Title 6. P1C6. Phy. For FRB-2024_With Solve_Ridoy- 12.01.25 - OK.pdf ✅

2  HSC Physics 1st Paper Chapter-6 (N) MÖnwUi N~Y©‡bi Rb ̈ D3 ̄’v‡b e ̄‘wUi Rb ̈ D3 ̄’v‡b e ̄‘wUi IR‡bi Kx iƒc cwieZ©b n‡e? MvwYwZKfv‡e we‡kølY Ki| mgvavb: MÖnwUi N~Y©bMwZ bv _vK‡j MÖ‡ni c„‡ô e ̄‘i IRb, W1 = mg1 = 100  3.908 = 390.8 N 45  MÖ‡ni N~Y©‡bi d‡j e ̄‘i IRb, W2 = mg2 = m(g –  2Rcos2 ) = mg – m 2Rcos2  = 390.8 – m     2π T 2 Rcos2  =390.8–       100      2π 6  3600 2  3.2  106  cos2 (90 – 45) = 390.8 – 13.54 = 377.26 N  W = W1 – W2 = 390.8 – 377.26 = 13.54 N myZivs MÖ‡ni N~Y©‡bi Rb ̈ e ̄‘i IRb 13.54 N n«vm cv‡e| (Ans.) 3| GKRb c`v_©we` c„w_exi N~Y©‡bi mv‡_ AwfKl©R Z¡iY ÔgÕ Gi m¤úK© ̄’vc‡bi Rb ̈ 70 kg f‡ii GKwU e ͇̄K f‚- c„‡ô 70 DËi Aÿvs‡k ivL‡jb| c„w_ex wbR A‡ÿ 24 NÈvq GKevi AveZ©b K‡i| (c„w_exi fi M = 6  1024 kg, e ̈vmva© 24 R = 6.4  106m, gnKlx©q aaæeK G = 6.676  1011 Nm2 kg–2 , AwfKl©R Z¡iY g = 9.77 ms–2 ) [e. †ev. 24] (K) gnvKl©xq wefe Kv‡K e‡j? (L) P›`a I c„w_exi g‡a ̈ †Kvb †ÿ‡Î gyw3‡eM †ewk? e ̈vL ̈v Ki| (M) c„w_ex N~Y©‡bi Rb ̈ 70 DËi Aÿvs‡k e ̄‘wUi •iwLK †eM KZ? mgvavb: O  = 70 A B OB = R AB = r 70 DËi Aÿvs‡k •iwLK †eM, v = r = . AB = 2π T  OBcos = 2π 24  3600  6.4  106  cos70 = 159.18 ms–1 (Ans.) (N) AveZ©bRwbZ Kvi‡Y DÏxc‡K DwjøwLZ ̄’v‡b e ̄‘wUi IRb evo‡e bv Kg‡e MvwYwZKfv‡e we‡kølY Ki| mgvavb: N~Y©‡bi d‡j e ̄‘wUi IRb, W2 = mg2 = m(g –  2Rcos2 ) = mg – m 2Rcos2  = mg – m     2π T 2 Rcos2  = 683.9 –     70      2π 86400 2  6.4  106  cos2 70 = 683.623 N N~Y©b bv _vK‡j IRb, W1 = mg = 683.9 N  W = W1 – W2 = 683.9 – 683.623 = 0.277 N myZivs AveZ©bRwbZ Kvi‡Y e ̄‘wUi IRb K‡g hv‡e| (Ans.) 4| `ywU MÖ‡ni gyw3 †eM h_vμ‡g 11.2 kms–1 Ges 5.2 kms–1 , cÖ_g MÖ‡ni fi wØZxq MÖ‡ni f‡ii 8 ̧Y| Dfq MÖ‡bi c„ô n‡Z 4 ms–1 †e‡Mi `ywU e ̄‘‡K Lvov Dc‡ii w`‡K wb‡ÿc Kiv nj| [wm. †ev. 24] (K) gnvKl© ej Kv‡K e‡j? (L) i‡K‡Ui †eM gyw3‡eM bq †Kb? (M) DÏxc‡K DwjøwLZ `ywU MÖ‡ni e ̈vmv‡a©i AbycvZ wbY©q Ki| mgvavb: †`Iqv Av‡Q, M1 = 8 M2 ve 1 = 11.2 kms–1 = 11200 ms–1 ve 2 = 5.2 kms–1 = 5200 ms–1 Avgiv Rvwb, gyw3‡eM, ve = 2GM R  ve  M R  ve 1 ve 2 = M1 M2  R2 R1      11200 5200 2 = 8M2 M2  R2 R1  R1 R2 = 169 98  R1 : R2 = 169 : 98 myZivs MÖn؇qi e ̈vmv‡a©i AbycvZ 169 : 98 (Ans.)