Title Y5 Maths 5012f - 2025 Week13 Notes.pdf ✅

Page 1 YEAR 5 MATHS WEEK 13 NOTES Practice 5012f Term 2 Week 4, 2025 Learning Outcomes A) Revision • Problem Solving by using inverse operations • Problem Solving by using symbols B) Factors, Multiples and Prime & Composite numbers • Key Definitions • Highest Common Factor • Lowest Common Multiple C) Reflection & Coordinates • Reflection • Finding the coordinates of points D) Cryptarithms (optional) • Cryptarithms Homework • Complete Practice 12 (Paper 5012f) • Levels 6-7 Location and Transformation pp197 -198 • Scholarship Tests Year 5 & 6 Factors, Multiples & Remainders pp15-16 NEW CENTURY SCHOOL 2025

Page 3 Q4. A rectangle has length 3.7 cm and perimeter 13.2 cm. Write a number sentence to find the width of the rectangle. Use inverse operation to verify your answer. 2 x Length + 2 x Width = Perimeter so Width = 1⁄2(Perimeter – 2 x Length) So the number sentence is: 1⁄2 ( 13.2 – 2 x 3.7) = 2.9 Can use: 2 x 3.7 + 2 x 2.9 = 13.2 to check or 1⁄2 ( 13.2 – 2 x 2.9) = 3.7 Q5. The table shows whether the children in a town are left or right handed. Use addition and subtraction in a column format to find the missing values. Boys Girls Total Left A 1 241 2 565 Right 2 121 B 4 433 Total C 3 553 6 998 Solution: A = 2.565 – 1.241 = 1.324 B = 4.433 – 2.121 = 2.312 C = 6.998 – 3.553 = 3.445 2. Problem solving by using symbols Sometimes the symbol is not at the beginning so you have to rearrange the equation by performing an inverse operation. This is because it is easier to solve when the symbol is on the left hand side of the equals sign. 12 = 78 – Step 1 Move the symbol to the left with an inverse operation. The inverse of + is – : 12 + = 78 Step 2 Make the symbol stand alone with an inverse operation. To do this, subtract 12 from both sides: = 78 - 12 Now try the following: 23 56