Title MSTE 34 Solutions.pdf ✅

34 Surveying: Horizontal Curves 1 Solutions SITUATION 1. Two tangents adjacent to each other having bearings N 65°30′E and S 85°10′E meet at station 11+157.98. If the radius of the simple curve connecting these two tangents is 249.17 m, determine the following: ▣ 1. Tangent distance. [SOLUTION] Solve for the angle of intersection I = 180° − (85°10′ + 65°30′ ) = 29°20′ T = R tan I 2 T = (249.17 m) tan 29°20′ 2 T = 65.2136 m ▣ 2. Long Chord. [SOLUTION] C = 2R sin I 2 C = 2(249.17 m) sin 29°20′ 2 C = 126.1773 m ▣ 3. Middle Ordinate. [SOLUTION] M = R (1 − cos I 2 ) M = (249.17 m) (1 − cos 29°20′ 2 ) M = 8.119 m ▣ 4. External Distance. [SOLUTION] E = R (sec I 2 − 1)

TC = R1 tan I1 2 + R2 tan I2 2 70 m = R1 tan 12° 2 + (180 m) tan 18° 2 R1 = 394.7586 m