Title 10. P2C10. সেমিকন্ডাক্টর ও ইলেক্ট্রনিক্স (With Solve).pdf ✅

†mwgKÛv±i I B‡jKUawb·  Engineering Practice Sheet ................................................................................................... 3 MCQ weMZ mv‡j BUET-G Avmv cÖkœvejx 1. Kv‡i›U weea©K ̧Yv1⁄4  = ? [BUET Preli 22-23] IC IE IC IB IE IB †Kv‡bvwUB bq DËi: IC IE 2. Kgb †em UavbwR÷‡ii Collector current 47 A n‡Z 96 A Ges emitter current 100 A n‡Z 150 A n‡jv| Current Amplification factor = ? [BUET Preli 22-23] 0.98 0.99 0.49 0.48 DËi: 0.98 e ̈vL ̈v:  = IC IE = 96 – 47 150 – 100 = 0.98 3. Transistor Kx wn‡m‡e KvR Ki‡Z cv‡i? [BUET Preli 21-22] Amplifier, Rectifier Amplifier, Switch Rectifier, Switch Amplifier, Rectifier, Switch DËi: Amplifier, Switch 4. †Kvb UavbwR÷‡i BbcyU I AvDUcyU wmMb ̈v‡ji g‡a ̈ `kv cv_©K ̈ KZ? [BUET Preli 21-22] 0 180 90 – 90 DËi: 180 5. GwU †Kvb †MBU? [BUET Preli 21-22] X Y Output 1 1 0 1 0 0 0 1 0 0 0 1 OR Gate AND Gate NAND Gate NOR Gate DËi: NOR Gate 6. wb‡Pi †KvbwU‡K †Wv‡c›U wnmv‡e e ̈envi Ki‡j p-UvBc Aa©cwievnxi ag© cvIqv hv‡e bv? [BUET 11-12] A ̈vjywgwbqvg Gw›Ugwb M ̈vwjqvg BwÛqvg DËi: Gw›Ugwb 7. p-n Rvsk‡bi ms‡hvM ̄’‡j wW‡cøkb ͇̄ii m„wói KviY njÑ [BUET 10-11] †nv‡jb Zvob Avavb evn‡Ki e ̈vcb B‡jKUa‡bi Zvob Ac`ae ̈ Avqb-Gi ̄’vbvšÍi DËi: Avavb evn‡Ki e ̈vcb weMZ mv‡j CKRUET-G Avmv cÖkœvejx 1. GKwU Kgb †em ms‡hv‡M _vKv UavbwR÷‡ii wbtmviK I †em cÖevn h_vμ‡g 5 mA Ges 0.5 mA| wbtmviK Gi cÖevn 5 ̧Y I †em cÖevn 3 ̧Y Kiv n‡j, UavbwR÷iwUi cÖevn e„w× KZ? [CKRUET 23-24] 0 6.67 9 15.67 24.67 DËi: Blank e ̈vL ̈v: Kgb †em ms‡hv‡M cÖevn jvf =  = IC IE = 5 – 0.5 5 = 0.9  = IC IE = IE – IB IE = (5 × 5) – (3 × 0.5) 5 × 5 = 0.94   = 0.04 myZivs Kgb †em Kv‡bKk‡b cÖevn jvf | †m‡ÿ‡Î DËi †bB| cÖevn jvf =  ai‡j,  = IC IB = IE – IB IB = 5 – 0.5 0.5 = 9  = IC IB = IE – IB IE = (5 × 5) – (0.5 × 3) 0.5 × 3 = 15.67   =  –  = 6.67  cÖevn e„w× 6.67 2. wb‡Pi wP‡Î Si Ges Ge Wv‡qvW `ywUi bx-†fv‡ëR h_vμ‡g 0.7 V Ges 0.3 V| 5.5 k †iv‡ai ga ̈ w`‡q KZ we`y ̈r cÖevwnZ n‡e? Ge Wv‡qvWwU D‡ëv K‡i ms‡hvM w`‡j †ivawUi `yB cÖv‡šÍi wefe cv_©K ̈ KZ n‡e? [CKRUET 23-24] +12 V Si Ge 5.5 k 2.0 mA and 0 V 2.0 mA and 0.7 V 2.0 A and 0 V 2.0 mA and 0.3 V 2.0 mA and 11.3 V DËi: 2.0 mA and 0 V e ̈vL ̈v: I = 12 – 0.7 – 0.3 5.5  103 = 2 mA Ge Wv‡qvWwU D‡ëv K‡i mshy3 Ki‡j I = 0  V = 0  R = 0 V
