8 15 (0.58)√2 (9.81 m s 2 ) ( 1.25 1.5 ) (1.5 m) 5 2] + 2 3 (0.58)√2 (9.81 m s 2 ) (2 m)(1.5 m) 3 2 + 1 2 [ 8 15 (0.58)√2 (9.81 m s 2 ) ( 1.75 1.5 ) (1.5 m) 5 2] QT = 10.0687 m3 s ▣ 11. A V-notch weir is installed at the end of a rectangular water tank, as shown in the figure. Determine the time required to discharge 60 m3 of water. C = 0.61. [SOLUTION] Determine the change in height: h = 60 m3 15 m × 7 m h = 4 7 m Compute for the time t = ∫ As 8 15 CD√2g tan θ 2 H 5 2 dh h1 h2