Title 46 Bolted Connections.pdf ✅

For the configuration shown, the number of shear planes (and consequently the number of areas resisting shear) is doubled. For double shear joints, the critical plate to be analyzed for limit states involving plate thickness and material strength (e.g., plate yielding, rupture, bearing) is the one that will yield the smallest force- thickness ratio. This consideration is irrelevant to computations based on bolt shear, as middle plates carrying a full load will have double shear planes, and thus experience the same stresses as outer plates with single shear planes, but with half the resisted load (i.e., P/2 = (P/2)/1). Allowable Force per Bolt Shear Area P௔௟௟௢௪ = F௩ π 4 d௕ ଶ Where: F௩ = allowable bolt shear stress (typically specified in board exam problems) From NSCP 2015: 510.3.6 Nominal Shear Strength of a Bolt R௡ = F௡௩ ቀ π 4 d௕ ଶቁ Where: F௡௩ = nominal shear stress of the bolt (may vary depending on shear planes if they intersect the threaded portion of the bolt or not) φ = 0.75 (LRFD) Ω = 2.00 (ASD)