4 ......................................................................................................................................  Physics 2nd Paper Chapter-10 3. Kgb G ̈vwgUvi eZ©bx‡Z GKwU n-p-n UavbwR÷‡ii msMÖvn‡K 8 V e ̈vUvix mshy3 Av‡Q| msMÖvnK eZ©bxi RC †iv‡ai `yB cÖv‡šÍ wefe cZb 0.5 V n‡j †em Kv‡i›U wbY©q K‡iv| [†`Iqv Av‡Q, RC = 800  Ges  = 0.96] [CKRUET 22-23] 0.625 mA 0.000625 mA 0.974 mA 0.026 mA 0.000026 mA DËi: 0.026 mA e ̈vL ̈v: IC = VC RC = 0.5 800 = 6.25  10–4 A IB = IC  = 6.25  10–4 0.96  (1 – 0.96) A = 2.6  10–5 A = 0.026 mA 4. GKwU UavbwR÷‡ii wb¤œwjwLZ gvb ̧‡jv cwigvc Kiv n‡jv| IC = 1.98 mA; IB = 20A; UavbwR÷‡ii ,  Ges IE Gi gvb †ei Ki| [CKRUET 21-22]  = 0.99;  = 99 and IE = 5.02 mA  = 99;  = 0.99 and IE = 5.02 mA  = 0.99;  = 99 and IE = 7.00 mA  = 99;  = 0.99 and IE = 5.02 mA  = 0.99;  = 0.99 and IE = 5.02 A DËi: Blank e ̈vL ̈v:  = IC IE = IC IC + IB = 1.98 1.98 + 20 × 10–3 = 0.99  =  1 –  = 99 IE = IB + IC = 1.98 + 20 × 10–3 = 2 mA weMZ mv‡j KUET-G Avmv cÖkœvejx 1. wbtmviK cÖev‡ni 11.6 mA cwieZ©b msMÖvnK cÖev‡ni 10.92 mA cwieZ©b NUvq|  Gi gvb KZ? [KUET 18-19] 19 18 16 13 15 DËi: 16 e ̈vL ̈v:  = IC IB = IC IE – IC = 10.92 11.6 – 10.92    16 2. 98 †K evBbvix msL ̈vq iƒcvšÍi Ki| [KUET 15-16] 1100010 0100011 1000011 100011 110001 DËi: 1100010 e ̈vL ̈v: Calculator e ̈envi K‡i| 3. †Kvb UavbwR÷i mvaviY cxV ms‡hv‡M mshy3| Gi wbtmviK cÖevn 0.88 mA Ges cxV cÖevn 0.065 mA| cÖevn weea©b ̧YK KZ? [KUET 14-15; CUET 13-14; RUET 09-10] 0.942 0.93 0.95 0.96 0.926 DËi: 0.926 e ̈vL ̈v:  = IC IE = IE – IB IE = 0.88 – 0.065 0.88   = 0.926 4. GKwU UavbwR÷‡ii †ÿ‡Î  = 0.95 Ges IE = 0.9 mA n‡j  KZ n‡e? [KUET 13-14] 19 16 18 12 DËi: 19 e ̈vL ̈v:  =  1 –  = 0.95 1 – 0.95 = 19 5. 0.02 A wbtmviK cÖev‡ni d‡j GKwU UavbwR÷‡i 18 mA msMÖvnK cÖevn cvIqv †Mj| UavbwR÷‡ii f~wg cÖev‡ni gvb KZ? [KUET 12-13] 38 mA 2 A 2 mA 0.2 A 0.38 A DËi: 2 mA e ̈vL ̈v: IB = IE – IC = 0.02 – 18 × 10–3  IB = 2 mA weMZ mv‡j RUET-G Avmv cÖkœvejx 1. GKwU mvaviY f~wg UavbwR÷‡i msMÖvnK cÖevn 0.85 A Ges f~wg cÖevn 0.05 mA| cÖevn weea©K ̧YK KZ? [RUET 13-14] 0.99994 1.99994 0.49999 4.9999 None DËi: 0.99994 e ̈vL ̈v:  = IC IE = IC IC + IB = 0.85 0.85 + 0.05 × 10–3   = 0.99994 2. GKwU UavbwR÷‡ii weea©b ̧Yv1⁄4 0.98 Ges GwgUi Kv‡i›U 1.5 mA n‡j Kv‡j±i Kv‡i›U KZ? [RUET 12-13] 7.47 mA 4.74 mA 4.17 mA 1.74 mA 1.47 mA DËi: 1.47 mA e ̈vL ̈v:  = IC IE  IC = 0.98 × 1.5 = 1.47 mA