Title গণিত ম্যাজিক শিট সমাধান.pdf ✅

Kauser’s Math Academy MwYZ m„Rbkxj g ̈vwRK wkU cÖ ̄‘ZKviK : KvDQvi Avn‡g` Lvb (01761-886621) GmGmwm- 24/25 mgvavb aib bs-1 :- (‡Rvo,we‡Rvo,μwgK msL ̈v, c~Y©eM© msL ̈v m¤úwK©Z cÖkœ Ges Ag~j` msL ̈v wbY©q) 1. cÖgvY Ki †h, †h‡Kv‡bv we‡Rvo c~Y© msL ̈vi eM© GKwU we‡Rvo msL ̈v| :mgvavb: g‡b Kwi, n GKwU we‡Rvo msL ̈v  n = 2x  1; †hLv‡b x GKwU c~Y© msL ̈v  n2 = (2x 1)2 ; Dfqcÿ‡K eM© K‡i = (2x)2  22x1 + (1)2 = 4x2  4x + 1 = 4x(x 1) + 1 GLv‡b, 4x(x 1) msL ̈vwU 2 Øviv wefvR ̈| A_©vr †Rvo msL ̈v|  4x(x 1) + 1 msL ̈vwU we‡Rvo msL ̈v| AZGe, n2 we‡Rvo msL ̈v| myZivs mKj we‡Rvo c~Y© msL ̈vi eM© GKwU we‡Rvo msL ̈v (cÖgvwYZ) 2. cÖgvY Ki †h, `yBwU μwgK †Rvo msL ̈vi ̧Ydj 8 (AvU) Øviv wefvR ̈| :mgvavb: mgvavb : g‡b Kwi, `yBwU μwgK †Rvo msL ̈v h_vμ‡g 2x I 2x + 2 μwgK msL ̈v `yBwUi ̧Ydj, 2x  (2x + 2); †hLv‡b x †h‡Kv‡bv ̄^vfvweK msL ̈v|  2x (2x + 2) = 2x (2x + 2) = 4x2 + 4x = 4x (x + 1) GLv‡b, x I x + 1 `yBwU μwgK msL ̈v| myZivs G‡`i GKwU †Rvo msL ̈v n‡eB|  x(x + 1) msL ̈vwU 2 Øviv wefvR ̈ n‡e|  4x(x +1) msL ̈vwU 4  2 ev 8 Øviv wefvR ̈ n‡e| AZGe, `yBwU μwgK †Rvo msL ̈vi ̧Ydj 8 Øviv wefvR ̈ n‡e| myZivs x Gi ̄^vfvweK gvb wbwe©‡k‡l 8 Øviv 4x(x +1) msL ̈vwU wefvR ̈ n‡e| (cÖgvwYZ) 3. cÖgvY Ki †h, †Kv‡bv PviwU μwgK ̄^vfvweK msL ̈vi ̧Yd‡ji mv‡_ 1 †hvM Ki‡j †hvMdj GKwU c~Y© eM© msL ̈v n‡e| :mgvavb: g‡bKwi, PviwU μwgK ̄^vfvweK msL ̈v h_vμ‡g x, x + 1, x + 2, x + 3 μwgK msL ̈v PviwUi ̧Yd‡ji mv‡_ 1 ‡hvM Ki‡j cvIqv hvq, x(x + 1)(x + 2)(x + 3) + 1 = x(x + 3)(x + 1)(x + 2) + 1 = (x2 + 3x)(x2 + 3x + 2) + 1 = a(a + 2) + 1 [x2 + 3x = a a‡i] = a2 + 2a + 1 = (a + 1)2 = (x2 + 3x + 1)2 hv GKwU c~Y©eM© msL ̈v| myZivs †h †Kv‡bv PviwU μwgK ̄v^ fvweK msL ̈vi ̧Yd‡ji mv‡_ 1 †hvM Ki‡j †hvMdj GKwU c~Y©eM© msL ̈v n‡e|
Kauser’s Math Academy MwYZ m„Rbkxj g ̈vwRK wkU cÖ ̄‘ZKviK : KvDQvi Avn‡g` Lvb (01761-886621) GmGmwm- 24/25 mgvavb Av‡iv †hmKj dvBj wKb‡Z cvi‡eb 1. BwR A+ MwYZ mcq wkU (90 wU UwcK †_‡K †gvU 1300+ cÖkœ I DËi) 2. 23 mv‡ji ‡evW © cÖkœh3 m„ y Rbkxj mv‡RkÝ wkU 3. cixÿv †bIqvi Rb ̈ Aa ̈vq wfwËK cÖkœ Avcbvi cÖ‡qvR‡b wKb‡Z Kj Kiæb A_ev †g‡mR Kiæb 01780-116884 ‡nvqvUmA ̈vc : 01761-886621 (KvDQvi m ̈vi)