Title PSAD 2 - Cables and Trusses.pdf ✅

This also gives Bv = 67.045 lb and H = 40.227 lb. Consider point D: +↑ ∑FV = 0: CDv + 50 = BDv CDv + 50 = 67.045 CDv = 17.045 lb ∑FH = 0: CDH = BDH = 40.227 lb Consider point C: +↑ ∑FV = 0: ACv + CDv = 80 ACv + 17.045 = 80 ACv = 62.955 lb + ←∑FH = 0: ACH = CDH = 40.227 lb For the tension on cable AC: AC = √ACv 2 + ACh 2 AC = √62.9552 + 40.2272 AC = 74. 710 lb For the tension on cable CD: CD = √CDv 2 + CDh 2 CD = √17.0452 + 40.2272 CD = 43. 689 lb