Title 1. P2C1. Phy. For FRB-2024_With Solve_Ridoy 25.03.25.pdf ✅

ZvcMwZwe` ̈v  Final Revision Batch 1 cÖ_g Aa ̈vq ZvcMwZwe` ̈v Thermodynamics Topicwise CQ Trend Analysis UwcK 2016 2017 2018 2019 2021 2022 2023 2024 †gvU ZvcgvÎv cwigv‡ci bxwZ (_v‡g©vwgUvi) Ñ Ñ Ñ Ñ 1 Ñ Ñ Ñ 1 ZvcMwZwe` ̈vi 1g m~Î Ñ 2 Ñ 1 3 2 3 Ñ 11 iƒ×Zvcxq cÖwμqvi m~Î 1 Ñ Ñ 2 3 6 1 2 15 m‡gvò I iæ×Zvcxq cÖwμqvq K...ZKvR Ñ Ñ Ñ 1 2 6 6 6 21 Zvc, Af ̈šÍixY kw3 I KvR Ñ 2 Ñ 4 Ñ 1 1 6 14 Kv‡b©v Pμ I Kv‡b©v BwÄb ev cÖZ ̈vMvgx BwÄb 2 3 2 1 9 2 5 2 26 Zvcxq BwÄb: †iwd«Rv‡iU Ñ Ñ Ñ Ñ 1 Ñ Ñ Ñ 1 Bwćbi `ÿZv 3 5 1 2 9 2 1 6 29 GbUawc I wek„•Ljv Ñ 2 1 4 3 4 1 2 17 * we.`a.: 2020 mv‡j GBPGmwm cixÿv AbywôZ nqwb| weMZ mv‡j †ev‡W© Avmv m„Rbkxj cÖkœ 1| wb‡Pi †jLwP‡Î 2 †gvj †Kv‡bv M ̈v‡mi ZvcgvÎvi mv‡_ Pv‡ci cwieZ©b †`Lv‡bv n‡jv| OA As‡k M ̈v‡mi AvqZb w ̄’i _v‡K| w ̄’i AvqZ‡b M ̈v‡mi †gvjvi Av‡cwÿK Zvc 12.5 J mol–1K –1 | [e. †ev. 24] (K) cÖZ ̈veZ©x cÖwμqvi msÁv `vI| (L) m‡gvò cÖwμqv axi cÖwμqv †Kb? e ̈vL ̈v Ki| (M) OA †iLvq Af ̈šÍixY kw3i cwieZ©b wbY©q Ki| mgvavb: †`Iqv Av‡Q, †gvj msL ̈v, n = 2 mol w ̄’i AvqZ‡b M ̈v‡mi †gvjvi Av‡cwÿK Zvc, CV = 12.5 Jmol–1K –1 †jLwPÎ n‡Z, OA As‡k, ZvcgvÎvi cwieZ©b, T = (300 – 0) K = 300 K Avgiv Rvwb, Af ̈šÍixY kw3i cwieZ©b, U = nCVT = 2  12.5  300 = 7500 J (Ans.) (N) †jLwP‡Îi AB I BC As‡ki K„ZKvR MvwYwZK we‡kølY mnKv‡i Zzjbv Ki| mgvavb: AB AskwU mgPvc cÖwμqv wb‡`©k K‡i  WAB = P(VB – VA) = P     nRTB PB – nRTA PA [ PV = nRT] = nR(TB – TA) [ PB = PA = P] = 2  8.314  (600 – 300) = 4988.4 J BC AskwU m‡gvò cÖwμqv wb‡`©k K‡i|  WBC = nRT ln     PB PC = 2  8.314  600 ln     2  105 1  105 = 6915.4 J  WBC – WAB = 6915.4 – 4988.4 = 1927 J  AB As‡ki Zzjbvq BC As‡k K...ZKvR 1927 J †ewk| (Ans.) 2| Kv‡b©v Bwćbi cÖwZ ͇̄i es‡KvPb ev cÖmvi‡Yi AbycvZ 1 : 6, G‡Z Kvh©wbe©vnK e ̄‘ wnmv‡e 3 †gvj wØÑcigvYyK M ̈vm e ̈envi Kiv n‡jv| ( = 1.4) [P. †ev. 24] (P1, V1 ) T = 227C A D T2 B (P1, V1 ) B (P4, V4 ) C (P4, V4 ) V P (K) cvwbi •Îa we›`y Kv‡K e‡j? (L) cÖZ ̈veZx© cÖwμqvq G›Uawc w ̄’i _v‡K †Kb? e ̈vL ̈v Ki| (M) Kvh©wbe©vnK e ̄‘‡K A n‡Z B we›`y‡Z Avb‡Z K...ZKvR wbY©q Ki| [P. †ev. 24; Abyiƒc w`. †ev. 24] (N) cÖ`Ë Bwćbi Kg©`ÿZv 55% A‡cÿv †ewk nIqv m¤¢e wK? MvwYwZKfv‡e we‡kølY Ki| [P. †ev. 24; Abyiƒc w`. †ev. 24]
