Title Corrections for Eval 7 Nov 2024 Solutions (1).pdf ✅

θ ≈ 13.90∘ SITUATION 3. ▣ 5. Shown is the figure for the situation w = 80 rpm × π 30 = 8π 3 rad/s y = w 2 r 2 2g y = ( 8π 3 rad s ) 2 (0.5 m) 2 2 (9.81 m s 2 ) y = 0.8943 m To assure no spillage, the volume of air in the tank initially must be equal to the volume of air during rotation. Vcylinder = Vparaboloid π(0.5 m) 2 (h − 3.85 m) = 1 2 π(0.5 m) 2 (0.8943 m) h = 4.297 m