Title 2. P2C2 (Electrostatics)_With Solve_Ridoy 12.12.24.pdf ✅

w ̄’i Zwor  Varsity Practice Sheet 1 MCQ weMZ mv‡j DU-G Avmv cÖkœvejx 1. cvZ-`~iZ¡ d Ges aviKZ¡ C, Ggb GKwU mgvšÍivj cvZ-avi‡Ki cvZ `ywUi gvSLv‡b d 2 cyiæZ¡wewkó GKwU avZe cvZ ̄’vcb Kiv n‡jv| bZzb aviKZ¡ KZ n‡e? [DU 23-24] C d C 2 4Cd 2C DËi: 2C e ̈vL ̈v: C = 0A d – d 2 = 0A d 2 = 2C 2. q gv‡bi cuvPwU abvZ¥K PvR© r e ̈vmv‡a©i GKwU e„‡Ëi cwiwa eivei cÖwZmgfv‡e mvRv‡bv n‡jv| e„‡Ëi †K‡›`a •e`y ̈wZK †ÿ‡Îi gvb KZ? [DU 22-23] q 4 40r 2 q 5 40r 2 0 5q 40r 2 DËi: 0 e ̈vL ̈v: cÖwZmgZvi Kvi‡Y wbU Zwor cÖvej ̈ k~b ̈ n‡e| 3. a •`N© ̈ wewkó `ywU eM©vKvi cvZ w`‡q MwVZ aviK hvi cvZ `ywUi ga ̈eZ©x `~iZ¡ d Ges d << a| avi‡Ki mg ̄Í •iwLK gvÎv wZb ̧Y Kiv n‡j aviKZ¡ KZ ̧Y cwieZ©b n‡e? [DU 22-23] 1 3 1 3 9 DËi: 3 e ̈vL ̈v: cÖv_wgK aviKZ¡, C = 0A d •iwLK gvÎv 3 ̧Y Ki‡j, A = 9A, d = 3d  bZzb aviKZ¡, C = 0A d = 0  9A 3d = 3  0A d = 3C 4. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi ci e ̈vUvwi Ly‡j †djv n‡jv| G Ae ̄’vq aviKwU‡Z mwÂZ kw3i cwigvY U0| cvZ `ywUi `~iZ¡ hw` wØ ̧Y Kiv nq, Z‡e avi‡K mwÂZ kw3 KZ ̧Y n‡e? [DU 20-21; JUST 14-15] U0 2 U0 4 2U0 4U0 DËi: 2U0 e ̈vL ̈v: Avgiv Rvwb, U = Q 2 2C I C = 0A d  U  1 C  d [G‡ÿ‡Î avi‡K mwÂZ Avavb aaæeK _v‡K]  U1 U2 = d1 d2 = d1 2d1  U2 = 2U0 5. hw` Zwor †ÿ‡Îi cÖvej ̈ +x Aÿ eivei wμqv K‡i Ges Gi gvb E = cx2 nq, †hLv‡b c = aaæeK, Z‡e Zwor wefe V = ? [DU 18-19] –2cx 2cx – cx3 3 cx3 3 DËi: – cx3 3 e ̈vL ̈v: V = – Edx = –  cx2  V = – cx3 3 6. `ywU mgvb Pv‡R©i ga ̈eZ©x `~iZ¡ A‡a©K Kiv n‡j Ges PvR© `ywUi gvb Kwg‡q A‡a©K Kiv n‡j e‡ji gvbÑ [DU 17-18] A‡a©K n‡e wØ ̧Y n‡e AcwiewZ©Z _vK‡e Pvi ̧Y n‡e DËi: AcwiewZ©Z _vK‡e e ̈vL ̈v: F1 F2 = q  q d 2 1 2 q  1 2 q 1 4 d 2  F1 F2 = 1  F1 = F2 (AcwiewZ©Z)
2  Physics 2nd Paper Chapter-2 7. k~b ̈ gva ̈‡g `yBwU B‡jKUa‡bi ga ̈Kvi Kzj¤^ ej FE Ges gnvKl© ej FG Gi AbycvZ n‡eÑ [DU 16-17] 4.2  1062 4.2  1052 4.2  1042 9  109 N DËi: 4.2  1042 e ̈vL ̈v: FE FG = k  q 2 d 2 G  m 2 d 2 = 9  109  (1.6  10–19) 2 6.673  10–11  (9.1  10–31) 2  FE FG = 4.2  1042 8. GKwU we›`y PvR© n‡Z 2 m `~i‡Z¡ Zwor‡ÿ‡Îi cÖve‡j ̈i gvb E n‡j, 1 m `~i‡Z¡ Zwor‡ÿ‡Îi cÖve‡j ̈i gvb KZ? [DU 15-16] E 2E 4E E 2 DËi: 4E e ̈vL ̈v: E  1 d 2 E1 E2 = d2 2 d1 2  E E2 = 1 2 2 2  E2 = 4E 9. 