Title HPGE 4 Solutions.pdf ✅

well is lowered 0.5 m and the drawdown of the other observation well at a distance of 35 m from the test well is 1.1 m. ▣ 3. Compute the coefficient of permeability of the aquifer in m/day. [SOLUTION] k = q π(z1 2 − z2 2 ) ln r2 r1 Compute for the heights of water z1 = 27 − 0.5 = 26.5 m z2 = 27 − 1.1 = 25.9 m k = 0.069 m3 s π[(26.5 m) 2 − (25.9 m) 2] ln 95 m 35 m × 86400 s 1 day k = 60.27 m/day ▣ 4. Compute the transmissibility of the aquifer in m2/day. [SOLUTION] T = kb T = (60.27 m day) (27 m) T = 1627 m2/day SITUATION 2. A canal and a river run parallel 50 m apart and at a length of 750 m. The elevation of the water in the canal is 300 m and in the river 292 m. A stratum of sand intersects both the river and the canal below their water levels. The sand is 1.3 m thick and its between strata of impervious clay as shown on the sketch. The permeability of the sand stratum is 1.6 × 10−3 mm/s. ▣ 5. Determine the hydraulic gradient.
[SOLUTION] i = Δh L i = 300 m − 292 m 50 m i = 0.16 ▣ 6. Determine the quantity of water which flows into the canal per day. [SOLUTION] Q = kiA Q = (1.6 × 10−3 mm s × 1 m 1000 mm) (0.16)(1.3 m × 750 m) × 86400 s day Q = 21.565 m3/day