Title NEET Chapter -1,2,3,4,5 -Key.pdf ✅

RS ACADEMY Satellite STD : 11 and 12 (GSEB/CBSE) Total Marks:180marks Total Time: 1:00hr NEET-FULL COURSE Ronak Shah - 9428239499 Page 1 of 5 1. A charged particle is projected in a magnetic field 2 ˆ ˆ (3 4 ) 10 i j T− +  . The acceleration of the particle is found to be a = xi j ˆ ˆ + 4 m/s2 .Find the value of x. a)8/3 b)-8/3 c)4/3 d)-4/3 2. Two particles X and Y having equal charges, after being accelerated through the same potential difference, enter a region of uniform magnetic field and describe circular paths of radii R1and R2 , respectively. The ratio of the mass of X to that of Y is a) 1/2 1 2 R R       b) 1 2 R R c) 2 1 2 R R       d) 2 1 R R 3. A square of side 2.0 m is placed in a uniform magnetic field B = 2.0T in a direction perpendicular to the plane of the square inwards. Equal current i = 3.0 A is flowing in the directions shown in figure. Find the magnitude of magnetic force on the loop. a) 36 2N force along EC b) 36 2N force along AD c) 36N force along EC d) 36N force along AD 4. Find the magnitude of magnetic moment of the current carrying loop ABCDEFA. Each side of the loop is 10 cm long and current in the loop is i = 2.0 A. a)0.058A/m2 b)0.028A/m2 c)0.068A/m2 d)0.038A/m2 5. A circular loop of radius R = 20 cm is placed in a uniform magnetic field B = 2T in xy-plane as shown in figure. The loop carries a current i = 1.0 A in the direction shown in figure. Find the torque acting on the loop. a) 0.18( ) ˆ ˆ i j − b) 0.18( ) ˆ ˆ i j + c) 0.36( ) ˆ ˆ i j − d) 0.36( ) ˆ ˆ i j + 6. A conductor consists of a circular loop of radius R = 10 cm and two straight, long sections as shown in figure. The wire lies in the plane of the paper and carries a current of i = 7.00 A. Determine the magnitude and direction of the magnetic field at the centre of the loop. a)58.0 μT into the page b)68.0 μT into the page c)58.0 μT out the page d)68.0 μT out the page 7. Consider three long straight parallel wires as shown in figure. Find the force experienced by a 25 cm length of wire C. a) ) 4 5 10 T −  toward’s right b) 4 5 10 T −  toward’s left c) 4 3 10 T −  toward’s right d) 4 3 10 T −  toward’s left