5 F Gi 5 wU aviK wmwiR ms‡hv‡M hy3 Kiv n‡jv| H aviK ̧‡jvi mgZzj ̈ aviKZ¡ n‡”QÑ [DU 14-15; JU 14-15; JnU 09-10] 5 F 4 F 1 F 10 F DËi: 1 F e ̈vL ̈v: Ceq = C n = 5 F 5 = 1 F 10. mgvšÍivj `ywU avZe cv‡Zi ga ̈Kvi `~iZ¡ d Ges wefe cv_©K ̈ V| hw` Q Avav‡bi GKwU we›`y PvR© `ywUi wVK ga ̈eZ©x we›`y‡Z ivLv nq Z‡e PvR©wUi Dci wμqvkxj w ̄’i Zwor e‡ji gvb KZ? [DU 14-15] 2VQ d VQ d VQ 2d dQ V DËi: VQ d e ̈vL ̈v: avi‡Ki Rb ̈, E = V d  F = EQ = VQ d 11. GKwU Zwor w؇cv‡ji Rb ̈ Zwor‡ÿÎ, `~iZ¡ r Gi mv‡_ wKfv‡e cwiewZ©Z nq? [DU 14-15] r –1 r –2 r r –3 DËi: r –3 e ̈vL ̈v: E = 1 40  P 1 + 3 cos2  r 3  E  1 r 3  E  r –3 12. GKwU mgvšÍivj cvZ aviK‡K PvwR©Z Kivi d‡j GwUi cvZ `yBwUi g‡a ̈ wefe cv_©K ̈ nq V| aviKwUi mwÂZ kw3 wØ ̧Y Kivi Rb ̈ wefe cv_©K ̈ KZ n‡e? [DU 13-14, 06-07] 1 4 V 1 2 V 2V 2V DËi: 2V e ̈vL ̈v: U = 1 2 CV2 U  V 2  U1 U2 = V1 2 V2 2  1 2 = V 2 V2 2  V2 2 = 2V2  V2 = 2 V weMZ mv‡j GST-G Avmv cÖkœvejx 1. 4 F 4 F 2 F 3 F A B 2 F Dc‡ii eZ©bxwUi Zzj ̈ aviKZ¡ KZ F? [GST 23-24] 1 2 3 2.2 DËi: 2
w ̄’i Zwor  Varsity Practice Sheet 3 e ̈vL ̈v: 2F 2F 2F 2F 2F 3F 4F 4F 3F 6F 3F  Ceq = 3  6 3 + 6 = 2 F 2. 40  10–20C PvR©hy3 GKwU e ̄‘ 4.9  104 Vm–1 gv‡bi mylg •e`y ̈wZK †ÿ‡Î SzjšÍ Ae ̄’vq Av‡Q| e ̄‘wUi fi KZ kg? [GST 22-23] 20  10–16 30  10–16 40  10–16 60  10–16 DËi: 20  10–16 e ̈vL ̈v: FG = Fe  mg = Eq  m = 4.9  104  40  10–20 9.8 = 20  10–16 kg 3. Dc‡ii wP‡Îi +q we›`y PvR© ̧‡jvi Rb ̈ P we›`y‡Z Zwor †ÿ‡Îi cÖvej ̈ I wefe h_vμ‡gÑ [GST 22-23] +q L L r r L P r +q +q 1 40r 2 3q r 2 , 0 1 40 q r 2, 0 0, 1 40 3q r 1 40 q r , 0 DËi: 0, 1 40 3q r e ̈vL ̈v:  E r 120 120 120 r r  E  E me ̧‡jv mgvb ej 120 †Kv‡Y wμqv K‡i|  jwä cÖvej ̈ k~b ̈ n‡e| wefe, VP = 1 40     q r + q r + q r = 1 40 3q r 4. 2 F aviK‡Z¡i GKwU eZ©bx‡Z 2000 V wefe cv_©K ̈ cÖ‡qv‡Mi ci avi‡K mwÂZ kw3i cwigvY KZ J? [GST 22-23] 8 6 4 2 DËi: 4 e ̈vL ̈v: avi‡K mwÂZ kw3, U = 1 2 CV2 = 1 2  2  10–6  20002 = 4 J 5. †Kvb Zj Øviv Ave×K...Z 2 GKK Pv‡R©i Rb ̈ k~b ̈ ̄’v‡b •e`y ̈wZK d¬v·Ñ [GST 20-21] 20 0 1 40 2 0 DËi: 2 0 e ̈vL ̈v: †Kv‡bv Z‡j Ave× Pv‡R©i Rb ̈ •e`y ̈wZK d¬v·,  = q 0   = 2 0 weMZ mv‡j Agri-G Avmv cÖkœvejx 1. AvwnZ e ̄‘i †Kv_vq me‡P‡q †ewk Avavb _v‡K? [Agri. Guccho 19-20; KU 19-20; IU 15-16] †K‡›`a AeZj Z‡j mgZj Z‡j DËj Z‡j DËi: DËj Z‡j weMZ mv‡j JU-G Avmv cÖkœvejx 1. r `~i‡Z¡ ivLv mgvb gvÎvi `ywU PvR© G‡K Ac‡ii Dci F ej cÖ‡qvM K‡i| hw` Pv‡R©i gvb A‡a©K nq Ges Zv‡`i g‡a ̈ `~iZ¡ wØ ̧Y Kiv nq, Zvn‡j cÖwZwU Pv‡R©i Dci wμqvkxj bZzb ej n‡eÑ [JU 22-23] F 8 F 4 4F F 16 DËi: F 16
4  Physics 2nd Paper Chapter-2 e ̈vL ̈v: F1 F2 = q1q2 d 2 1 2 q1  1 2 q2 4d2  F1 F2 = 16  F2 = F1 16 2. 500 †fvë Gi mgZzj ̈ †KvbwU? [JU 22-23] Pv‡R©i 4 Kzj¤^ cÖwZ 2000 Ryj kw3 cÖwZ 2 Kzj¤^ Pv‡R© 1000 Ryj kw3 cÖwZ 1 Kzj¤^ Pv‡R© 500 Ryj kw3 Dc‡ii me ̧‡jv DËi: Dc‡ii me ̧‡jv e ̈vL ̈v: W = qV  V = W q  V = 2000 4 = 500 V  V = 1000 2 = 500 V  V = 500 1 = 500 V  me ̧‡jv mwVK| 3. GKwU K ̈vcvwmU‡ii aviKZ¡ 6 pF| avZe †cø‡Ui g‡a ̈ GKwU Møvm (k = 5.2) WvBB‡jKwUaK ̄’vc‡bi d‡j bZzb aviKZ¡ KZ? [JU 22-23] 6 pF 15 pF 31.2 pF 331 pF DËi: 31.2 pF e ̈vL ̈v: Avgiv Rvwb, C = k  C0 = 5.2  6 pF = 31.2 pF 4. `ywU PvR© q1 Ges q2 GKwU f ̈vKzqv‡g d `~i‡Z¡ ̄’vcb Kiv n‡q‡Q Ges Zv‡`i g‡a ̈ wμqvkxj ej n‡jv F| hw` Zv‡`i Pvicv‡k WvBB‡jw±aK aaæe‡Ki gvb 4 wewkó GKwU gva ̈g cÖeZ©b Kiv nq, Z‡e bZzb e‡ji gvb n‡eÑ [JU 22-23] F F 2 F 4 4F DËi: F 4 e ̈vL ̈v: F = 1 40k q1q2 d 2  F  1 k  F1 F2 = k2 k1 = 4 1  F2 = 1 4 F 5. GKwU cwjw_b iW‡K Kvco w`‡q Nl‡j GwU FYvZ¥K PvR© jvf K‡i| wb¤œwjwLZ wee„wZ ̧‡jvi g‡a ̈ †KvbwU m‡e©vËg? [JU 22-23] Kvco †_‡K B‡jKUab cwjw_b i‡W ̄’vbvšÍwiZ nq cwjw_b iW †_‡K B‡jKUab Kvc‡o ̄’vbvšÍwiZ nq cwjw_b iW †_‡K †cÖvUb Kvc‡o ̄’vbvšÍwiZ nq †cÖvUb Kvco †_‡K cwjw_‡bi i‡W ̄’vbvšÍwiZ nq DËi: Kvco †_‡K B‡jKUab cwjw_b i‡W ̄’vbvšÍwiZ nq e ̈vL ̈v: Kvco †_‡K B‡jKUab cwjw_b i‡W ̄’vbvšÍwiZ nIqvq cwjw_b i‡W B‡jKUa‡bi cwigvY e„w× cvq| B‡jKUab FYvZ¥K PvR©wewkó nIqv‡Z cwjw_b iW FYvZ¥K PvR© jvf K‡i| 6. avi‡Ki †ÿ‡Î †KvbwU mwVK? [JU 20-21] W = 1 2 VC2 W = 1 2 CI2 W = 1 2 Q C W = 1 2 V 2C DËi: W = 1 2 V 2C e ̈vL ̈v: avi‡K mwÂZ kw3, U = 1 2 CV2 7. GKwU we›`y PvR© 1.736  10–9 C Gi Rb ̈ m„ó Zwor †ÿ‡Îi †Kvb GKwU we›`y‡Z cÖvej ̈ 40 NC–1 n‡j H we›`y‡Z Zwor wef‡ei gvb KZ? [JU 19-20] 1.5 JC–1 15 JC–1 2.5 JC–1 25 JC–1 DËi: 25 JC–1 e ̈vL ̈v: E = 1 40  q d 2  d = 9  109  1.736  10–9 40  d = 0.625 m  V = Ed = 40  0.625 = 25 V = 25 JC–1