2  HSC Physics 2nd Paper Chapter-1 3| wc÷bhy3 GKB ai‡bi `ywU wfbœ wmwjÛv‡i 10C ZvcgvÎvi 8 gm K‡i nvB‡Wav‡Rb M ̈vm Av‡Q| cÖ_g wmwjÛv‡i AvqZb w ̄’i †i‡L 410 J Zvc cÖ`vb Kivq M ̈v‡mi ZvcgvÎv 15C G DbœxZ n‡jv| Acic‡ÿ wØZxq wmwjÛv‡i Pvc w ̄’i †i‡L 410 J Zvc cÖ`vb Kiv n‡jv| [†gvjvi M ̈vm aaæeK R = 8.31 J/mol/K] [Kz. †ev. 24] (K) Zvc MwZwe` ̈vi k~b ̈Zg m~ÎwU wee„Z Ki| (L) iæ× Zvcxq cÖmvi‡Y wm‡÷g kxZj nq †Kb? e ̈vL ̈v Ki| (M) w ̄’i AvqZ‡b †gvjvi Zvc aviYÿgZv (Cu) wbY©q Ki| mgvavb: †`Iqv Av‡Q, nvB‡Wav‡Rb M ̈v‡mi fi, m = 8 g  †gvj msL ̈v, n = m M = 8 2 = 4 mol cÖv_wgK ZvcgvÎv, T1 = 10C = 283 K P‚ovšÍ ZvcgvÎv, T2 = 15C = 288 K  ZvcgvÎvi cwieZ©b, T = (288 – 283) K = 5 K M„nxZ Zvc, Q = 410 J Avgiv Rvwb, w ̄’i AvqZ‡b †gvjvi ZvcaviY ÿgZv, CV = Q nT = 410 4  5 = 20.5 Jmol–1K –1 (Ans.) (N) wØZxq wmwjÛv‡i M ̈v‡mi ZvcgvÎv 15C G DbœxZ n‡e wK-bv? MvwYwZK we‡kølYmn hvPvB Ki| mgvavb: †`Iqv Av‡Q, †gvjvi M ̈vm aaæeK, R = 8.31 J mol–1K –1 wØZxq wmwjÛv‡ii †ÿ‡Î, cÖv_wgK ZvcgvÎv, Ti = 10C M„nxZ Zvc, Q = 410 J ÔMÕ n‡Z cvB, †gvj msL ̈v, n = 4 mol w ̄’i AvqZ‡b †gvjvi ZvcaviY ÿgZv, CV = 20.5 J mol–1K –1 P‚ovšÍ ZvcgvÎv, Tf = ? Avgiv Rvwb, CP – CV = R  CP = CV + R  Q nT = CV + R  T = Q n(CV + R)  Tf – 10 = 410 4  (20.5 + 8.314) = 13.56C myZivs, wØZxq wmwjÛv‡i M ̈v‡mi ZvcgvÎv 15C G DbœxZ n‡e bv| (Ans.) 4| cixÿvMv‡i Av`k© ZvcgvÎv I Pv‡c GKwU wmwjÛv‡i GK †gvj Kve©b WvBA·vBW M ̈vm ivLv Av‡Q| cixÿv m¤ú‡bœi GK ch©v‡q wkÿK wkÿv_©x‡`i ej‡jb, iƒ×Zvcxq cÖwμqvq M ̈v‡mi AvqZb 2 ̧Y Ki‡Z m‡gv cÖwμqvq Zzjbvq Kg KvR Ki‡Z n‡e| [Xv. †ev. 24] (K) Af ̈šÍixY kw3 Kx? (L) iæ×Zvcxq cÖmvi‡Y wm‡÷‡g DòZv n«vm cvqÑ e ̈vL ̈v K‡iv| (M) iƒ×Zvcxq cÖwμqvq M ̈vmwUi P‚ovšÍ Pvc wbY©q K‡iv| mgvavb: Avgiv Rvwb, iæ×Zvcxq cÖwμqvq, P1V  1 = P2V  2  1  V  = P2  (2V)  P2 =     1 2  =     1 2 1.33 = 0.3978 atm  M ̈vmwUi P~ovšÍ Pvc 0.3978 atm| (Ans.) †`Iqv Av‡Q, cÖviw¤¢K Pvc, P1 = 1 atm CO2 Gi  = 1.33 cÖviw¤¢K AvqZb, V1 = V P‚ovšÍ AvqZb, V2 = 2 V (N) wkÿ‡Ki e3e ̈ h_v_© wQj wKbvÑ MvwYwZKfv‡e hvPvB Ki| mgvavb: iæ×Zvcxq cÖmvi‡Y, T1V  – 1 1 = T2V  – 1 2  273  V  – 1 = T2  (2V) – 1  T2 = 273      1 2 1.33 – 1 = 217.18 K †`Iqv Av‡Q, cÖviw¤¢K ZvcgvÎv, T1 = 273 K †gvj msL ̈v, n = 1 mol  iæ×Zvcxq cÖmvi‡Y K...ZKvR, W1 = nR  – 1 (T1 – T2) = 1  8.314 1.33 – 1 (273 – 217.18) = 1406.32 J m‡gvò cÖmvi‡Y K...ZKvR, W2 = nRT ln V2 V1 = 1  8.314  273 ln2 = 1573.25 J  W2 > W1 myZivs, wkÿ‡Ki e3e ̈ h_v_© wQj| (Ans.) 5| 2 mole M ̈vm 30C cvÎ Dc‡ii wP‡Î M ̈v‡mi Pvc cÖ_‡g ax‡i wØ ̧Y Ges c‡i `aæZ wZb ̧Y Ki‡j ZvcgvÎv †cj 197.83C| Rvwnb `vwe Kij cv‡Îi M ̈vm wnwjqvg| [w`. †ev. 24]