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6. Compute the stress at section BC. Solving for BC: ∑MF = 0 10(3 + 3) = BC(3) BC = 20 N (Compression) SITUATION (7-9): The parabolic cable supports the truss shown in the Figure. The truss is pinned at D. Free Body Diagram (Considering Whole System): ∑MC = 0 Ey (51.6) + By (51.6) + Ax(7.5) = Bx (7.5) + 5.6(12.9) + 142.4(17.2) Parabolic Cable:Horizontal Component of Tension is Constant Throughout Entire Length of Cable Ax = Bx

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