Title Current electricity & Organic chemistry- Daily-19 (Set-A)-With Solve.pdf ✅

4 24. †Kv‡bv d ̈v±wi‡Z 0.2  †ivahy3 GKwU ˆe`y ̈wZK Zvi 200 volt wWwm Kv‡i‡›U 10 kW ÿgZv mieivn Ki‡j, Gi Kvh©ÿgZv KZ? 65% 75% 85% 95% DËi: 95% e ̈vL ̈v: ÿgZv, P = 10 kW, mieivnK...Z wefe, V = 200 V hš¿vwUi Zzj ̈‡iva R n‡j, R = V 2 P = 2002 10  103 = 4   mieivnK...Z cÖevngvÎv, I = V R = 200 4 = 50 A Zv‡ii †iv‡ai Rb ̈ e ̈wqZ ÿgZv = 502  0.2 = 500 W   = Kvh©Ki ÿgZv †gvU ÿgZv  100% = 10  103 – 500 10  103  100%  95% 25. 6 V kw3i Drm Øviv GKwU evwZi ga ̈ w`‡q 0.3 A we`y ̈r 2 wgwbU a‡i cÖevwnZ Kiv n‡jv, GB 2 wgwb‡U evwZwU Øviv kw3 e ̈‡qi cwigvY KZ? 12 J 1.8 J 216 J 220 J DËi: 216 J e ̈vL ̈v: e ̈wqZ kw3, W = Pt = VIt = 6  0.3  2  60 = 216 J 26. GKwU ûBU‡÷vb wea‡Ri PviwU evû‡Z h_vμ‡g 6, 18, 10 Ges 20 In‡gi †iva hy3 Av‡Q| PZz_© evû‡Z KZ gv‡bi †iva †kÖwY mgev‡q hy3 Ki‡j weaRwU mvg ̈ve ̄’v cÖvß n‡e? 20  30  10  40  DËi: 10  e ̈vL ̈v: mvg ̈ve ̄’vq, P Q = R S  S = QR P  S = 18  10 6  S = 30  wKš‘ S = 20   S > S, myZivs mvg ̈ve ̄’vq ivL‡Z n‡j PZz_© evû‡Z (30 – 20) = 10  †kÖwY‡Z hy3 Ki‡Z n‡e| 27. GK wK‡jvIqvU-AvIqvi (kWh) mgvb KZ Ryj? 550 J 746 J 3.6 × 106 J 9.8 J DËi: 3.6 × 106 J e ̈vL ̈v: 1 kWh = 1000 W  3600 s = 3.6  106 J 28. GKwU †iv‡ai Mv‡q 1g, 2q I 3q e ̈v‡Û Kgjv, mv`v I iƒcvjx is Av‡Q| 4_© e ̈v‡Û †mvbvjx is _vK‡j †iv‡ai gvb I Ujv‡iÝ KZ n‡e? 0.39 , 20% 39 , 10% 3.9 , 10% 0.39 , 5% DËi: 0.39 , 5% e ̈vL ̈v: 0.39 , 5% PZz_© e ̈vÛ †mvbvjx nIqvq Ujv‡iÝ 5%| 29. wb‡¤œi eZ©bx‡Z Zwor cÖevn = ? 10 5 V 2 V 20 0.1 A 0.2 A 0.3 A 0.4 A DËi: 0.1 A e ̈vL ̈v: 10 5 V 2 V 20 i wKk©‡di m~Îvbyhvqx, 10i – 5 + 20i + 2 = 0  i = 0.1 A 30. A, B cÖv‡šÍ wefe cv_©K ̈ KZ? 4  4  4  4  A 10 V B 3.33 V 2 V 4 V 6 V DËi: 2 V e ̈vL ̈v: 4  4  4  4  A 10 V B RAB = 4 2 = 2   VAB = 2 2 + 4 + 4  10 = 2 V