Title 10. P2C10. Phy.-2nd-Paper-For-FRB-2024_With Solve_Ridoy_03.05.25.pdf ✅

2  HSC Physics 2nd Paper Chapter-10 3| [Kz. †ev. 24] + IE IB IC = 5.4 mA RL = 4.5  – – + DÏxc‡K GKwU Kgb GwgUvi UavbwR÷vi eZ©bx †`Lv‡bv n‡jv| eZ©bxwUi MZxq †iva I fvi †iva h_vμ‡g 55  I 45 | eZ©bxi Kv‡i›U †MBb 80 Ges Kv‡j±i Kv‡i›U 5.4 mA| (K) †Wvwcs Kv‡K e‡j? (L) ZvcgvÎv e„wׇZ Aa©cwievnxi Zwor cwievwnZv e„w× cvq †Kb? e ̈vL ̈v Ki| (M) eZ©bxi wbtmviK cÖevn wbY©q Ki| mgvavb: Avgiv Rvwb, IE = IC + IB Avevi,  = IC IB  IB = IC  = 5.4 80 mA = 0.0675 mA †`Iqv Av‡Q, Kv‡i›U †MBb,  = 80 Kv‡j±i (msMÖvnK) cÖevn, IC = 5.4 mA wbtmviK cÖevn, IE =?  IE = IC + IB = (5.4 + 0.0675) mA = 5.4675 mA (Ans.) (N) DÏxc‡Ki eZ©bx †_‡K 100% †fv‡ëR †MBb cvIqv m¤¢e wK-bv? MvwYwZK we‡køl‡Yi gva ̈‡g hvPvB Ki| mgvavb: Avgiv Rvwb, Av =   RL Rin = 80  45 55 = 65.45 †`Iqv Av‡Q, Kv‡i›U †MBb,  = 80 MZxq †iva ev BbcyU †iva, Rin = 55  fvi †iva, RL = 45  †fv‡ëR †MBb Av = ?  DÏxc‡Ki UavbwR÷‡ii †fv‡ëR †MBb 65.45| myZivs D3 UavbwR÷‡ii gva ̈‡g 100% (ev 100) †fv‡ëR †MBb cvIqv m¤¢e bq| (Ans.) 4| Vin=0.28 V Rin=7 E VBB VCE B C IC=60 mA RL=12  Vout wP‡Î GKwU Kgb GwgUi n-p-n UavbwR÷i eZ©bx †`Lv‡bv nj| [Xv. †ev. 24] (K) NAND †MBU Kx? (L) Wv‡qv‡Wi †Rbvi wμqv e ̈vL ̈v K‡iv| (M) UavbwR÷iwUi cÖevn weea©b ̧YK wbY©q K‡iv| mgvavb: Avgiv Rvwb,  = IC IE Avevi, IE = IC + IB Avevi, IB = Vin Rin †`Iqv Av‡Q, msMÖvnK cÖevn, IC = 60 mA = 0.06 A BbcyU Voltage, Vin = 0.28 V BbcyU †iva, Rin = 7  cÖevn weea©b ̧YK,  = ?  IB = 0.28 7 = 0.04 A IE = IC + IB  IE = (0.06 + 0.04) A = 0.1 A   = IC IE = 0.06 0.1 = 0.6 (Ans.) (N) DÏxc‡Ki eZ©bx †_‡K weewa©Z ms‡KZ cvIqv m¤¢e wKbv, MvwYwZK we‡køl‡Yi gva ̈‡g gZvgZ `vI| mgvavb: DÏxc‡Ki eZ©bx †_‡K weewa©Z ms‡KZ cvIqv m¤¢e n‡e hw` eZ©bxi weea©b 1-Gi †_‡K †ewk nq| Avgiv Rvwb, Av =   RL Rin Avevi,  = IC IB = 60  10–3 40  10–3 = 1.5  Av = 1.5  12 7 = 2.571 †`Iqv Av‡Q, msMÖvnK cÖevn, IC = 60 mA = 0.06 A fvi †iva, RL = 12  BbcyU †iva, Rin = 7 †fv‡ëR †MBb Av = ? ‘MÕ bs †_‡K IB = 0.04A myZivs DÏxc‡Ki eZ©bx †_‡K weewa©Z ms‡KZ cvIqv hv‡e| (Ans.) 5| Kgb BwgUvi UavbwR÷i ms‡hvM eZ©bx‡Z 0.8 V I 1.10 V weef cÖ‡qv‡M BwgUvi cÖevn h_vμ‡g 10 mA I 40 mA cvIqv hvq| cÖevn weea©b ̧YK 0.9 Ges fvi †iva 120 | [w`. †ev. 24] (K) GK Kzix Kv‡K e‡j? (L) mKj Acwievnx WvBB‡jKwUaK bqÑ e ̈vL ̈v Ki| (M) UavbwR÷iwUi cÖevn jvf wbY©q Ki| mgvavb: †`Iqv Av‡Q, CE UavbwR÷‡ii cÖevn weea©b ̧Yv1⁄4,  = 0.98 Avgiv Rvwb, cÖevn jvf,  =  1 –  = 0.98 1 – 0.98 = 49 (Ans.) (N) DÏxc‡Ki UavbwR÷iwU weea©K iƒ‡c wμqv Ki‡e wK bvÑ MvwYwZKfv‡e we‡kølY Ki| [Abyiƒc e. †ev. 24] 6| GKwU UavbwR÷‡ii mvaviY cxV ms‡hvM _vKv Ae ̄’vq cxV cÖevn I wbtmviK cÖev‡ni gvb h_vμ‡g 0.04 mA I 0.7 mA cvIqv hvq| [h. †ev. 24] (K) ZvcMwZwe` ̈vi 1g m~ÎwU †jL| (L) †Wvwcs †Kb Kiv nq? e ̈vL ̈v Ki| (M) DÏxcK Abyhvqx UavbwR÷iwUi cÖevn weea©K ̧Y‡Ki gvb wbY©q Ki| [Abyiƒc wm. †ev. 24] (N) UavbwR÷iwUi cÖevn jvf  Gi gv‡bi cwieZ©b Kxiƒc n‡e hw` cxV cÖev‡ni gvb wØ ̧Y Kiv nq? MvwYwZK we‡kølYmnKv‡i DËi `vI| [Abyiƒc wm. †ev. 24]

4  HSC Physics 2nd Paper Chapter-10 (N) DÏxc‡Ki mZ ̈K mviwYi jwRK †MB‡Ui mv‡_ GKwU NOT †MBU hy3 Ki‡j †Kv‡bv jwRK †MBU •Zwi n‡e wKbvÑ Zv wPÎ I mZ ̈K mviwYi mvnv‡h ̈ e ̈vL ̈v Ki| mgvavb: DÏxc‡K mZ ̈K mviwYi jwRK †MBU n‡jv AND †MBU| Gi mv‡_ NOT †MBU hy3 Ki‡j NAND †MBU •Zwi n‡e| A B AB AB–– A B Y = AB–– NAND wPÎ: NAND †MBU wb‡¤œ NAND †MB‡Ui mZ ̈K mviwY †`Lv‡bv n‡jv: A B AB AB –––– (AvDUcyU) 0 0 0 1 0 1 0 1 1 0 0 1 1 1 1 0 A_©vr DÏxc‡Ki mZ ̈K mviwYi jwRK †MB‡Ui mv‡_ NOT †MBU hy3 Ki‡j NAND †MBU •Zwi n‡e| (Ans.) 11| + – – + IE = 20mA Output IC=18mA RL VBB VCE Input n-p-n b c Ib e RL [iv. †ev. 23] (K) wW‡cøkb †jqvi Kx? (L) wecixZ †Suv‡K Wv‡qv‡W Zwor cÖevn nq bv †Kb? e ̈vL ̈v K‡iv| (M) eZ©bx‡Z cÖevn jvf KZ n‡e? wbY©q K‡iv| mgvavb: IE = IB + IC  IB = IE – IC = (20 – 18) mA  IB = 2 mA  cÖevn jvf,  = IC IB = 18 2   = 9  cÖevn jvf 9 n‡e| (Ans.) (N) DÏxc‡Ki eZ©bxwU myBP wnmv‡eI KvR Kiv‡bv m¤¢eÑ we‡kølY K‡iv| mgvavb: DÏxc‡Ki eZ©bxwU UavbwR÷i nIqvq †jvW RL Gi ga ̈ w`‡q Zwor cÖevn wbqš¿‡Yi gva ̈‡g myBP wn‡m‡e KvR K‡i| +VCC RL Vi VO = VCC +VCC RL Vi VO = VCC – ICRL IC wPÎ: myBP Ab I Ad Ae ̄’v hLb †e‡m BbcyU †fv‡ëR FYvZ¥K ev k~b ̈ nq ZLb †jvW RL Gi ga ̈ w`‡q Zwor cÖevwnZ nq bv Ges AvDUcyU †fv‡ëR VCC nq| hLb †e‡m BbcyU †fv‡ëR abvZ¥K nq ZLb weewa©Z Kv‡i›U cÖevn IC †jvW RL Gi g‡a ̈ w`‡q cÖevwnZ nq Ges AvDUcyU †fv‡ëR nq, VO = VCC – ICRL A_©vr DÏxc‡Ki eZ©bxwU myBP wn‡m‡eI KvR Kiv‡bv m¤¢e| (Ans.) 12| Rl = 5000  E B IC Ri = 500  IE IB C [Kz. †ev. 23] eZ©bxi UavbwR÷‡ii  = 0.98 I IE = 1.5 mA| (K) m¤§yLx †SuvK Kv‡K e‡j? (L) e ̈vÛ Z‡Ë¡i Av‡jv‡K AšÍiK c`v‡_©i cwievwnZv e ̈vL ̈v K‡iv| (M) DÏxc‡Ki IB wbY©q K‡iv| mgvavb: cÖevn weea©b ̧YK,  = IC IE  IC = IE = 0.98  1.5 mA  IC = 1.47 mA  IE = IC + IB  IB = IE – IC = (1.5 – 1.47) mA  IB = 0.03 mA (Ans.) (N) DÏxc‡Ki eZ©bxwU‡K †fv‡ëR weea©K wn‡m‡e e ̈envi Kiv hvq wKbv? MvwYwZKfv‡e we‡kølY K‡iv| mgvavb: †fv‡ëR jvf, VA =   RL Ri = IC IB  RL Ri = 1.47 0.03  5000 500  VA = 490 ∵ VA > 1 A_©vr DÏxc‡Ki eZ©bxwU‡K †fv‡ëR weea©K wn‡m‡e e ̈envi Kiv hvq| (Ans.)